details

property	value
status	complete
benchmark	FactSLR.jar-obl-8.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n150.star.cs.uiowa.edu
space	From_AProVE_2014

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	1.05847 seconds
cpu usage	1.06871
user time	0.600108
system time	0.468605
max virtual memory	684116.0
max residence set size	8504.0

stage attributes

key	value
starexec-result	MAYBE

output

MAYBE DP problem for innermost termination. P = init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) f2#(I0, I1, I2, I3) -> f2#(I0 - 1, I0, I2, I3 + 1) [I3 <= I2 - 1 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1 /\ 0 <= I1 - 1] f2#(I4, I5, I6, I7) -> f2#(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1] f1#(I8, I9, I10, I11) -> f2#(I12, I13, I9, 1) [-1 <= y1 - 1 /\ 0 <= I9 - 1 /\ 0 <= I8 - 1 /\ 3 * y1 - 1 = I12 /\ 3 * y1 = I13] f1#(I14, I15, I16, I17) -> f2#(-1, 0, 0, 0) [0 = I15 /\ 0 <= I14 - 1] R = init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) f2(I0, I1, I2, I3) -> f2(I0 - 1, I0, I2, I3 + 1) [I3 <= I2 - 1 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1 /\ 0 <= I1 - 1] f2(I4, I5, I6, I7) -> f2(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1] f1(I8, I9, I10, I11) -> f2(I12, I13, I9, 1) [-1 <= y1 - 1 /\ 0 <= I9 - 1 /\ 0 <= I8 - 1 /\ 3 * y1 - 1 = I12 /\ 3 * y1 = I13] f1(I14, I15, I16, I17) -> f2(-1, 0, 0, 0) [0 = I15 /\ 0 <= I14 - 1] The dependency graph for this problem is: 0 -> 3, 4 1 -> 1, 2 2 -> 2 3 -> 1, 2 4 -> Where: 0) init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) 1) f2#(I0, I1, I2, I3) -> f2#(I0 - 1, I0, I2, I3 + 1) [I3 <= I2 - 1 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1 /\ 0 <= I1 - 1] 2) f2#(I4, I5, I6, I7) -> f2#(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1] 3) f1#(I8, I9, I10, I11) -> f2#(I12, I13, I9, 1) [-1 <= y1 - 1 /\ 0 <= I9 - 1 /\ 0 <= I8 - 1 /\ 3 * y1 - 1 = I12 /\ 3 * y1 = I13] 4) f1#(I14, I15, I16, I17) -> f2#(-1, 0, 0, 0) [0 = I15 /\ 0 <= I14 - 1] We have the following SCCs. { 1 } { 2 } DP problem for innermost termination. P = f2#(I4, I5, I6, I7) -> f2#(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1] R = init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) f2(I0, I1, I2, I3) -> f2(I0 - 1, I0, I2, I3 + 1) [I3 <= I2 - 1 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1 /\ 0 <= I1 - 1] f2(I4, I5, I6, I7) -> f2(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1] f1(I8, I9, I10, I11) -> f2(I12, I13, I9, 1) [-1 <= y1 - 1 /\ 0 <= I9 - 1 /\ 0 <= I8 - 1 /\ 3 * y1 - 1 = I12 /\ 3 * y1 = I13] f1(I14, I15, I16, I17) -> f2(-1, 0, 0, 0) [0 = I15 /\ 0 <= I14 - 1] popout

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