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SRS Standard pair #487511471
details
property
value
status
complete
benchmark
x03.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n185.star.cs.uiowa.edu
space
Secret_07_SRS
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
4.24772405624 seconds
cpu usage
13.887027168
max memory
1.721094144E9
stage attributes
key
value
output-size
5083
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) QTRSRRRProof [EQUIVALENT, 19 ms] (4) QTRS (5) DependencyPairsProof [EQUIVALENT, 7 ms] (6) QDP (7) MRRProof [EQUIVALENT, 27 ms] (8) QDP (9) QDPOrderProof [EQUIVALENT, 72 ms] (10) QDP (11) DependencyGraphProof [EQUIVALENT, 0 ms] (12) TRUE ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(c(x1))) -> b(x1) c(b(b(x1))) -> a(x1) c(x1) -> b(x1) a(a(x1)) -> c(b(a(c(x1)))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: c(b(a(x1))) -> b(x1) b(b(c(x1))) -> a(x1) c(x1) -> b(x1) a(a(x1)) -> c(a(b(c(x1)))) Q is empty. ---------------------------------------- (3) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(a(x_1)) = 3 + x_1 POL(b(x_1)) = 1 + x_1 POL(c(x_1)) = 1 + x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: c(b(a(x1))) -> b(x1) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: b(b(c(x1))) -> a(x1) c(x1) -> b(x1) a(a(x1)) -> c(a(b(c(x1)))) Q is empty. ---------------------------------------- (5) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (6) Obligation: Q DP problem: The TRS P consists of the following rules:
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