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ITS pair #487099912
details
property
value
status
complete
benchmark
PastaA7.jar-obl-8.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n149.star.cs.uiowa.edu
space
From_AProVE_2014
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
0.353389 seconds
cpu usage
0.360884
user time
0.193485
system time
0.167399
max virtual memory
113188.0
max residence set size
8640.0
stage attributes
key
value
starexec-result
YES
output
YES DP problem for innermost termination. P = init#(x1, x2, x3) -> f1#(rnd1, rnd2, rnd3) f2#(I0, I1, I2) -> f2#(I0 + 1, I1, I2 + 1) [I0 <= I1 - 1 /\ I2 <= I1 - 1] f1#(I3, I4, I5) -> f2#(I6, I7, I8) [0 <= I3 - 1 /\ -1 <= I8 - 1 /\ -1 <= I6 - 1 /\ -1 <= I4 - 1 /\ -1 <= I7 - 1] R = init(x1, x2, x3) -> f1(rnd1, rnd2, rnd3) f2(I0, I1, I2) -> f2(I0 + 1, I1, I2 + 1) [I0 <= I1 - 1 /\ I2 <= I1 - 1] f1(I3, I4, I5) -> f2(I6, I7, I8) [0 <= I3 - 1 /\ -1 <= I8 - 1 /\ -1 <= I6 - 1 /\ -1 <= I4 - 1 /\ -1 <= I7 - 1] The dependency graph for this problem is: 0 -> 2 1 -> 1 2 -> 1 Where: 0) init#(x1, x2, x3) -> f1#(rnd1, rnd2, rnd3) 1) f2#(I0, I1, I2) -> f2#(I0 + 1, I1, I2 + 1) [I0 <= I1 - 1 /\ I2 <= I1 - 1] 2) f1#(I3, I4, I5) -> f2#(I6, I7, I8) [0 <= I3 - 1 /\ -1 <= I8 - 1 /\ -1 <= I6 - 1 /\ -1 <= I4 - 1 /\ -1 <= I7 - 1] We have the following SCCs. { 1 } DP problem for innermost termination. P = f2#(I0, I1, I2) -> f2#(I0 + 1, I1, I2 + 1) [I0 <= I1 - 1 /\ I2 <= I1 - 1] R = init(x1, x2, x3) -> f1(rnd1, rnd2, rnd3) f2(I0, I1, I2) -> f2(I0 + 1, I1, I2 + 1) [I0 <= I1 - 1 /\ I2 <= I1 - 1] f1(I3, I4, I5) -> f2(I6, I7, I8) [0 <= I3 - 1 /\ -1 <= I8 - 1 /\ -1 <= I6 - 1 /\ -1 <= I4 - 1 /\ -1 <= I7 - 1] We use the reverse value criterion with the projection function NU: NU[f2#(z1,z2,z3)] = z2 - 1 + -1 * z1 This gives the following inequalities: I0 <= I1 - 1 /\ I2 <= I1 - 1 ==> I1 - 1 + -1 * I0 > I1 - 1 + -1 * (I0 + 1) with I1 - 1 + -1 * I0 >= 0 All dependency pairs are strictly oriented, so the entire dependency pair problem may be removed.
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