details

property	value
status	complete
benchmark	small05.t2.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n141.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	0.499325 seconds
cpu usage	0.50865
user time	0.272334
system time	0.236316
max virtual memory	113188.0
max residence set size	8348.0

stage attributes

key	value
starexec-result	MAYBE

output

MAYBE DP problem for innermost termination. P = f5#(x1, x2) -> f4#(x1, x2) f4#(I0, I1) -> f1#(I0, I1) [I0 <= I1 /\ I1 <= I0] f3#(I2, I3) -> f1#(I2, I3) f1#(I4, I5) -> f3#(1 + I4, 1 + I5) R = f5(x1, x2) -> f4(x1, x2) f4(I0, I1) -> f1(I0, I1) [I0 <= I1 /\ I1 <= I0] f3(I2, I3) -> f1(I2, I3) f1(I4, I5) -> f3(1 + I4, 1 + I5) f1(I6, I7) -> f2(I6, I7) [1 + I7 <= I6] The dependency graph for this problem is: 0 -> 1 1 -> 3 2 -> 3 3 -> 2 Where: 0) f5#(x1, x2) -> f4#(x1, x2) 1) f4#(I0, I1) -> f1#(I0, I1) [I0 <= I1 /\ I1 <= I0] 2) f3#(I2, I3) -> f1#(I2, I3) 3) f1#(I4, I5) -> f3#(1 + I4, 1 + I5) We have the following SCCs. { 2, 3 } DP problem for innermost termination. P = f3#(I2, I3) -> f1#(I2, I3) f1#(I4, I5) -> f3#(1 + I4, 1 + I5) R = f5(x1, x2) -> f4(x1, x2) f4(I0, I1) -> f1(I0, I1) [I0 <= I1 /\ I1 <= I0] f3(I2, I3) -> f1(I2, I3) f1(I4, I5) -> f3(1 + I4, 1 + I5) f1(I6, I7) -> f2(I6, I7) [1 + I7 <= I6] popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to ITS