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Integer TRS Innermost pair #487100500
details
property
value
status
complete
benchmark
quicksort.itrs
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n142.star.cs.uiowa.edu
space
Mixed_ITRS_2014
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
2.70778 seconds
cpu usage
6.86094
user time
6.51351
system time
0.347425
max virtual memory
1.9348776E7
max residence set size
465456.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox/benchmark/theBenchmark.itrs # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination of the given ITRS could be proven: (0) ITRS (1) ITRStoIDPProof [EQUIVALENT, 0 ms] (2) IDP (3) ItpfGraphProof [EQUIVALENT, 12 ms] (4) IDP (5) IDependencyGraphProof [EQUIVALENT, 0 ms] (6) AND (7) IDP (8) UsableRulesProof [EQUIVALENT, 0 ms] (9) IDP (10) IDPtoQDPProof [SOUND, 34 ms] (11) QDP (12) QReductionProof [EQUIVALENT, 0 ms] (13) QDP (14) QDPSizeChangeProof [EQUIVALENT, 0 ms] (15) YES (16) IDP (17) UsableRulesProof [EQUIVALENT, 3 ms] (18) IDP (19) IDPNonInfProof [SOUND, 87 ms] (20) IDP (21) PisEmptyProof [EQUIVALENT, 0 ms] (22) YES (23) IDP (24) UsableRulesProof [EQUIVALENT, 0 ms] (25) IDP (26) IDPNonInfProof [SOUND, 197 ms] (27) IDP (28) IDependencyGraphProof [EQUIVALENT, 0 ms] (29) TRUE ---------------------------------------- (0) Obligation: ITRS problem: The following function symbols are pre-defined: <<< & ~ Bwand: (Integer, Integer) -> Integer >= ~ Ge: (Integer, Integer) -> Boolean | ~ Bwor: (Integer, Integer) -> Integer / ~ Div: (Integer, Integer) -> Integer != ~ Neq: (Integer, Integer) -> Boolean && ~ Land: (Boolean, Boolean) -> Boolean ! ~ Lnot: (Boolean) -> Boolean = ~ Eq: (Integer, Integer) -> Boolean <= ~ Le: (Integer, Integer) -> Boolean ^ ~ Bwxor: (Integer, Integer) -> Integer % ~ Mod: (Integer, Integer) -> Integer > ~ Gt: (Integer, Integer) -> Boolean + ~ Add: (Integer, Integer) -> Integer -1 ~ UnaryMinus: (Integer) -> Integer < ~ Lt: (Integer, Integer) -> Boolean || ~ Lor: (Boolean, Boolean) -> Boolean - ~ Sub: (Integer, Integer) -> Integer ~ ~ Bwnot: (Integer) -> Integer * ~ Mul: (Integer, Integer) -> Integer >>> The TRS R consists of the following rules: app(nil, zs) -> zs app(cons(x, ys), zs) -> cons(x, app(ys, zs)) split(x, e) -> pair(e, e) split(x, ins(y, zs)) -> Cond_split(x > y, x, ins(y, zs)) Cond_split(TRUE, x, ins(y, zs)) -> if_1(split(x, zs), x, y, zs) if_1(pair(zl, zh), x, y, zs) -> Cond_if_1(x > y, pair(zl, zh), x, y, zs) Cond_if_1(TRUE, pair(zl, zh), x, y, zs) -> pair(ins(y, zl), zh) split(x, ins(y, zs)) -> Cond_split1(y >= x, x, ins(y, zs)) Cond_split1(TRUE, x, ins(y, zs)) -> if_2(split(x, zs), x, y, zs) if_2(pair(zl, zh), x, y, zs) -> Cond_if_2(y >= x, pair(zl, zh), x, y, zs) Cond_if_2(TRUE, pair(zl, zh), x, y, zs) -> pair(zl, ins(y, zh)) qsort(e) -> nil qsort(ins(x, ys)) -> if_3(split(x, ys), x, ys) if_3(pair(yl, yh), x, ys) -> app(qsort(yl), cons(x, qsort(yh))) The set Q consists of the following terms: app(nil, x0) app(cons(x0, x1), x2) split(x0, e) split(x0, ins(x1, x2)) Cond_split(TRUE, x0, ins(x1, x2)) if_1(pair(x0, x1), x2, x3, x4) Cond_if_1(TRUE, pair(x0, x1), x2, x3, x4) Cond_split1(TRUE, x0, ins(x1, x2)) if_2(pair(x0, x1), x2, x3, x4) Cond_if_2(TRUE, pair(x0, x1), x2, x3, x4) qsort(e) qsort(ins(x0, x1)) if_3(pair(x0, x1), x2, x3) ----------------------------------------
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