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Derivational Complexity: TRS pair #487102864
details
property
value
status
complete
benchmark
63142.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n147.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
AProVE
configuration
rcdcRelativeAlsoLower
runtime (wallclock)
297.818 seconds
cpu usage
879.643
user time
870.658
system time
8.98492
max virtual memory
1.875102E7
max residence set size
1.5132944E7
stage attributes
key
value
starexec-result
WORST_CASE(?, O(n^1))
output
WORST_CASE(?, O(n^1)) proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty The Derivational Complexity (full) of the given DCpxTrs could be proven to be BOUNDS(1, n^1). (0) DCpxTrs (1) DerivationalComplexityToRuntimeComplexityProof [BOTH BOUNDS(ID, ID), 0 ms] (2) CpxRelTRS (3) SInnermostTerminationProof [BOTH CONCRETE BOUNDS(ID, ID), 40 ms] (4) CpxRelTRS (5) RelTrsToTrsProof [UPPER BOUND(ID), 0 ms] (6) CpxTRS (7) CpxTrsMatchBoundsProof [FINISHED, 89 ms] (8) BOUNDS(1, n^1) ---------------------------------------- (0) Obligation: The Derivational Complexity (full) of the given DCpxTrs could be proven to be BOUNDS(1, n^1). The TRS R consists of the following rules: 0(0(0(1(0(2(0(2(1(2(0(2(2(x1))))))))))))) -> 0(0(1(0(1(1(0(2(1(0(0(0(1(0(1(1(0(x1))))))))))))))))) 0(0(0(1(1(2(1(2(1(1(0(0(0(x1))))))))))))) -> 1(0(0(2(2(2(2(1(1(2(0(2(0(0(2(1(0(x1))))))))))))))))) 0(1(0(1(0(0(1(0(0(2(1(2(0(x1))))))))))))) -> 0(1(0(2(0(0(2(1(0(0(0(0(0(1(0(0(0(x1))))))))))))))))) 0(1(2(0(2(0(1(1(1(1(0(0(2(x1))))))))))))) -> 0(0(0(0(0(2(0(2(2(0(2(2(2(0(0(0(0(x1))))))))))))))))) 0(1(2(1(1(0(0(2(2(1(0(2(2(x1))))))))))))) -> 1(0(0(2(1(0(0(2(0(0(0(2(0(2(2(2(2(x1))))))))))))))))) 0(1(2(2(0(0(2(0(0(0(2(0(2(x1))))))))))))) -> 2(1(0(0(0(2(1(1(0(2(0(1(0(2(1(0(2(x1))))))))))))))))) 0(2(0(1(0(1(1(0(1(2(0(0(1(x1))))))))))))) -> 0(1(1(0(0(0(2(1(1(1(0(2(0(0(2(0(1(x1))))))))))))))))) 1(0(0(1(0(2(2(0(0(1(2(0(0(x1))))))))))))) -> 0(0(0(0(0(1(0(1(0(1(1(0(1(0(0(2(0(x1))))))))))))))))) 1(0(1(1(1(2(2(2(2(1(0(0(0(x1))))))))))))) -> 2(1(0(0(1(0(1(0(2(2(1(1(0(0(2(2(2(x1))))))))))))))))) 1(1(0(0(1(0(0(0(0(1(1(1(2(x1))))))))))))) -> 1(1(0(2(1(0(0(2(1(0(1(0(0(2(0(1(2(x1))))))))))))))))) 1(1(2(0(1(0(2(1(2(0(1(0(2(x1))))))))))))) -> 1(1(2(1(0(1(0(2(1(1(1(0(1(0(2(0(2(x1))))))))))))))))) 1(1(2(2(1(1(2(1(0(0(1(0(2(x1))))))))))))) -> 0(0(2(0(2(0(0(0(2(0(0(2(0(0(2(2(2(x1))))))))))))))))) 2(0(0(0(1(1(2(1(0(2(2(0(0(x1))))))))))))) -> 1(1(0(2(0(1(0(2(2(1(1(1(0(2(2(0(0(x1))))))))))))))))) 2(0(0(1(1(2(2(1(0(2(2(2(2(x1))))))))))))) -> 1(0(2(2(1(0(1(2(1(0(1(0(0(2(0(2(0(x1))))))))))))))))) 2(0(0(2(1(2(1(1(0(1(0(0(2(x1))))))))))))) -> 2(1(1(1(1(0(2(0(1(0(1(0(2(1(0(0(2(x1))))))))))))))))) 2(1(1(2(2(0(2(1(0(0(0(1(0(x1))))))))))))) -> 1(1(2(0(0(2(0(0(1(0(0(2(0(0(0(1(0(x1))))))))))))))))) 2(1(2(1(1(2(1(0(0(1(0(1(0(x1))))))))))))) -> 2(2(1(1(1(0(0(0(0(1(0(0(2(2(0(1(0(x1))))))))))))))))) 2(1(2(2(0(2(1(0(2(0(2(1(0(x1))))))))))))) -> 1(0(1(2(0(0(2(0(0(2(1(0(2(1(0(0(0(x1))))))))))))))))) 2(2(0(1(1(1(1(0(1(0(1(2(0(x1))))))))))))) -> 0(1(1(0(1(1(0(0(2(2(0(1(1(0(1(0(0(x1))))))))))))))))) S is empty. Rewrite Strategy: FULL ---------------------------------------- (1) DerivationalComplexityToRuntimeComplexityProof (BOTH BOUNDS(ID, ID)) The following rules have been added to S to convert the given derivational complexity problem to a runtime complexity problem: encArg(cons_0(x_1)) -> 0(encArg(x_1)) encArg(cons_1(x_1)) -> 1(encArg(x_1)) encArg(cons_2(x_1)) -> 2(encArg(x_1)) encode_0(x_1) -> 0(encArg(x_1)) encode_1(x_1) -> 1(encArg(x_1)) encode_2(x_1) -> 2(encArg(x_1)) ---------------------------------------- (2) Obligation: The Runtime Complexity (full) of the given CpxRelTRS could be proven to be BOUNDS(1, n^1). The TRS R consists of the following rules: 0(0(0(1(0(2(0(2(1(2(0(2(2(x1))))))))))))) -> 0(0(1(0(1(1(0(2(1(0(0(0(1(0(1(1(0(x1))))))))))))))))) 0(0(0(1(1(2(1(2(1(1(0(0(0(x1))))))))))))) -> 1(0(0(2(2(2(2(1(1(2(0(2(0(0(2(1(0(x1))))))))))))))))) 0(1(0(1(0(0(1(0(0(2(1(2(0(x1))))))))))))) -> 0(1(0(2(0(0(2(1(0(0(0(0(0(1(0(0(0(x1))))))))))))))))) 0(1(2(0(2(0(1(1(1(1(0(0(2(x1))))))))))))) -> 0(0(0(0(0(2(0(2(2(0(2(2(2(0(0(0(0(x1))))))))))))))))) 0(1(2(1(1(0(0(2(2(1(0(2(2(x1))))))))))))) -> 1(0(0(2(1(0(0(2(0(0(0(2(0(2(2(2(2(x1))))))))))))))))) 0(1(2(2(0(0(2(0(0(0(2(0(2(x1))))))))))))) -> 2(1(0(0(0(2(1(1(0(2(0(1(0(2(1(0(2(x1))))))))))))))))) 0(2(0(1(0(1(1(0(1(2(0(0(1(x1))))))))))))) -> 0(1(1(0(0(0(2(1(1(1(0(2(0(0(2(0(1(x1))))))))))))))))) 1(0(0(1(0(2(2(0(0(1(2(0(0(x1))))))))))))) -> 0(0(0(0(0(1(0(1(0(1(1(0(1(0(0(2(0(x1))))))))))))))))) 1(0(1(1(1(2(2(2(2(1(0(0(0(x1))))))))))))) -> 2(1(0(0(1(0(1(0(2(2(1(1(0(0(2(2(2(x1))))))))))))))))) 1(1(0(0(1(0(0(0(0(1(1(1(2(x1))))))))))))) -> 1(1(0(2(1(0(0(2(1(0(1(0(0(2(0(1(2(x1))))))))))))))))) 1(1(2(0(1(0(2(1(2(0(1(0(2(x1))))))))))))) -> 1(1(2(1(0(1(0(2(1(1(1(0(1(0(2(0(2(x1))))))))))))))))) 1(1(2(2(1(1(2(1(0(0(1(0(2(x1))))))))))))) -> 0(0(2(0(2(0(0(0(2(0(0(2(0(0(2(2(2(x1))))))))))))))))) 2(0(0(0(1(1(2(1(0(2(2(0(0(x1))))))))))))) -> 1(1(0(2(0(1(0(2(2(1(1(1(0(2(2(0(0(x1))))))))))))))))) 2(0(0(1(1(2(2(1(0(2(2(2(2(x1))))))))))))) -> 1(0(2(2(1(0(1(2(1(0(1(0(0(2(0(2(0(x1))))))))))))))))) 2(0(0(2(1(2(1(1(0(1(0(0(2(x1))))))))))))) -> 2(1(1(1(1(0(2(0(1(0(1(0(2(1(0(0(2(x1))))))))))))))))) 2(1(1(2(2(0(2(1(0(0(0(1(0(x1))))))))))))) -> 1(1(2(0(0(2(0(0(1(0(0(2(0(0(0(1(0(x1))))))))))))))))) 2(1(2(1(1(2(1(0(0(1(0(1(0(x1))))))))))))) -> 2(2(1(1(1(0(0(0(0(1(0(0(2(2(0(1(0(x1))))))))))))))))) 2(1(2(2(0(2(1(0(2(0(2(1(0(x1))))))))))))) -> 1(0(1(2(0(0(2(0(0(2(1(0(2(1(0(0(0(x1))))))))))))))))) 2(2(0(1(1(1(1(0(1(0(1(2(0(x1))))))))))))) -> 0(1(1(0(1(1(0(0(2(2(0(1(1(0(1(0(0(x1))))))))))))))))) The (relative) TRS S consists of the following rules: encArg(cons_0(x_1)) -> 0(encArg(x_1)) encArg(cons_1(x_1)) -> 1(encArg(x_1)) encArg(cons_2(x_1)) -> 2(encArg(x_1)) encode_0(x_1) -> 0(encArg(x_1)) encode_1(x_1) -> 1(encArg(x_1)) encode_2(x_1) -> 2(encArg(x_1))
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