details

property	value
status	complete
benchmark	Velroyen08-ex08.jar-obl-8.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n150.star.cs.uiowa.edu
space	From_AProVE_2014

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	2.16052 seconds
cpu usage	2.19038
user time	1.17865
system time	1.01173
max virtual memory	576160.0
max residence set size	8552.0

stage attributes

key	value
starexec-result	MAYBE

output

MAYBE DP problem for innermost termination. P = init#(x1, x2) -> f1#(rnd1, rnd2) f2#(I0, I1) -> f2#(0, 9) [10 = I1] f2#(I2, I3) -> f2#(0, I3 - 1) [0 = I2 /\ 10 <= I3 - 1] f2#(I4, I5) -> f2#(1, I5 + 1) [1 = I4 /\ 10 <= I5 - 1] f2#(I6, I7) -> f2#(0, I7 - 1) [0 = I6 /\ 1 <= I7 - 1 /\ I7 <= 9] f2#(I8, I9) -> f2#(1, I9 + 1) [1 = I8 /\ 1 <= I9 - 1 /\ I9 <= 9] f2#(I10, I11) -> f2#(1, 2) [1 = I11] f1#(I12, I13) -> f2#(0, I13) [-1 <= I13 - 1 /\ 0 <= I12 - 1] R = init(x1, x2) -> f1(rnd1, rnd2) f2(I0, I1) -> f2(0, 9) [10 = I1] f2(I2, I3) -> f2(0, I3 - 1) [0 = I2 /\ 10 <= I3 - 1] f2(I4, I5) -> f2(1, I5 + 1) [1 = I4 /\ 10 <= I5 - 1] f2(I6, I7) -> f2(0, I7 - 1) [0 = I6 /\ 1 <= I7 - 1 /\ I7 <= 9] f2(I8, I9) -> f2(1, I9 + 1) [1 = I8 /\ 1 <= I9 - 1 /\ I9 <= 9] f2(I10, I11) -> f2(1, 2) [1 = I11] f1(I12, I13) -> f2(0, I13) [-1 <= I13 - 1 /\ 0 <= I12 - 1] The dependency graph for this problem is: 0 -> 7 1 -> 4 2 -> 1, 2 3 -> 3 4 -> 4, 6 5 -> 1, 5 6 -> 5 7 -> 1, 2, 4, 6 Where: 0) init#(x1, x2) -> f1#(rnd1, rnd2) 1) f2#(I0, I1) -> f2#(0, 9) [10 = I1] 2) f2#(I2, I3) -> f2#(0, I3 - 1) [0 = I2 /\ 10 <= I3 - 1] 3) f2#(I4, I5) -> f2#(1, I5 + 1) [1 = I4 /\ 10 <= I5 - 1] 4) f2#(I6, I7) -> f2#(0, I7 - 1) [0 = I6 /\ 1 <= I7 - 1 /\ I7 <= 9] 5) f2#(I8, I9) -> f2#(1, I9 + 1) [1 = I8 /\ 1 <= I9 - 1 /\ I9 <= 9] 6) f2#(I10, I11) -> f2#(1, 2) [1 = I11] 7) f1#(I12, I13) -> f2#(0, I13) [-1 <= I13 - 1 /\ 0 <= I12 - 1] We have the following SCCs. { 3 } { 2 } { 1, 4, 5, 6 } DP problem for innermost termination. P = f2#(I0, I1) -> f2#(0, 9) [10 = I1] f2#(I6, I7) -> f2#(0, I7 - 1) [0 = I6 /\ 1 <= I7 - 1 /\ I7 <= 9] f2#(I8, I9) -> f2#(1, I9 + 1) [1 = I8 /\ 1 <= I9 - 1 /\ I9 <= 9] f2#(I10, I11) -> f2#(1, 2) [1 = I11] R = init(x1, x2) -> f1(rnd1, rnd2) f2(I0, I1) -> f2(0, 9) [10 = I1] f2(I2, I3) -> f2(0, I3 - 1) [0 = I2 /\ 10 <= I3 - 1] f2(I4, I5) -> f2(1, I5 + 1) [1 = I4 /\ 10 <= I5 - 1] f2(I6, I7) -> f2(0, I7 - 1) [0 = I6 /\ 1 <= I7 - 1 /\ I7 <= 9] f2(I8, I9) -> f2(1, I9 + 1) [1 = I8 /\ 1 <= I9 - 1 /\ I9 <= 9] f2(I10, I11) -> f2(1, 2) [1 = I11] f1(I12, I13) -> f2(0, I13) [-1 <= I13 - 1 /\ 0 <= I12 - 1] popout

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