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SRS Standard pair #487511729
details
property
value
status
complete
benchmark
07-oppelt08.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n128.star.cs.uiowa.edu
space
Mixed_SRS
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
2.03215789795 seconds
cpu usage
4.714567218
max memory
3.87428352E8
stage attributes
key
value
output-size
1510
starexec-result
NO
output
/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 128 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: R(b(x1)) -> b(R(x1)) R(c(x1)) -> L(c(x1)) b(L(x1)) -> L(b(x1)) a(L(x1)) -> a(b(R(x1))) Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "a (b)^k L c -> a (b)^k+1 L c" a (b)^k L c -> a (b)^k+1 L c by Overlap u with r (ol3)"a (b)^k L -> a (b)^k+1 R by Equivalent"a (b)^k L -> a b (b)^k R by Overlapping Derivationstructures"a (b)^k L -> a b R (b)^k by Overlap u with l (ol4)"(b)^k L -> L (b)^k by Selfoverlapping OC am1"b L -> L b by original rule (OC 1)"""a L -> a b R by original rule (OC 1)"""R (b)^k -> (b)^k R by Selfoverlapping OC am2"R b -> b R by original rule (OC 1)"""""R c -> L c by original rule (OC 1)" ---------------------------------------- (2) NO
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