details

property	value
status	complete
benchmark	AProVEMathRecursive.jar-obl-8.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n151.star.cs.uiowa.edu
space	From_AProVE_2014

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	5.98142 seconds
cpu usage	6.07076
user time	3.29321
system time	2.77755
max virtual memory	726296.0
max residence set size	8636.0

stage attributes

key	value
starexec-result	YES

output

YES DP problem for innermost termination. P = init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) f6#(I0, I1, I2, I3) -> f2#(I0, I1 - 1, I4, I5) [1 = I2 /\ I1 - 1 <= I1 - 1 /\ 1 <= I1 - 1] f7#(I6, I7, I8, I9) -> f2#(I6, I10, I11, I12) [0 = I8 /\ 0 <= I7 - 2 * I10 /\ I7 - 2 * I10 <= 1 /\ 0 <= I10 - 1 /\ I10 <= I7 - 1 /\ 1 <= I7 - 1] f6#(I13, I14, I15, I16) -> f7#(I13, I14, 0, I16) [1 <= I14 - 1 /\ 0 <= y1 - 1 /\ y1 <= I14 - 1 /\ 0 = I15] f5#(I17, I18, I19, I20) -> f6#(I17, I18, I21, I22) [1 <= I18 - 1 /\ 2 <= I17 - 1 /\ I18 - 2 * I23 <= 1 /\ 0 <= I18 - 2 * I23 /\ I18 - 2 * I23 = I21] f2#(I24, I25, I26, I27) -> f5#(I24, I25, I28, I29) [1 <= I25 - 1 /\ 2 <= I24 - 1] f5#(I30, I31, I32, I33) -> f6#(I30, I31, I34, I35) [1 <= I31 - 1 /\ I30 <= 1 /\ I31 - 2 * I36 <= 1 /\ 0 <= I31 - 2 * I36 /\ I31 - 2 * I36 = I34] f2#(I37, I38, I39, I40) -> f5#(I37, I38, I41, I42) [1 <= I38 - 1 /\ I37 <= 1] f4#(I43, I44, I45, I46) -> f2#(I44, I45, I47, I48) [0 <= I43 - 1 /\ 1 <= I49 - 1] f3#(I50, I51, I52, I53) -> f4#(I54, I51, I55, I56) [1 <= I57 - 1 /\ -1 <= I55 - 1 /\ I54 <= I50 /\ 0 <= I50 - 1 /\ 0 <= I54 - 1] f3#(I58, I59, I60, I61) -> f4#(I62, I59, 0, I63) [I62 <= I58 /\ 1 <= I64 - 1 /\ 0 <= I58 - 1 /\ 0 <= I62 - 1] f3#(I65, I66, I67, I68) -> f2#(I66, 0, I69, I70) [0 <= I65 - 1] f1#(I71, I72, I73, I74) -> f3#(I75, I76, I77, I78) [0 <= I75 - 1 /\ 0 <= I71 - 1 /\ I75 <= I71 /\ 0 <= I72 - 1 /\ -1 <= I76 - 1] f1#(I79, I80, I81, I82) -> f3#(I83, 0, I84, I85) [0 <= I83 - 1 /\ 0 <= I79 - 1 /\ 0 <= I80 - 1 /\ I83 <= I79] f1#(I86, I87, I88, I89) -> f2#(0, 0, I90, I91) [0 = I87 /\ 0 <= I86 - 1] R = init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) f6(I0, I1, I2, I3) -> f2(I0, I1 - 1, I4, I5) [1 = I2 /\ I1 - 1 <= I1 - 1 /\ 1 <= I1 - 1] f7(I6, I7, I8, I9) -> f2(I6, I10, I11, I12) [0 = I8 /\ 0 <= I7 - 2 * I10 /\ I7 - 2 * I10 <= 1 /\ 0 <= I10 - 1 /\ I10 <= I7 - 1 /\ 1 <= I7 - 1] f6(I13, I14, I15, I16) -> f7(I13, I14, 0, I16) [1 <= I14 - 1 /\ 0 <= y1 - 1 /\ y1 <= I14 - 1 /\ 0 = I15] f5(I17, I18, I19, I20) -> f6(I17, I18, I21, I22) [1 <= I18 - 1 /\ 2 <= I17 - 1 /\ I18 - 2 * I23 <= 1 /\ 0 <= I18 - 2 * I23 /\ I18 - 2 * I23 = I21] f2(I24, I25, I26, I27) -> f5(I24, I25, I28, I29) [1 <= I25 - 1 /\ 2 <= I24 - 1] f5(I30, I31, I32, I33) -> f6(I30, I31, I34, I35) [1 <= I31 - 1 /\ I30 <= 1 /\ I31 - 2 * I36 <= 1 /\ 0 <= I31 - 2 * I36 /\ I31 - 2 * I36 = I34] f2(I37, I38, I39, I40) -> f5(I37, I38, I41, I42) [1 <= I38 - 1 /\ I37 <= 1] f4(I43, I44, I45, I46) -> f2(I44, I45, I47, I48) [0 <= I43 - 1 /\ 1 <= I49 - 1] f3(I50, I51, I52, I53) -> f4(I54, I51, I55, I56) [1 <= I57 - 1 /\ -1 <= I55 - 1 /\ I54 <= I50 /\ 0 <= I50 - 1 /\ 0 <= I54 - 1] f3(I58, I59, I60, I61) -> f4(I62, I59, 0, I63) [I62 <= I58 /\ 1 <= I64 - 1 /\ 0 <= I58 - 1 /\ 0 <= I62 - 1] f3(I65, I66, I67, I68) -> f2(I66, 0, I69, I70) [0 <= I65 - 1] f1(I71, I72, I73, I74) -> f3(I75, I76, I77, I78) [0 <= I75 - 1 /\ 0 <= I71 - 1 /\ I75 <= I71 /\ 0 <= I72 - 1 /\ -1 <= I76 - 1] f1(I79, I80, I81, I82) -> f3(I83, 0, I84, I85) [0 <= I83 - 1 /\ 0 <= I79 - 1 /\ 0 <= I80 - 1 /\ I83 <= I79] f1(I86, I87, I88, I89) -> f2(0, 0, I90, I91) [0 = I87 /\ 0 <= I86 - 1] The dependency graph for this problem is: 0 -> 12, 13, 14 1 -> 5, 7 2 -> 5, 7 3 -> 2 4 -> 1, 3 5 -> 4 6 -> 1, 3 7 -> 6 8 -> 5, 7 9 -> 8 10 -> 8 11 -> 12 -> 9, 10, 11 13 -> 9, 10, 11 14 -> Where: 0) init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) 1) f6#(I0, I1, I2, I3) -> f2#(I0, I1 - 1, I4, I5) [1 = I2 /\ I1 - 1 <= I1 - 1 /\ 1 <= I1 - 1] 2) f7#(I6, I7, I8, I9) -> f2#(I6, I10, I11, I12) [0 = I8 /\ 0 <= I7 - 2 * I10 /\ I7 - 2 * I10 <= 1 /\ 0 <= I10 - 1 /\ I10 <= I7 - 1 /\ 1 <= I7 - 1] 3) f6#(I13, I14, I15, I16) -> f7#(I13, I14, 0, I16) [1 <= I14 - 1 /\ 0 <= y1 - 1 /\ y1 <= I14 - 1 /\ 0 = I15] 4) f5#(I17, I18, I19, I20) -> f6#(I17, I18, I21, I22) [1 <= I18 - 1 /\ 2 <= I17 - 1 /\ I18 - 2 * I23 <= 1 /\ 0 <= I18 - 2 * I23 /\ I18 - 2 * I23 = I21] 5) f2#(I24, I25, I26, I27) -> f5#(I24, I25, I28, I29) [1 <= I25 - 1 /\ 2 <= I24 - 1] 6) f5#(I30, I31, I32, I33) -> f6#(I30, I31, I34, I35) [1 <= I31 - 1 /\ I30 <= 1 /\ I31 - 2 * I36 <= 1 /\ 0 <= I31 - 2 * I36 /\ I31 - 2 * I36 = I34] 7) f2#(I37, I38, I39, I40) -> f5#(I37, I38, I41, I42) [1 <= I38 - 1 /\ I37 <= 1] 8) f4#(I43, I44, I45, I46) -> f2#(I44, I45, I47, I48) [0 <= I43 - 1 /\ 1 <= I49 - 1] 9) f3#(I50, I51, I52, I53) -> f4#(I54, I51, I55, I56) [1 <= I57 - 1 /\ -1 <= I55 - 1 /\ I54 <= I50 /\ 0 <= I50 - 1 /\ 0 <= I54 - 1] 10) f3#(I58, I59, I60, I61) -> f4#(I62, I59, 0, I63) [I62 <= I58 /\ 1 <= I64 - 1 /\ 0 <= I58 - 1 /\ 0 <= I62 - 1] 11) f3#(I65, I66, I67, I68) -> f2#(I66, 0, I69, I70) [0 <= I65 - 1] 12) f1#(I71, I72, I73, I74) -> f3#(I75, I76, I77, I78) [0 <= I75 - 1 /\ 0 <= I71 - 1 /\ I75 <= I71 /\ 0 <= I72 - 1 /\ -1 <= I76 - 1] 13) f1#(I79, I80, I81, I82) -> f3#(I83, 0, I84, I85) [0 <= I83 - 1 /\ 0 <= I79 - 1 /\ 0 <= I80 - 1 /\ I83 <= I79] 14) f1#(I86, I87, I88, I89) -> f2#(0, 0, I90, I91) [0 = I87 /\ 0 <= I86 - 1] We have the following SCCs. { 1, 2, 3, 4, 5, 6, 7 } DP problem for innermost termination. P = f6#(I0, I1, I2, I3) -> f2#(I0, I1 - 1, I4, I5) [1 = I2 /\ I1 - 1 <= I1 - 1 /\ 1 <= I1 - 1] f7#(I6, I7, I8, I9) -> f2#(I6, I10, I11, I12) [0 = I8 /\ 0 <= I7 - 2 * I10 /\ I7 - 2 * I10 <= 1 /\ 0 <= I10 - 1 /\ I10 <= I7 - 1 /\ 1 <= I7 - 1] f6#(I13, I14, I15, I16) -> f7#(I13, I14, 0, I16) [1 <= I14 - 1 /\ 0 <= y1 - 1 /\ y1 <= I14 - 1 /\ 0 = I15] f5#(I17, I18, I19, I20) -> f6#(I17, I18, I21, I22) [1 <= I18 - 1 /\ 2 <= I17 - 1 /\ I18 - 2 * I23 <= 1 /\ 0 <= I18 - 2 * I23 /\ I18 - 2 * I23 = I21] f2#(I24, I25, I26, I27) -> f5#(I24, I25, I28, I29) [1 <= I25 - 1 /\ 2 <= I24 - 1] f5#(I30, I31, I32, I33) -> f6#(I30, I31, I34, I35) [1 <= I31 - 1 /\ I30 <= 1 /\ I31 - 2 * I36 <= 1 /\ 0 <= I31 - 2 * I36 /\ I31 - 2 * I36 = I34] f2#(I37, I38, I39, I40) -> f5#(I37, I38, I41, I42) [1 <= I38 - 1 /\ I37 <= 1] R = init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) f6(I0, I1, I2, I3) -> f2(I0, I1 - 1, I4, I5) [1 = I2 /\ I1 - 1 <= I1 - 1 /\ 1 <= I1 - 1] f7(I6, I7, I8, I9) -> f2(I6, I10, I11, I12) [0 = I8 /\ 0 <= I7 - 2 * I10 /\ I7 - 2 * I10 <= 1 /\ 0 <= I10 - 1 /\ I10 <= I7 - 1 /\ 1 <= I7 - 1] f6(I13, I14, I15, I16) -> f7(I13, I14, 0, I16) [1 <= I14 - 1 /\ 0 <= y1 - 1 /\ y1 <= I14 - 1 /\ 0 = I15] f5(I17, I18, I19, I20) -> f6(I17, I18, I21, I22) [1 <= I18 - 1 /\ 2 <= I17 - 1 /\ I18 - 2 * I23 <= 1 /\ 0 <= I18 - 2 * I23 /\ I18 - 2 * I23 = I21] f2(I24, I25, I26, I27) -> f5(I24, I25, I28, I29) [1 <= I25 - 1 /\ 2 <= I24 - 1] f5(I30, I31, I32, I33) -> f6(I30, I31, I34, I35) [1 <= I31 - 1 /\ I30 <= 1 /\ I31 - 2 * I36 <= 1 /\ 0 <= I31 - 2 * I36 /\ I31 - 2 * I36 = I34] f2(I37, I38, I39, I40) -> f5(I37, I38, I41, I42) [1 <= I38 - 1 /\ I37 <= 1] f4(I43, I44, I45, I46) -> f2(I44, I45, I47, I48) [0 <= I43 - 1 /\ 1 <= I49 - 1] f3(I50, I51, I52, I53) -> f4(I54, I51, I55, I56) [1 <= I57 - 1 /\ -1 <= I55 - 1 /\ I54 <= I50 /\ 0 <= I50 - 1 /\ 0 <= I54 - 1] f3(I58, I59, I60, I61) -> f4(I62, I59, 0, I63) [I62 <= I58 /\ 1 <= I64 - 1 /\ 0 <= I58 - 1 /\ 0 <= I62 - 1] f3(I65, I66, I67, I68) -> f2(I66, 0, I69, I70) [0 <= I65 - 1] f1(I71, I72, I73, I74) -> f3(I75, I76, I77, I78) [0 <= I75 - 1 /\ 0 <= I71 - 1 /\ I75 <= I71 /\ 0 <= I72 - 1 /\ -1 <= I76 - 1] f1(I79, I80, I81, I82) -> f3(I83, 0, I84, I85) [0 <= I83 - 1 /\ 0 <= I79 - 1 /\ 0 <= I80 - 1 /\ I83 <= I79] f1(I86, I87, I88, I89) -> f2(0, 0, I90, I91) [0 = I87 /\ 0 <= I86 - 1] We use the basic value criterion with the projection function NU: NU[f5#(z1,z2,z3,z4)] = z2 popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to ITS