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ITS pair #487100062
details
property
value
status
complete
benchmark
PastaB5.jar-obl-8.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n143.star.cs.uiowa.edu
space
From_AProVE_2014
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
0.134046 seconds
cpu usage
0.136446
user time
0.068314
system time
0.068132
max virtual memory
113188.0
max residence set size
8688.0
stage attributes
key
value
starexec-result
YES
output
YES DP problem for innermost termination. P = init#(x1, x2) -> f1#(rnd1, rnd2) f3#(I0, I1) -> f2#(I0 - 1, I2) [0 <= I0 - 1 /\ I0 - 2 * y1 = 0 /\ I0 - 2 * y1 <= 1 /\ 0 <= I0 - 2 * y1] f2#(I3, I4) -> f3#(I3, I5) [I3 - 2 * I6 = 0 /\ 0 <= I3 - 1] f1#(I7, I8) -> f2#(I9, I10) [0 <= I7 - 1 /\ -1 <= I9 - 1 /\ -1 <= I8 - 1] R = init(x1, x2) -> f1(rnd1, rnd2) f3(I0, I1) -> f2(I0 - 1, I2) [0 <= I0 - 1 /\ I0 - 2 * y1 = 0 /\ I0 - 2 * y1 <= 1 /\ 0 <= I0 - 2 * y1] f2(I3, I4) -> f3(I3, I5) [I3 - 2 * I6 = 0 /\ 0 <= I3 - 1] f1(I7, I8) -> f2(I9, I10) [0 <= I7 - 1 /\ -1 <= I9 - 1 /\ -1 <= I8 - 1] The dependency graph for this problem is: 0 -> 3 1 -> 2 -> 1 3 -> 2 Where: 0) init#(x1, x2) -> f1#(rnd1, rnd2) 1) f3#(I0, I1) -> f2#(I0 - 1, I2) [0 <= I0 - 1 /\ I0 - 2 * y1 = 0 /\ I0 - 2 * y1 <= 1 /\ 0 <= I0 - 2 * y1] 2) f2#(I3, I4) -> f3#(I3, I5) [I3 - 2 * I6 = 0 /\ 0 <= I3 - 1] 3) f1#(I7, I8) -> f2#(I9, I10) [0 <= I7 - 1 /\ -1 <= I9 - 1 /\ -1 <= I8 - 1] We have the following SCCs.
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