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ITS pair #487100041
details
property
value
status
complete
benchmark
flip2_rec.jar-obl-8.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n148.star.cs.uiowa.edu
space
From_AProVE_2014
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
1.04316 seconds
cpu usage
1.06136
user time
0.538194
system time
0.523164
max virtual memory
126036.0
max residence set size
8624.0
stage attributes
key
value
starexec-result
MAYBE
output
MAYBE DP problem for innermost termination. P = init#(x1, x2) -> f1#(rnd1, rnd2) f2#(I0, I1) -> f2#(I1, I0) [1 <= I0 - 1 /\ I1 <= I0 - 1 /\ 0 <= I1 - 1] f2#(I2, I3) -> f2#(I3, I3) [1 <= I3 - 1 /\ 0 <= I2 - 1 /\ I2 <= I3 - 1] f2#(I4, I5) -> f2#(I4, I4 - 1) [I4 = I5 /\ I4 - 1 <= I4 - 1 /\ 0 <= I4 - 1] f1#(I6, I7) -> f2#(I7 + 5, I7) [0 <= I6 - 1 /\ -1 <= I7 - 1 /\ I7 <= I7 + 5 - 1] R = init(x1, x2) -> f1(rnd1, rnd2) f2(I0, I1) -> f2(I1, I0) [1 <= I0 - 1 /\ I1 <= I0 - 1 /\ 0 <= I1 - 1] f2(I2, I3) -> f2(I3, I3) [1 <= I3 - 1 /\ 0 <= I2 - 1 /\ I2 <= I3 - 1] f2(I4, I5) -> f2(I4, I4 - 1) [I4 = I5 /\ I4 - 1 <= I4 - 1 /\ 0 <= I4 - 1] f1(I6, I7) -> f2(I7 + 5, I7) [0 <= I6 - 1 /\ -1 <= I7 - 1 /\ I7 <= I7 + 5 - 1] The dependency graph for this problem is: 0 -> 4 1 -> 2 2 -> 3 3 -> 1 4 -> 1 Where: 0) init#(x1, x2) -> f1#(rnd1, rnd2) 1) f2#(I0, I1) -> f2#(I1, I0) [1 <= I0 - 1 /\ I1 <= I0 - 1 /\ 0 <= I1 - 1] 2) f2#(I2, I3) -> f2#(I3, I3) [1 <= I3 - 1 /\ 0 <= I2 - 1 /\ I2 <= I3 - 1] 3) f2#(I4, I5) -> f2#(I4, I4 - 1) [I4 = I5 /\ I4 - 1 <= I4 - 1 /\ 0 <= I4 - 1] 4) f1#(I6, I7) -> f2#(I7 + 5, I7) [0 <= I6 - 1 /\ -1 <= I7 - 1 /\ I7 <= I7 + 5 - 1] We have the following SCCs. { 1, 2, 3 } DP problem for innermost termination. P = f2#(I0, I1) -> f2#(I1, I0) [1 <= I0 - 1 /\ I1 <= I0 - 1 /\ 0 <= I1 - 1] f2#(I2, I3) -> f2#(I3, I3) [1 <= I3 - 1 /\ 0 <= I2 - 1 /\ I2 <= I3 - 1] f2#(I4, I5) -> f2#(I4, I4 - 1) [I4 = I5 /\ I4 - 1 <= I4 - 1 /\ 0 <= I4 - 1] R = init(x1, x2) -> f1(rnd1, rnd2) f2(I0, I1) -> f2(I1, I0) [1 <= I0 - 1 /\ I1 <= I0 - 1 /\ 0 <= I1 - 1] f2(I2, I3) -> f2(I3, I3) [1 <= I3 - 1 /\ 0 <= I2 - 1 /\ I2 <= I3 - 1] f2(I4, I5) -> f2(I4, I4 - 1) [I4 = I5 /\ I4 - 1 <= I4 - 1 /\ 0 <= I4 - 1] f1(I6, I7) -> f2(I7 + 5, I7) [0 <= I6 - 1 /\ -1 <= I7 - 1 /\ I7 <= I7 + 5 - 1]
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