SRS Standard pair #487512483

details

property	value
status	complete
benchmark	size-12-alpha-3-num-560.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n191.star.cs.uiowa.edu
space	Waldmann_07_size12

run statistics

property	value
solver	ttt2-1.20
configuration	ttt2
runtime (wallclock)	41.4867548943 seconds
cpu usage	164.403685737
max memory	1.155579904E9

stage attributes

key	value
output-size	2118
starexec-result	YES

output

/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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YES

Problem:
 a(b(x1)) -> x1
 a(c(x1)) -> c(c(x1))
 b(c(x1)) -> a(a(b(b(x1))))

Proof:
 DP Processor:
  DPs:
   b#(c(x1)) -> b#(x1)
   b#(c(x1)) -> b#(b(x1))
   b#(c(x1)) -> a#(b(b(x1)))
   b#(c(x1)) -> a#(a(b(b(x1))))
  TRS:
   a(b(x1)) -> x1
   a(c(x1)) -> c(c(x1))
   b(c(x1)) -> a(a(b(b(x1))))
  TDG Processor:
   DPs:
    b#(c(x1)) -> b#(x1)
    b#(c(x1)) -> b#(b(x1))
    b#(c(x1)) -> a#(b(b(x1)))
    b#(c(x1)) -> a#(a(b(b(x1))))
   TRS:
    a(b(x1)) -> x1
    a(c(x1)) -> c(c(x1))
    b(c(x1)) -> a(a(b(b(x1))))
   graph:
    b#(c(x1)) -> b#(b(x1)) -> b#(c(x1)) -> a#(a(b(b(x1))))
    b#(c(x1)) -> b#(b(x1)) -> b#(c(x1)) -> a#(b(b(x1)))
    b#(c(x1)) -> b#(b(x1)) -> b#(c(x1)) -> b#(b(x1))
    b#(c(x1)) -> b#(b(x1)) -> b#(c(x1)) -> b#(x1)
    b#(c(x1)) -> b#(x1) -> b#(c(x1)) -> a#(a(b(b(x1))))
    b#(c(x1)) -> b#(x1) -> b#(c(x1)) -> a#(b(b(x1)))
    b#(c(x1)) -> b#(x1) -> b#(c(x1)) -> b#(b(x1))
    b#(c(x1)) -> b#(x1) -> b#(c(x1)) -> b#(x1)
   SCC Processor:
    #sccs: 1
    #rules: 2
    #arcs: 8/16
    DPs:
     b#(c(x1)) -> b#(b(x1))
     b#(c(x1)) -> b#(x1)
    TRS:
     a(b(x1)) -> x1
     a(c(x1)) -> c(c(x1))
     b(c(x1)) -> a(a(b(b(x1))))
    Arctic Interpretation Processor:
     dimension: 1
     usable rules:
      a(b(x1)) -> x1
      a(c(x1)) -> c(c(x1))
      b(c(x1)) -> a(a(b(b(x1))))
     interpretation:
      [b#](x0) = 6x0 + 8,
      
      [a](x0) = 3x0 + 4,
      
      [b](x0) = -3x0 + 0,
      
      [c](x0) = 3x0 + 10
     orientation:
      b#(c(x1)) = 9x1 + 16 >= 3x1 + 8 = b#(b(x1))
      
      b#(c(x1)) = 9x1 + 16 >= 6x1 + 8 = b#(x1)
      
      a(b(x1)) = x1 + 4 >= x1 = x1
      
      a(c(x1)) = 6x1 + 13 >= 6x1 + 13 = c(c(x1))
      
      b(c(x1)) = x1 + 7 >= x1 + 7 = a(a(b(b(x1))))
     problem:
      DPs:
       
      TRS:
       a(b(x1)) -> x1
       a(c(x1)) -> c(c(x1))
       b(c(x1)) -> a(a(b(b(x1))))
     Qed

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