details

property	value
status	complete
benchmark	poly3.itrs
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n149.star.cs.uiowa.edu
space	Mixed_ITRS_2014

run statistics

property	value
solver	Ctrl
configuration	Itrs
runtime (wallclock)	1.00057 seconds
cpu usage	0.997274
user time	0.697368
system time	0.299906
max virtual memory	720032.0
max residence set size	12692.0

stage attributes

key	value
starexec-result	MAYBE

output

MAYBE DP problem for innermost termination. P = eval#(x, y, z) -> eval#(x, y - 1, z + y) [x >= 0 && z * z * z >= y] eval#(I0, I1, I2) -> eval#(I0 - 1, I1 - 1, I2) [I0 >= 0 && I2 * I2 * I2 >= I1] R = eval(x, y, z) -> eval(x, y - 1, z + y) [x >= 0 && z * z * z >= y] eval(I0, I1, I2) -> eval(I0 - 1, I1 - 1, I2) [I0 >= 0 && I2 * I2 * I2 >= I1] We use the reverse value criterion with the projection function NU: NU[eval#(z1,z2,z3)] = z1 This gives the following inequalities: x >= 0 && z * z * z >= y ==> x >= x I0 >= 0 && I2 * I2 * I2 >= I1 ==> I0 > I0 - 1 with I0 >= 0 We remove all the strictly oriented dependency pairs. DP problem for innermost termination. P = eval#(x, y, z) -> eval#(x, y - 1, z + y) [x >= 0 && z * z * z >= y] R = eval(x, y, z) -> eval(x, y - 1, z + y) [x >= 0 && z * z * z >= y] eval(I0, I1, I2) -> eval(I0 - 1, I1 - 1, I2) [I0 >= 0 && I2 * I2 * I2 >= I1] popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to Integer TRS Innermost