details

property	value
status	complete
benchmark	FibSLR.jar-obl-8.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n138.star.cs.uiowa.edu
space	From_AProVE_2014

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	0.66857 seconds
cpu usage	0.679716
user time	0.363671
system time	0.316045
max virtual memory	720668.0
max residence set size	8504.0

stage attributes

key	value
starexec-result	MAYBE

output

MAYBE DP problem for innermost termination. P = init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) f2#(I0, I1, I2, I3) -> f2#(I0 - 1, I0, I2, I3 + 1) [I3 <= I2 - 1 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1 /\ 0 <= I1 - 1] f2#(I4, I5, I6, I7) -> f2#(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1] f1#(I8, I9, I10, I11) -> f2#(I12, I13, I9, 2) [-1 <= y2 - 1 /\ 1 <= I9 - 1 /\ -1 <= y1 - 1 /\ 0 <= I8 - 1 /\ y1 * y2 - 1 = I12 /\ y1 * y2 = I13] f1#(I14, I15, I16, I17) -> f2#(-1, 0, 1, 1) [0 <= I14 - 1 /\ -1 <= I18 - 1 /\ 1 = I15] f1#(I19, I20, I21, I22) -> f2#(-1, 0, 0, 0) [0 = I20 /\ 0 <= I19 - 1] R = init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) f2(I0, I1, I2, I3) -> f2(I0 - 1, I0, I2, I3 + 1) [I3 <= I2 - 1 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1 /\ 0 <= I1 - 1] f2(I4, I5, I6, I7) -> f2(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1] f1(I8, I9, I10, I11) -> f2(I12, I13, I9, 2) [-1 <= y2 - 1 /\ 1 <= I9 - 1 /\ -1 <= y1 - 1 /\ 0 <= I8 - 1 /\ y1 * y2 - 1 = I12 /\ y1 * y2 = I13] f1(I14, I15, I16, I17) -> f2(-1, 0, 1, 1) [0 <= I14 - 1 /\ -1 <= I18 - 1 /\ 1 = I15] f1(I19, I20, I21, I22) -> f2(-1, 0, 0, 0) [0 = I20 /\ 0 <= I19 - 1] The dependency graph for this problem is: 0 -> 3, 4, 5 1 -> 1, 2 2 -> 2 3 -> 1, 2 4 -> 5 -> Where: 0) init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) 1) f2#(I0, I1, I2, I3) -> f2#(I0 - 1, I0, I2, I3 + 1) [I3 <= I2 - 1 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1 /\ 0 <= I1 - 1] 2) f2#(I4, I5, I6, I7) -> f2#(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1] 3) f1#(I8, I9, I10, I11) -> f2#(I12, I13, I9, 2) [-1 <= y2 - 1 /\ 1 <= I9 - 1 /\ -1 <= y1 - 1 /\ 0 <= I8 - 1 /\ y1 * y2 - 1 = I12 /\ y1 * y2 = I13] 4) f1#(I14, I15, I16, I17) -> f2#(-1, 0, 1, 1) [0 <= I14 - 1 /\ -1 <= I18 - 1 /\ 1 = I15] 5) f1#(I19, I20, I21, I22) -> f2#(-1, 0, 0, 0) [0 = I20 /\ 0 <= I19 - 1] We have the following SCCs. { 1 } { 2 } DP problem for innermost termination. P = f2#(I4, I5, I6, I7) -> f2#(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1] R = init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) f2(I0, I1, I2, I3) -> f2(I0 - 1, I0, I2, I3 + 1) [I3 <= I2 - 1 /\ -1 <= I3 - 1 /\ -1 <= I2 - 1 /\ 0 <= I1 - 1] f2(I4, I5, I6, I7) -> f2(I4 - 1, I4, I6, I7) [-1 <= I6 - 1 /\ I6 <= I7 /\ 0 <= I5 - 1] f1(I8, I9, I10, I11) -> f2(I12, I13, I9, 2) [-1 <= y2 - 1 /\ 1 <= I9 - 1 /\ -1 <= y1 - 1 /\ 0 <= I8 - 1 /\ y1 * y2 - 1 = I12 /\ y1 * y2 = I13] f1(I14, I15, I16, I17) -> f2(-1, 0, 1, 1) [0 <= I14 - 1 /\ -1 <= I18 - 1 /\ 1 = I15] f1(I19, I20, I21, I22) -> f2(-1, 0, 0, 0) [0 = I20 /\ 0 <= I19 - 1] popout

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