details

property	value
status	complete
benchmark	ppblocktermbug.t2.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n145.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	63.8276 seconds
cpu usage	62.9726
user time	34.0629
system time	28.9097
max virtual memory	778688.0
max residence set size	18636.0

stage attributes

key	value
starexec-result	MAYBE

output

MAYBE DP problem for innermost termination. P = f9#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) -> f8#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) f8#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9, I10) -> f3#(I0, 0, 1, 0, I4, rnd6, I6, rnd8, I8, I9, 0) [rnd6 = rnd6 /\ rnd8 = rnd8] f3#(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) -> f7#(rnd1, I12, 1, I14, I15, I16, I17, I18, I19, I20, 0) [rnd1 = rnd1 /\ 1 + I18 <= I16] f3#(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) -> f2#(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, 0) [I27 <= I29] f7#(I33, I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f4#(I33, 1, I35, I36, I37, I38, rnd7, I40, I41, I42, I43) [rnd7 = rnd7 /\ 1 <= I33] f7#(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) -> f2#(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) [I44 <= 0] f5#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) f2#(I77, I78, I79, I80, I81, I82, I83, I84, I85, I86, I87) -> f5#(I77, I78, I79, I80, I81, I82, I83, I84, I85, -1 + I86, I87) [1 <= I86] f4#(I88, I89, I90, I91, I92, I93, I94, I95, I96, I97, I98) -> f1#(I88, 0, I90, I91, 0, I93, I99, I95, I96, I97, I98) [I99 = I99 /\ 2 <= I94] f4#(I100, I101, I102, I103, I104, I105, I106, I107, I108, I109, I110) -> f3#(I100, 0, I102, I103, I104, I105, I106, 1 + I107, I108, I109, 1) [I106 <= 1] f1#(I111, I112, I113, I114, I115, I116, I117, I118, I119, I120, I121) -> f3#(I111, I112, I113, I114, I115, I116, I117, I118, 1 + I119, I120, I121) [2 <= I117] f1#(I122, I123, I124, I125, I126, I127, I128, I129, I130, I131, I132) -> f2#(I122, I123, I124, I125, I126, I127, I128, I129, I130, I131, I132) [I128 <= 1] R = f9(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) -> f8(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) f8(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9, I10) -> f3(I0, 0, 1, 0, I4, rnd6, I6, rnd8, I8, I9, 0) [rnd6 = rnd6 /\ rnd8 = rnd8] f3(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) -> f7(rnd1, I12, 1, I14, I15, I16, I17, I18, I19, I20, 0) [rnd1 = rnd1 /\ 1 + I18 <= I16] f3(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) -> f2(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, 0) [I27 <= I29] f7(I33, I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f4(I33, 1, I35, I36, I37, I38, rnd7, I40, I41, I42, I43) [rnd7 = rnd7 /\ 1 <= I33] f7(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) -> f2(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) [I44 <= 0] f2(I55, I56, I57, I58, I59, I60, I61, I62, I63, I64, I65) -> f6(I55, I56, I57, 1, I59, I60, I61, I62, 0, I64, I65) [I64 <= 0] f5(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) f2(I77, I78, I79, I80, I81, I82, I83, I84, I85, I86, I87) -> f5(I77, I78, I79, I80, I81, I82, I83, I84, I85, -1 + I86, I87) [1 <= I86] f4(I88, I89, I90, I91, I92, I93, I94, I95, I96, I97, I98) -> f1(I88, 0, I90, I91, 0, I93, I99, I95, I96, I97, I98) [I99 = I99 /\ 2 <= I94] f4(I100, I101, I102, I103, I104, I105, I106, I107, I108, I109, I110) -> f3(I100, 0, I102, I103, I104, I105, I106, 1 + I107, I108, I109, 1) [I106 <= 1] f1(I111, I112, I113, I114, I115, I116, I117, I118, I119, I120, I121) -> f3(I111, I112, I113, I114, I115, I116, I117, I118, 1 + I119, I120, I121) [2 <= I117] f1(I122, I123, I124, I125, I126, I127, I128, I129, I130, I131, I132) -> f2(I122, I123, I124, I125, I126, I127, I128, I129, I130, I131, I132) [I128 <= 1] The dependency graph for this problem is: 0 -> 1 1 -> 2, 3 2 -> 4, 5 3 -> 7 4 -> 8, 9 5 -> 7 6 -> 7 7 -> 6 8 -> 10, 11 9 -> 2, 3 10 -> 2, 3 11 -> 7 Where: 0) f9#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) -> f8#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) 1) f8#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9, I10) -> f3#(I0, 0, 1, 0, I4, rnd6, I6, rnd8, I8, I9, 0) [rnd6 = rnd6 /\ rnd8 = rnd8] 2) f3#(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) -> f7#(rnd1, I12, 1, I14, I15, I16, I17, I18, I19, I20, 0) [rnd1 = rnd1 /\ 1 + I18 <= I16] 3) f3#(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) -> f2#(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, 0) [I27 <= I29] 4) f7#(I33, I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f4#(I33, 1, I35, I36, I37, I38, rnd7, I40, I41, I42, I43) [rnd7 = rnd7 /\ 1 <= I33] 5) f7#(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) -> f2#(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) [I44 <= 0] 6) f5#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) 7) f2#(I77, I78, I79, I80, I81, I82, I83, I84, I85, I86, I87) -> f5#(I77, I78, I79, I80, I81, I82, I83, I84, I85, -1 + I86, I87) [1 <= I86] 8) f4#(I88, I89, I90, I91, I92, I93, I94, I95, I96, I97, I98) -> f1#(I88, 0, I90, I91, 0, I93, I99, I95, I96, I97, I98) [I99 = I99 /\ 2 <= I94] 9) f4#(I100, I101, I102, I103, I104, I105, I106, I107, I108, I109, I110) -> f3#(I100, 0, I102, I103, I104, I105, I106, 1 + I107, I108, I109, 1) [I106 <= 1] 10) f1#(I111, I112, I113, I114, I115, I116, I117, I118, I119, I120, I121) -> f3#(I111, I112, I113, I114, I115, I116, I117, I118, 1 + I119, I120, I121) [2 <= I117] 11) f1#(I122, I123, I124, I125, I126, I127, I128, I129, I130, I131, I132) -> f2#(I122, I123, I124, I125, I126, I127, I128, I129, I130, I131, I132) [I128 <= 1] We have the following SCCs. { 2, 4, 8, 9, 10 } { 6, 7 } DP problem for innermost termination. P = f5#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) f2#(I77, I78, I79, I80, I81, I82, I83, I84, I85, I86, I87) -> f5#(I77, I78, I79, I80, I81, I82, I83, I84, I85, -1 + I86, I87) [1 <= I86] R = f9(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) -> f8(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) f8(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9, I10) -> f3(I0, 0, 1, 0, I4, rnd6, I6, rnd8, I8, I9, 0) [rnd6 = rnd6 /\ rnd8 = rnd8] f3(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) -> f7(rnd1, I12, 1, I14, I15, I16, I17, I18, I19, I20, 0) [rnd1 = rnd1 /\ 1 + I18 <= I16] f3(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) -> f2(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, 0) [I27 <= I29] f7(I33, I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f4(I33, 1, I35, I36, I37, I38, rnd7, I40, I41, I42, I43) [rnd7 = rnd7 /\ 1 <= I33] f7(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) -> f2(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) [I44 <= 0] f2(I55, I56, I57, I58, I59, I60, I61, I62, I63, I64, I65) -> f6(I55, I56, I57, 1, I59, I60, I61, I62, 0, I64, I65) [I64 <= 0] f5(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) f2(I77, I78, I79, I80, I81, I82, I83, I84, I85, I86, I87) -> f5(I77, I78, I79, I80, I81, I82, I83, I84, I85, -1 + I86, I87) [1 <= I86] f4(I88, I89, I90, I91, I92, I93, I94, I95, I96, I97, I98) -> f1(I88, 0, I90, I91, 0, I93, I99, I95, I96, I97, I98) [I99 = I99 /\ 2 <= I94] f4(I100, I101, I102, I103, I104, I105, I106, I107, I108, I109, I110) -> f3(I100, 0, I102, I103, I104, I105, I106, 1 + I107, I108, I109, 1) [I106 <= 1] f1(I111, I112, I113, I114, I115, I116, I117, I118, I119, I120, I121) -> f3(I111, I112, I113, I114, I115, I116, I117, I118, 1 + I119, I120, I121) [2 <= I117] f1(I122, I123, I124, I125, I126, I127, I128, I129, I130, I131, I132) -> f2(I122, I123, I124, I125, I126, I127, I128, I129, I130, I131, I132) [I128 <= 1] We use the basic value criterion with the projection function NU: NU[f2#(z1,z2,z3,z4,z5,z6,z7,z8,z9,z10,z11)] = z10 NU[f5#(z1,z2,z3,z4,z5,z6,z7,z8,z9,z10,z11)] = z10 This gives the following inequalities: ==> I75 (>! \union =) I75 1 <= I86 ==> I86 >! -1 + I86 We remove all the strictly oriented dependency pairs. DP problem for innermost termination. P = f5#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) R = f9(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) -> f8(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) f8(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9, I10) -> f3(I0, 0, 1, 0, I4, rnd6, I6, rnd8, I8, I9, 0) [rnd6 = rnd6 /\ rnd8 = rnd8] f3(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) -> f7(rnd1, I12, 1, I14, I15, I16, I17, I18, I19, I20, 0) [rnd1 = rnd1 /\ 1 + I18 <= I16] f3(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) -> f2(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, 0) [I27 <= I29] f7(I33, I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f4(I33, 1, I35, I36, I37, I38, rnd7, I40, I41, I42, I43) [rnd7 = rnd7 /\ 1 <= I33] popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to ITS