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SRS Standard pair #487511415
details
property
value
status
complete
benchmark
x05.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n108.star.cs.uiowa.edu
space
Secret_07_SRS
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
42.2348840237 seconds
cpu usage
167.532266401
max memory
1.283485696E9
stage attributes
key
value
output-size
5082
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: a(a(x1)) -> b(b(x1)) c(c(b(x1))) -> d(c(a(x1))) a(x1) -> d(c(c(x1))) c(d(x1)) -> b(c(x1)) Proof: String Reversal Processor: a(a(x1)) -> b(b(x1)) b(c(c(x1))) -> a(c(d(x1))) a(x1) -> c(c(d(x1))) d(c(x1)) -> c(b(x1)) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [0] [b](x0) = [0 1 1]x0 + [1] [0 1 0] [1], [1 0 0] [d](x0) = [0 0 0]x0 [0 0 0] , [1 1 0] [0] [a](x0) = [0 1 1]x0 + [1] [0 1 0] [1], [1 0 0] [c](x0) = [0 0 0]x0 [0 0 0] orientation: [1 2 1] [1] [1 0 0] [0] a(a(x1)) = [0 2 1]x1 + [3] >= [0 2 1]x1 + [3] = b(b(x1)) [0 1 1] [2] [0 1 1] [2] [1 0 0] [0] [1 0 0] [0] b(c(c(x1))) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = a(c(d(x1))) [0 0 0] [1] [0 0 0] [1] [1 1 0] [0] [1 0 0] a(x1) = [0 1 1]x1 + [1] >= [0 0 0]x1 = c(c(d(x1))) [0 1 0] [1] [0 0 0] [1 0 0] [1 0 0] d(c(x1)) = [0 0 0]x1 >= [0 0 0]x1 = c(b(x1)) [0 0 0] [0 0 0] problem: b(c(c(x1))) -> a(c(d(x1))) a(x1) -> c(c(d(x1))) d(c(x1)) -> c(b(x1)) DP Processor: DPs: b#(c(c(x1))) -> d#(x1) b#(c(c(x1))) -> a#(c(d(x1))) a#(x1) -> d#(x1) d#(c(x1)) -> b#(x1) TRS: b(c(c(x1))) -> a(c(d(x1))) a(x1) -> c(c(d(x1))) d(c(x1)) -> c(b(x1)) TDG Processor: DPs: b#(c(c(x1))) -> d#(x1) b#(c(c(x1))) -> a#(c(d(x1))) a#(x1) -> d#(x1) d#(c(x1)) -> b#(x1) TRS: b(c(c(x1))) -> a(c(d(x1))) a(x1) -> c(c(d(x1))) d(c(x1)) -> c(b(x1)) graph: a#(x1) -> d#(x1) -> d#(c(x1)) -> b#(x1) d#(c(x1)) -> b#(x1) -> b#(c(c(x1))) -> a#(c(d(x1))) d#(c(x1)) -> b#(x1) -> b#(c(c(x1))) -> d#(x1) b#(c(c(x1))) -> a#(c(d(x1))) -> a#(x1) -> d#(x1) b#(c(c(x1))) -> d#(x1) -> d#(c(x1)) -> b#(x1) Matrix Interpretation Processor: dim=4 interpretation: [b#](x0) = [0 0 1 0]x0, [0 0 1 0] [0 0 1 0] [b](x0) = [0 0 1 0]x0 [0 0 1 0] , [0 1 0 0] [0] [0 1 0 0] [0] [d](x0) = [0 1 0 0]x0 + [0] [0 1 0 0] [1], [d#](x0) = [0 1 0 0]x0,
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