Spaces
Explore
Communities
Statistics
Reports
Cluster
Status
Help
ITS pair #487098511
details
property
value
status
complete
benchmark
byron-2.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n139.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
39.2075 seconds
cpu usage
39.6977
user time
19.8932
system time
19.8045
max virtual memory
731928.0
max residence set size
17020.0
stage attributes
key
value
starexec-result
YES
output
YES DP problem for innermost termination. P = f8#(x1, x2, x3, x4, x5, x6, x7, x8) -> f1#(x1, x2, x3, x4, x5, x6, x7, x8) f7#(I0, I1, I2, I3, I4, I5, I6, I7) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7) f6#(I8, I9, I10, I11, I12, I13, I14, I15) -> f7#(I8, rnd2, I10, I11, I12, I13, -1 + I14, rnd8) [y1 = y1 /\ rnd8 = y1 /\ rnd2 = rnd2] f5#(I16, I17, I18, I19, I20, I21, I22, I23) -> f6#(I16, I17, I18, I19, I20, I21, I22, I23) [I16 = I16] f2#(I24, I25, I26, I27, I28, I29, I30, I31) -> f5#(I24, I32, I26, rnd4, I28, I29, I30, I31) [1 <= I30 /\ I33 = I33 /\ rnd4 = I33 /\ I32 = I32] f4#(I34, I35, I36, I37, I38, I39, I40, I41) -> f2#(I34, I35, I36, I37, I38, I39, I40, I41) f2#(I42, I43, I44, I45, I46, I47, I48, I49) -> f4#(I42, I50, I44, I51, I46, rnd6, I48, -1 + I49) [1 <= I48 /\ I52 = I52 /\ I51 = I52 /\ I50 = I50 /\ 0 <= I51 /\ I51 <= 0 /\ rnd6 = rnd6 /\ 2 <= -1 + I49] f1#(I61, I62, I63, I64, I65, I66, I67, I68) -> f2#(I61, I62, I63, I64, I65, I66, I67, I68) R = f8(x1, x2, x3, x4, x5, x6, x7, x8) -> f1(x1, x2, x3, x4, x5, x6, x7, x8) f7(I0, I1, I2, I3, I4, I5, I6, I7) -> f2(I0, I1, I2, I3, I4, I5, I6, I7) f6(I8, I9, I10, I11, I12, I13, I14, I15) -> f7(I8, rnd2, I10, I11, I12, I13, -1 + I14, rnd8) [y1 = y1 /\ rnd8 = y1 /\ rnd2 = rnd2] f5(I16, I17, I18, I19, I20, I21, I22, I23) -> f6(I16, I17, I18, I19, I20, I21, I22, I23) [I16 = I16] f2(I24, I25, I26, I27, I28, I29, I30, I31) -> f5(I24, I32, I26, rnd4, I28, I29, I30, I31) [1 <= I30 /\ I33 = I33 /\ rnd4 = I33 /\ I32 = I32] f4(I34, I35, I36, I37, I38, I39, I40, I41) -> f2(I34, I35, I36, I37, I38, I39, I40, I41) f2(I42, I43, I44, I45, I46, I47, I48, I49) -> f4(I42, I50, I44, I51, I46, rnd6, I48, -1 + I49) [1 <= I48 /\ I52 = I52 /\ I51 = I52 /\ I50 = I50 /\ 0 <= I51 /\ I51 <= 0 /\ rnd6 = rnd6 /\ 2 <= -1 + I49] f2(I53, I54, I55, I56, I57, I58, I59, I60) -> f3(I53, I54, I57, I56, I57, I58, I59, I60) [I59 <= 0] f1(I61, I62, I63, I64, I65, I66, I67, I68) -> f2(I61, I62, I63, I64, I65, I66, I67, I68) The dependency graph for this problem is: 0 -> 7 1 -> 4, 6 2 -> 1 3 -> 2 4 -> 3 5 -> 4, 6 6 -> 5 7 -> 4, 6 Where: 0) f8#(x1, x2, x3, x4, x5, x6, x7, x8) -> f1#(x1, x2, x3, x4, x5, x6, x7, x8) 1) f7#(I0, I1, I2, I3, I4, I5, I6, I7) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7) 2) f6#(I8, I9, I10, I11, I12, I13, I14, I15) -> f7#(I8, rnd2, I10, I11, I12, I13, -1 + I14, rnd8) [y1 = y1 /\ rnd8 = y1 /\ rnd2 = rnd2] 3) f5#(I16, I17, I18, I19, I20, I21, I22, I23) -> f6#(I16, I17, I18, I19, I20, I21, I22, I23) [I16 = I16] 4) f2#(I24, I25, I26, I27, I28, I29, I30, I31) -> f5#(I24, I32, I26, rnd4, I28, I29, I30, I31) [1 <= I30 /\ I33 = I33 /\ rnd4 = I33 /\ I32 = I32] 5) f4#(I34, I35, I36, I37, I38, I39, I40, I41) -> f2#(I34, I35, I36, I37, I38, I39, I40, I41) 6) f2#(I42, I43, I44, I45, I46, I47, I48, I49) -> f4#(I42, I50, I44, I51, I46, rnd6, I48, -1 + I49) [1 <= I48 /\ I52 = I52 /\ I51 = I52 /\ I50 = I50 /\ 0 <= I51 /\ I51 <= 0 /\ rnd6 = rnd6 /\ 2 <= -1 + I49] 7) f1#(I61, I62, I63, I64, I65, I66, I67, I68) -> f2#(I61, I62, I63, I64, I65, I66, I67, I68) We have the following SCCs. { 1, 2, 3, 4, 5, 6 } DP problem for innermost termination. P = f7#(I0, I1, I2, I3, I4, I5, I6, I7) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7) f6#(I8, I9, I10, I11, I12, I13, I14, I15) -> f7#(I8, rnd2, I10, I11, I12, I13, -1 + I14, rnd8) [y1 = y1 /\ rnd8 = y1 /\ rnd2 = rnd2] f5#(I16, I17, I18, I19, I20, I21, I22, I23) -> f6#(I16, I17, I18, I19, I20, I21, I22, I23) [I16 = I16] f2#(I24, I25, I26, I27, I28, I29, I30, I31) -> f5#(I24, I32, I26, rnd4, I28, I29, I30, I31) [1 <= I30 /\ I33 = I33 /\ rnd4 = I33 /\ I32 = I32] f4#(I34, I35, I36, I37, I38, I39, I40, I41) -> f2#(I34, I35, I36, I37, I38, I39, I40, I41) f2#(I42, I43, I44, I45, I46, I47, I48, I49) -> f4#(I42, I50, I44, I51, I46, rnd6, I48, -1 + I49) [1 <= I48 /\ I52 = I52 /\ I51 = I52 /\ I50 = I50 /\ 0 <= I51 /\ I51 <= 0 /\ rnd6 = rnd6 /\ 2 <= -1 + I49] R = f8(x1, x2, x3, x4, x5, x6, x7, x8) -> f1(x1, x2, x3, x4, x5, x6, x7, x8) f7(I0, I1, I2, I3, I4, I5, I6, I7) -> f2(I0, I1, I2, I3, I4, I5, I6, I7) f6(I8, I9, I10, I11, I12, I13, I14, I15) -> f7(I8, rnd2, I10, I11, I12, I13, -1 + I14, rnd8) [y1 = y1 /\ rnd8 = y1 /\ rnd2 = rnd2] f5(I16, I17, I18, I19, I20, I21, I22, I23) -> f6(I16, I17, I18, I19, I20, I21, I22, I23) [I16 = I16] f2(I24, I25, I26, I27, I28, I29, I30, I31) -> f5(I24, I32, I26, rnd4, I28, I29, I30, I31) [1 <= I30 /\ I33 = I33 /\ rnd4 = I33 /\ I32 = I32] f4(I34, I35, I36, I37, I38, I39, I40, I41) -> f2(I34, I35, I36, I37, I38, I39, I40, I41) f2(I42, I43, I44, I45, I46, I47, I48, I49) -> f4(I42, I50, I44, I51, I46, rnd6, I48, -1 + I49) [1 <= I48 /\ I52 = I52 /\ I51 = I52 /\ I50 = I50 /\ 0 <= I51 /\ I51 <= 0 /\ rnd6 = rnd6 /\ 2 <= -1 + I49] f2(I53, I54, I55, I56, I57, I58, I59, I60) -> f3(I53, I54, I57, I56, I57, I58, I59, I60) [I59 <= 0] f1(I61, I62, I63, I64, I65, I66, I67, I68) -> f2(I61, I62, I63, I64, I65, I66, I67, I68) We use the extended value criterion with the projection function NU: NU[f4#(x0,x1,x2,x3,x4,x5,x6,x7)] = x6 - 1 NU[f5#(x0,x1,x2,x3,x4,x5,x6,x7)] = x6 - 2 NU[f6#(x0,x1,x2,x3,x4,x5,x6,x7)] = x6 - 2 NU[f2#(x0,x1,x2,x3,x4,x5,x6,x7)] = x6 - 1 NU[f7#(x0,x1,x2,x3,x4,x5,x6,x7)] = x6 - 1 This gives the following inequalities: ==> I6 - 1 >= I6 - 1 y1 = y1 /\ rnd8 = y1 /\ rnd2 = rnd2 ==> I14 - 2 >= (-1 + I14) - 1 I16 = I16 ==> I22 - 2 >= I22 - 2 1 <= I30 /\ I33 = I33 /\ rnd4 = I33 /\ I32 = I32 ==> I30 - 1 > I30 - 2 with I30 - 1 >= 0 ==> I40 - 1 >= I40 - 1 1 <= I48 /\ I52 = I52 /\ I51 = I52 /\ I50 = I50 /\ 0 <= I51 /\ I51 <= 0 /\ rnd6 = rnd6 /\ 2 <= -1 + I49 ==> I48 - 1 >= I48 - 1 We remove all the strictly oriented dependency pairs. DP problem for innermost termination. P = f7#(I0, I1, I2, I3, I4, I5, I6, I7) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7) f6#(I8, I9, I10, I11, I12, I13, I14, I15) -> f7#(I8, rnd2, I10, I11, I12, I13, -1 + I14, rnd8) [y1 = y1 /\ rnd8 = y1 /\ rnd2 = rnd2] f5#(I16, I17, I18, I19, I20, I21, I22, I23) -> f6#(I16, I17, I18, I19, I20, I21, I22, I23) [I16 = I16] f4#(I34, I35, I36, I37, I38, I39, I40, I41) -> f2#(I34, I35, I36, I37, I38, I39, I40, I41) f2#(I42, I43, I44, I45, I46, I47, I48, I49) -> f4#(I42, I50, I44, I51, I46, rnd6, I48, -1 + I49) [1 <= I48 /\ I52 = I52 /\ I51 = I52 /\ I50 = I50 /\ 0 <= I51 /\ I51 <= 0 /\ rnd6 = rnd6 /\ 2 <= -1 + I49] R = f8(x1, x2, x3, x4, x5, x6, x7, x8) -> f1(x1, x2, x3, x4, x5, x6, x7, x8) f7(I0, I1, I2, I3, I4, I5, I6, I7) -> f2(I0, I1, I2, I3, I4, I5, I6, I7) f6(I8, I9, I10, I11, I12, I13, I14, I15) -> f7(I8, rnd2, I10, I11, I12, I13, -1 + I14, rnd8) [y1 = y1 /\ rnd8 = y1 /\ rnd2 = rnd2] f5(I16, I17, I18, I19, I20, I21, I22, I23) -> f6(I16, I17, I18, I19, I20, I21, I22, I23) [I16 = I16] f2(I24, I25, I26, I27, I28, I29, I30, I31) -> f5(I24, I32, I26, rnd4, I28, I29, I30, I31) [1 <= I30 /\ I33 = I33 /\ rnd4 = I33 /\ I32 = I32] f4(I34, I35, I36, I37, I38, I39, I40, I41) -> f2(I34, I35, I36, I37, I38, I39, I40, I41) f2(I42, I43, I44, I45, I46, I47, I48, I49) -> f4(I42, I50, I44, I51, I46, rnd6, I48, -1 + I49) [1 <= I48 /\ I52 = I52 /\ I51 = I52 /\ I50 = I50 /\ 0 <= I51 /\ I51 <= 0 /\ rnd6 = rnd6 /\ 2 <= -1 + I49] f2(I53, I54, I55, I56, I57, I58, I59, I60) -> f3(I53, I54, I57, I56, I57, I58, I59, I60) [I59 <= 0] f1(I61, I62, I63, I64, I65, I66, I67, I68) -> f2(I61, I62, I63, I64, I65, I66, I67, I68) The dependency graph for this problem is:
popout
output may be truncated. 'popout' for the full output.
job log
popout
actions
all output
return to ITS