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Runtime Complexity: TRS pair #487110734
details
property
value
status
complete
benchmark
append-hard.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n150.star.cs.uiowa.edu
space
CiME_04
run statistics
property
value
solver
AProVE
configuration
complexity
runtime (wallclock)
291.633 seconds
cpu usage
302.261
user time
300.287
system time
1.97379
max virtual memory
1.828148E7
max residence set size
5297080.0
stage attributes
key
value
starexec-result
WORST_CASE(Omega(n^1), ?)
output
WORST_CASE(Omega(n^1), ?) proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, INF). (0) CpxTRS (1) RenamingProof [BOTH BOUNDS(ID, ID), 0 ms] (2) CpxTRS (3) TypeInferenceProof [BOTH BOUNDS(ID, ID), 0 ms] (4) typed CpxTrs (5) OrderProof [LOWER BOUND(ID), 0 ms] (6) typed CpxTrs (7) RewriteLemmaProof [LOWER BOUND(ID), 242 ms] (8) proven lower bound (9) LowerBoundPropagationProof [FINISHED, 0 ms] (10) BOUNDS(n^1, INF) ---------------------------------------- (0) Obligation: The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, INF). The TRS R consists of the following rules: is_empty(nil) -> true is_empty(cons(x, l)) -> false hd(cons(x, l)) -> x tl(cons(x, l)) -> l append(l1, l2) -> ifappend(l1, l2, is_empty(l1)) ifappend(l1, l2, true) -> l2 ifappend(l1, l2, false) -> cons(hd(l1), append(tl(l1), l2)) S is empty. Rewrite Strategy: FULL ---------------------------------------- (1) RenamingProof (BOTH BOUNDS(ID, ID)) Renamed function symbols to avoid clashes with predefined symbol. ---------------------------------------- (2) Obligation: The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, INF). The TRS R consists of the following rules: is_empty(nil) -> true is_empty(cons(x, l)) -> false hd(cons(x, l)) -> x tl(cons(x, l)) -> l append(l1, l2) -> ifappend(l1, l2, is_empty(l1)) ifappend(l1, l2, true) -> l2 ifappend(l1, l2, false) -> cons(hd(l1), append(tl(l1), l2)) S is empty. Rewrite Strategy: FULL ---------------------------------------- (3) TypeInferenceProof (BOTH BOUNDS(ID, ID)) Infered types. ---------------------------------------- (4) Obligation: TRS: Rules: is_empty(nil) -> true is_empty(cons(x, l)) -> false hd(cons(x, l)) -> x tl(cons(x, l)) -> l append(l1, l2) -> ifappend(l1, l2, is_empty(l1)) ifappend(l1, l2, true) -> l2 ifappend(l1, l2, false) -> cons(hd(l1), append(tl(l1), l2)) Types: is_empty :: nil:cons -> true:false nil :: nil:cons true :: true:false cons :: hd -> nil:cons -> nil:cons false :: true:false hd :: nil:cons -> hd tl :: nil:cons -> nil:cons append :: nil:cons -> nil:cons -> nil:cons ifappend :: nil:cons -> nil:cons -> true:false -> nil:cons hole_true:false1_0 :: true:false hole_nil:cons2_0 :: nil:cons hole_hd3_0 :: hd gen_nil:cons4_0 :: Nat -> nil:cons ---------------------------------------- (5) OrderProof (LOWER BOUND(ID)) Heuristically decided to analyse the following defined symbols: append
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