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Derivational Complexity: TRS Innermost pair #487106862
details
property
value
status
complete
benchmark
97888.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n141.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
AProVE
configuration
rcdcRelativeAlsoLower
runtime (wallclock)
296.99 seconds
cpu usage
1063.75
user time
1060.7
system time
3.04714
max virtual memory
1.88207E7
max residence set size
6007892.0
stage attributes
key
value
starexec-result
KILLED
output
KILLED proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty The Derivational Complexity (innermost) of the given DCpxTrs could be proven to be BOUNDS(1, INF). (0) DCpxTrs (1) DerivationalComplexityToRuntimeComplexityProof [BOTH BOUNDS(ID, ID), 0 ms] (2) CpxRelTRS (3) SInnermostTerminationProof [BOTH CONCRETE BOUNDS(ID, ID), 45 ms] (4) CpxRelTRS (5) RelTrsToDecreasingLoopProblemProof [LOWER BOUND(ID), 0 ms] (6) TRS for Loop Detection (7) RenamingProof [BOTH BOUNDS(ID, ID), 0 ms] (8) CpxRelTRS (9) TypeInferenceProof [BOTH BOUNDS(ID, ID), 0 ms] (10) typed CpxTrs (11) OrderProof [LOWER BOUND(ID), 2 ms] (12) typed CpxTrs (13) RelTrsToTrsProof [UPPER BOUND(ID), 0 ms] (14) CpxTRS (15) NonCtorToCtorProof [UPPER BOUND(ID), 0 ms] (16) CpxRelTRS (17) RelTrsToWeightedTrsProof [BOTH BOUNDS(ID, ID), 0 ms] (18) CpxWeightedTrs (19) CpxWeightedTrsRenamingProof [BOTH BOUNDS(ID, ID), 85 ms] (20) CpxWeightedTrs (21) TypeInferenceProof [BOTH BOUNDS(ID, ID), 0 ms] (22) CpxTypedWeightedTrs (23) CompletionProof [UPPER BOUND(ID), 19 ms] (24) CpxTypedWeightedCompleteTrs (25) NarrowingProof [BOTH BOUNDS(ID, ID), 4577 ms] (26) CpxTypedWeightedCompleteTrs (27) CpxTypedWeightedTrsToRntsProof [UPPER BOUND(ID), 0 ms] (28) CpxRNTS (29) SimplificationProof [BOTH BOUNDS(ID, ID), 6 ms] (30) CpxRNTS (31) CompletionProof [UPPER BOUND(ID), 15 ms] (32) CpxTypedWeightedCompleteTrs (33) CpxTypedWeightedTrsToRntsProof [UPPER BOUND(ID), 10 ms] (34) CpxRNTS (35) CpxTrsToCdtProof [UPPER BOUND(ID), 19.0 s] (36) CdtProblem (37) CdtRhsSimplificationProcessorProof [BOTH BOUNDS(ID, ID), 1282 ms] (38) CdtProblem (39) CdtGraphSplitRhsProof [BOTH BOUNDS(ID, ID), 0 ms] (40) CdtProblem (41) CdtLeafRemovalProof [ComplexityIfPolyImplication, 0 ms] (42) CdtProblem (43) CdtUsableRulesProof [BOTH BOUNDS(ID, ID), 95.4 s] (44) CdtProblem (45) CdtNarrowingProof [BOTH BOUNDS(ID, ID), 26.2 s] (46) CdtProblem ---------------------------------------- (0) Obligation: The Derivational Complexity (innermost) of the given DCpxTrs could be proven to be BOUNDS(1, INF). The TRS R consists of the following rules: 0(0(0(1(0(0(1(2(1(2(2(2(0(2(2(0(1(2(0(1(1(1(1(x1))))))))))))))))))))))) -> 1(2(0(2(2(2(1(2(1(2(0(2(0(2(2(1(2(2(1(1(1(1(2(0(1(0(1(x1))))))))))))))))))))))))))) 0(0(0(2(1(1(2(1(2(2(0(2(0(2(2(2(1(1(1(0(2(2(1(x1))))))))))))))))))))))) -> 2(1(2(2(0(2(0(1(2(2(1(2(1(0(2(2(0(2(2(2(0(0(2(2(0(2(1(x1))))))))))))))))))))))))))) 0(0(1(1(1(0(2(2(2(0(2(2(1(1(2(0(0(1(2(0(1(1(0(x1))))))))))))))))))))))) -> 0(0(1(2(2(1(1(2(2(2(2(0(1(1(0(1(2(2(0(1(0(1(2(1(0(2(2(x1))))))))))))))))))))))))))) 0(0(1(1(2(0(1(2(2(1(1(0(1(1(2(2(2(0(0(0(2(2(2(x1))))))))))))))))))))))) -> 2(2(2(0(1(1(0(0(2(0(2(2(0(0(0(1(2(1(0(2(2(1(2(2(2(2(2(x1))))))))))))))))))))))))))) 0(0(1(2(2(1(2(0(0(2(2(0(2(1(1(1(0(2(1(0(2(2(0(x1))))))))))))))))))))))) -> 0(1(1(1(1(2(0(1(1(2(1(1(2(1(2(2(1(2(2(2(0(2(1(2(1(2(2(x1))))))))))))))))))))))))))) 0(0(1(2(2(1(2(0(2(2(2(1(1(2(0(0(0(1(0(0(2(2(0(x1))))))))))))))))))))))) -> 0(2(2(2(1(0(0(2(0(2(1(2(1(2(1(2(2(1(2(2(1(1(2(0(1(2(2(x1))))))))))))))))))))))))))) 0(0(1(2(2(2(0(2(0(2(0(2(0(0(0(0(1(1(2(1(2(2(2(x1))))))))))))))))))))))) -> 1(2(1(1(0(2(0(2(1(2(1(2(0(1(1(2(2(2(1(1(2(0(2(2(1(2(2(x1))))))))))))))))))))))))))) 0(0(2(2(0(1(1(0(2(0(1(0(1(2(2(1(0(2(2(2(0(2(2(x1))))))))))))))))))))))) -> 0(0(2(2(1(2(0(1(0(2(2(1(2(1(2(2(0(1(2(2(0(2(1(2(2(0(2(x1))))))))))))))))))))))))))) 0(0(2(2(2(1(2(1(1(1(2(1(1(2(1(0(0(2(0(2(0(2(2(x1))))))))))))))))))))))) -> 2(1(2(0(2(2(2(0(1(2(2(2(1(0(1(2(2(2(0(0(0(2(0(0(0(1(2(x1))))))))))))))))))))))))))) 0(0(2(2(2(2(2(0(2(0(1(1(0(1(2(2(2(1(1(1(1(0(1(x1))))))))))))))))))))))) -> 2(1(2(2(2(2(0(1(2(1(2(0(1(1(1(1(2(0(1(0(0(0(0(2(2(2(2(x1))))))))))))))))))))))))))) 0(1(0(0(2(0(2(0(1(0(2(0(0(1(2(2(0(1(2(0(2(1(2(x1))))))))))))))))))))))) -> 0(1(2(1(1(1(2(1(2(1(2(1(0(2(2(2(2(1(0(2(2(2(0(1(1(2(2(x1))))))))))))))))))))))))))) 0(1(0(1(2(0(0(0(2(1(1(2(2(1(1(2(0(2(1(2(0(2(2(x1))))))))))))))))))))))) -> 2(2(0(1(2(2(1(2(1(2(0(0(1(0(1(0(1(2(0(1(0(1(1(2(1(2(2(x1))))))))))))))))))))))))))) 0(1(1(1(0(2(2(1(2(2(2(2(0(0(2(0(2(2(0(2(0(1(0(x1))))))))))))))))))))))) -> 2(2(2(2(0(2(2(2(2(1(0(0(0(1(2(2(2(2(0(1(2(1(2(0(1(2(0(x1))))))))))))))))))))))))))) 0(1(1(1(1(2(0(1(2(0(2(2(0(0(0(1(0(2(2(1(2(0(2(x1))))))))))))))))))))))) -> 0(0(1(2(2(0(1(1(1(2(2(0(2(1(2(2(0(2(1(0(1(2(0(2(1(2(2(x1))))))))))))))))))))))))))) 0(1(1(2(2(0(0(0(2(0(0(2(1(2(1(2(0(2(2(1(2(1(1(x1))))))))))))))))))))))) -> 2(2(1(2(1(0(0(2(2(2(2(1(0(2(2(1(2(2(2(2(0(0(2(2(2(2(0(x1))))))))))))))))))))))))))) 0(1(2(0(1(1(1(1(1(0(2(1(2(2(1(2(0(2(2(1(2(0(2(x1))))))))))))))))))))))) -> 1(1(2(0(1(2(2(2(2(2(2(0(2(2(2(2(2(1(2(1(0(2(0(1(1(2(2(x1))))))))))))))))))))))))))) 0(1(2(0(1(2(0(1(1(2(2(0(1(2(2(1(1(1(2(0(0(0(2(x1))))))))))))))))))))))) -> 2(0(0(2(2(1(1(2(2(2(0(1(2(2(0(2(2(1(2(1(2(0(0(0(1(2(2(x1))))))))))))))))))))))))))) 0(1(2(0(2(1(1(2(0(1(0(2(2(0(0(2(1(0(0(2(1(2(1(x1))))))))))))))))))))))) -> 2(2(0(1(2(2(2(1(0(0(2(1(0(2(2(1(1(0(2(2(2(2(2(2(0(2(1(x1))))))))))))))))))))))))))) 0(1(2(1(0(0(0(2(2(2(2(0(2(0(0(1(0(1(0(2(2(1(2(x1))))))))))))))))))))))) -> 2(1(1(1(2(2(1(2(2(2(0(1(1(2(1(2(2(1(0(2(1(2(2(0(0(1(2(x1))))))))))))))))))))))))))) 0(1(2(1(0(2(2(2(1(2(0(0(0(2(1(1(1(1(0(2(1(2(2(x1))))))))))))))))))))))) -> 0(0(1(1(2(2(1(2(2(1(2(1(0(2(2(2(0(2(0(2(2(1(2(1(0(1(2(x1))))))))))))))))))))))))))) 0(1(2(1(1(2(2(2(1(2(1(2(0(2(0(1(2(0(1(0(1(0(0(x1))))))))))))))))))))))) -> 0(1(2(0(1(1(1(2(0(1(0(1(2(2(1(2(1(2(1(1(1(2(2(2(2(1(2(x1))))))))))))))))))))))))))) 0(1(2(2(0(0(0(0(0(2(2(1(2(2(2(2(1(1(1(2(0(0(1(x1))))))))))))))))))))))) -> 2(1(2(1(2(1(2(1(0(2(1(2(1(2(0(0(1(2(2(1(2(2(2(0(2(2(2(x1))))))))))))))))))))))))))) 0(2(0(0(0(2(2(1(2(1(1(2(1(1(1(1(1(1(1(2(0(2(2(x1))))))))))))))))))))))) -> 0(0(0(1(2(2(2(1(2(0(2(1(2(2(2(1(2(1(1(2(1(0(2(2(0(0(2(x1))))))))))))))))))))))))))) 0(2(0(2(1(2(2(1(1(0(0(2(2(0(1(1(0(2(0(2(0(1(2(x1))))))))))))))))))))))) -> 2(2(0(0(1(2(0(0(1(0(2(1(1(2(0(1(2(2(1(2(2(0(2(2(0(2(2(x1))))))))))))))))))))))))))) 0(2(1(0(0(0(0(0(0(0(2(0(0(1(2(2(2(2(0(1(2(1(2(x1))))))))))))))))))))))) -> 1(2(1(2(1(2(1(2(1(1(2(1(2(0(0(2(1(2(2(0(2(0(2(1(0(0(2(x1))))))))))))))))))))))))))) 0(2(1(0(2(0(0(2(1(2(1(0(2(0(0(2(1(2(1(1(2(1(1(x1))))))))))))))))))))))) -> 1(1(2(2(2(2(1(2(2(2(2(1(1(0(0(1(1(2(0(1(2(1(2(0(1(2(0(x1))))))))))))))))))))))))))) 0(2(1(1(0(2(2(0(1(1(0(0(2(1(0(1(2(1(2(1(2(2(2(x1))))))))))))))))))))))) -> 2(2(2(2(2(2(1(2(2(2(0(2(1(2(2(0(1(0(1(2(0(0(2(1(1(0(2(x1))))))))))))))))))))))))))) 0(2(1(1(2(2(0(0(0(2(0(0(2(1(1(2(1(2(0(0(1(2(2(x1))))))))))))))))))))))) -> 2(2(1(1(1(0(2(2(2(1(2(1(0(2(0(0(0(2(1(2(2(2(1(2(2(2(2(x1))))))))))))))))))))))))))) 0(2(2(0(2(1(2(0(1(1(2(0(0(0(0(2(2(2(2(0(0(2(0(x1))))))))))))))))))))))) -> 0(2(0(0(2(2(2(2(2(0(2(0(1(1(1(2(2(2(1(2(0(0(0(2(2(2(0(x1))))))))))))))))))))))))))) 0(2(2(1(0(0(1(2(2(0(1(2(0(2(1(0(1(2(0(2(0(0(2(x1))))))))))))))))))))))) -> 0(2(1(1(2(2(1(0(1(2(1(2(1(2(2(1(2(1(2(0(0(1(0(2(0(2(2(x1))))))))))))))))))))))))))) 0(2(2(1(2(0(1(1(2(1(1(1(0(0(0(0(2(0(1(2(0(1(1(x1))))))))))))))))))))))) -> 0(2(2(1(2(0(1(2(1(2(0(0(0(1(2(2(1(0(1(0(1(1(2(2(0(1(1(x1))))))))))))))))))))))))))) 0(2(2(2(0(1(2(2(2(2(1(0(0(0(2(2(1(1(1(1(1(0(2(x1))))))))))))))))))))))) -> 1(2(0(1(1(2(1(2(1(2(0(2(2(0(1(2(0(2(2(1(2(2(0(1(1(2(2(x1))))))))))))))))))))))))))) 0(2(2(2(1(0(1(1(0(2(2(0(2(1(0(1(0(2(2(2(2(2(2(x1))))))))))))))))))))))) -> 2(1(2(2(2(1(0(2(1(2(2(1(2(0(1(2(1(1(0(2(2(1(1(2(1(0(2(x1))))))))))))))))))))))))))) 0(2(2(2(2(0(0(1(0(1(0(1(2(0(2(0(0(2(1(2(0(2(1(x1))))))))))))))))))))))) -> 1(2(2(0(1(2(2(0(1(2(0(1(1(2(2(2(0(1(2(2(2(2(1(2(1(1(2(x1))))))))))))))))))))))))))) 1(0(1(0(0(0(0(1(2(2(2(1(1(2(2(0(1(2(1(1(2(1(2(x1))))))))))))))))))))))) -> 2(2(2(0(2(2(2(2(0(0(0(2(2(2(2(2(0(2(1(1(1(1(2(0(1(2(2(x1)))))))))))))))))))))))))))
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