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ITS pair #487099939
details
property
value
status
complete
benchmark
NonPeriodicNonterm2.jar-obl-8.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n149.star.cs.uiowa.edu
space
From_AProVE_2014
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
0.679368 seconds
cpu usage
0.692302
user time
0.340445
system time
0.351857
max virtual memory
124692.0
max residence set size
8676.0
stage attributes
key
value
starexec-result
MAYBE
output
MAYBE DP problem for innermost termination. P = init#(x1, x2) -> f1#(rnd1, rnd2) f2#(I0, I1) -> f2#(2 * I0 + 1, I1 + 1) [0 <= 2 * I0 /\ I0 - I1 = 0 /\ I1 <= I0 /\ -1 <= I1 - 1 /\ -1 <= I0 - 1] f2#(I2, I3) -> f2#(I2 - 1, I3) [0 <= I2 - I3 - 1 /\ I3 <= I2 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1] f1#(I4, I5) -> f2#(I6, I7) [0 <= I4 - 1 /\ -1 <= I6 - 1 /\ 1 <= I5 - 1 /\ -1 <= I7 - 1] R = init(x1, x2) -> f1(rnd1, rnd2) f2(I0, I1) -> f2(2 * I0 + 1, I1 + 1) [0 <= 2 * I0 /\ I0 - I1 = 0 /\ I1 <= I0 /\ -1 <= I1 - 1 /\ -1 <= I0 - 1] f2(I2, I3) -> f2(I2 - 1, I3) [0 <= I2 - I3 - 1 /\ I3 <= I2 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1] f1(I4, I5) -> f2(I6, I7) [0 <= I4 - 1 /\ -1 <= I6 - 1 /\ 1 <= I5 - 1 /\ -1 <= I7 - 1] The dependency graph for this problem is: 0 -> 3 1 -> 1, 2 2 -> 1, 2 3 -> 1, 2 Where: 0) init#(x1, x2) -> f1#(rnd1, rnd2) 1) f2#(I0, I1) -> f2#(2 * I0 + 1, I1 + 1) [0 <= 2 * I0 /\ I0 - I1 = 0 /\ I1 <= I0 /\ -1 <= I1 - 1 /\ -1 <= I0 - 1] 2) f2#(I2, I3) -> f2#(I2 - 1, I3) [0 <= I2 - I3 - 1 /\ I3 <= I2 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1] 3) f1#(I4, I5) -> f2#(I6, I7) [0 <= I4 - 1 /\ -1 <= I6 - 1 /\ 1 <= I5 - 1 /\ -1 <= I7 - 1] We have the following SCCs. { 1, 2 } DP problem for innermost termination. P = f2#(I0, I1) -> f2#(2 * I0 + 1, I1 + 1) [0 <= 2 * I0 /\ I0 - I1 = 0 /\ I1 <= I0 /\ -1 <= I1 - 1 /\ -1 <= I0 - 1] f2#(I2, I3) -> f2#(I2 - 1, I3) [0 <= I2 - I3 - 1 /\ I3 <= I2 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1] R = init(x1, x2) -> f1(rnd1, rnd2) f2(I0, I1) -> f2(2 * I0 + 1, I1 + 1) [0 <= 2 * I0 /\ I0 - I1 = 0 /\ I1 <= I0 /\ -1 <= I1 - 1 /\ -1 <= I0 - 1] f2(I2, I3) -> f2(I2 - 1, I3) [0 <= I2 - I3 - 1 /\ I3 <= I2 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1] f1(I4, I5) -> f2(I6, I7) [0 <= I4 - 1 /\ -1 <= I6 - 1 /\ 1 <= I5 - 1 /\ -1 <= I7 - 1]
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