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ITS pair #487099672
details
property
value
status
complete
benchmark
Avg.jar-obl-8.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n151.star.cs.uiowa.edu
space
From_AProVE_2014
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
0.660829 seconds
cpu usage
0.66051
user time
0.357781
system time
0.302729
max virtual memory
124308.0
max residence set size
8564.0
stage attributes
key
value
starexec-result
MAYBE
output
MAYBE DP problem for innermost termination. P = init#(x1, x2) -> f1#(rnd1, rnd2) f2#(I0, I1) -> f2#(I0 - 2, 1) [0 = I1 /\ I0 - 2 <= I0 - 1 /\ 2 <= I0 - 1] f2#(I2, I3) -> f2#(I2 + 1, I3 - 1) [I3 - 1 <= I3 - 1 /\ I2 <= I2 + 1 - 1 /\ -1 <= I2 - 1 /\ 0 <= I3 - 1] f1#(I4, I5) -> f2#(I6, I7) [0 <= I4 - 1 /\ -1 <= I7 - 1 /\ 1 <= I5 - 1 /\ -1 <= I6 - 1] R = init(x1, x2) -> f1(rnd1, rnd2) f2(I0, I1) -> f2(I0 - 2, 1) [0 = I1 /\ I0 - 2 <= I0 - 1 /\ 2 <= I0 - 1] f2(I2, I3) -> f2(I2 + 1, I3 - 1) [I3 - 1 <= I3 - 1 /\ I2 <= I2 + 1 - 1 /\ -1 <= I2 - 1 /\ 0 <= I3 - 1] f1(I4, I5) -> f2(I6, I7) [0 <= I4 - 1 /\ -1 <= I7 - 1 /\ 1 <= I5 - 1 /\ -1 <= I6 - 1] The dependency graph for this problem is: 0 -> 3 1 -> 2 2 -> 1, 2 3 -> 1, 2 Where: 0) init#(x1, x2) -> f1#(rnd1, rnd2) 1) f2#(I0, I1) -> f2#(I0 - 2, 1) [0 = I1 /\ I0 - 2 <= I0 - 1 /\ 2 <= I0 - 1] 2) f2#(I2, I3) -> f2#(I2 + 1, I3 - 1) [I3 - 1 <= I3 - 1 /\ I2 <= I2 + 1 - 1 /\ -1 <= I2 - 1 /\ 0 <= I3 - 1] 3) f1#(I4, I5) -> f2#(I6, I7) [0 <= I4 - 1 /\ -1 <= I7 - 1 /\ 1 <= I5 - 1 /\ -1 <= I6 - 1] We have the following SCCs. { 1, 2 } DP problem for innermost termination. P = f2#(I0, I1) -> f2#(I0 - 2, 1) [0 = I1 /\ I0 - 2 <= I0 - 1 /\ 2 <= I0 - 1] f2#(I2, I3) -> f2#(I2 + 1, I3 - 1) [I3 - 1 <= I3 - 1 /\ I2 <= I2 + 1 - 1 /\ -1 <= I2 - 1 /\ 0 <= I3 - 1] R = init(x1, x2) -> f1(rnd1, rnd2) f2(I0, I1) -> f2(I0 - 2, 1) [0 = I1 /\ I0 - 2 <= I0 - 1 /\ 2 <= I0 - 1] f2(I2, I3) -> f2(I2 + 1, I3 - 1) [I3 - 1 <= I3 - 1 /\ I2 <= I2 + 1 - 1 /\ -1 <= I2 - 1 /\ 0 <= I3 - 1] f1(I4, I5) -> f2(I6, I7) [0 <= I4 - 1 /\ -1 <= I7 - 1 /\ 1 <= I5 - 1 /\ -1 <= I6 - 1]
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