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SRS Standard pair #487514203
details
property
value
status
complete
benchmark
213537.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n094.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
muterm 6.0.3
configuration
default
runtime (wallclock)
21.7421500683 seconds
cpu usage
21.450679389
max memory
4.9270784E7
stage attributes
key
value
output-size
521988
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR v_NonEmpty:S x1:S) (RULES 0(1(0(0(x1:S)))) -> 2(0(2(0(0(1(x1:S)))))) 1(0(0(1(x1:S)))) -> 1(0(3(0(1(x1:S))))) 1(0(0(4(x1:S)))) -> 1(4(0(2(0(x1:S))))) 1(0(0(4(x1:S)))) -> 1(4(0(3(2(0(x1:S)))))) 1(0(1(0(x1:S)))) -> 1(3(0(0(3(1(x1:S)))))) 1(0(1(4(5(x1:S))))) -> 1(3(1(5(4(0(x1:S)))))) 1(0(1(4(x1:S)))) -> 1(0(3(1(2(4(x1:S)))))) 1(0(1(5(x1:S)))) -> 1(0(2(1(5(x1:S))))) 1(0(4(0(4(x1:S))))) -> 1(0(4(3(4(0(x1:S)))))) 1(0(4(1(x1:S)))) -> 1(0(3(4(1(x1:S))))) 1(0(5(0(x1:S)))) -> 1(2(5(2(0(0(x1:S)))))) 1(1(1(0(0(x1:S))))) -> 1(1(0(0(3(1(x1:S)))))) 1(1(4(5(0(x1:S))))) -> 1(1(3(4(0(5(x1:S)))))) 1(4(1(0(x1:S)))) -> 1(4(0(2(1(x1:S))))) 1(4(1(0(x1:S)))) -> 1(4(0(3(1(x1:S))))) 1(4(5(0(0(x1:S))))) -> 4(0(5(0(2(1(x1:S)))))) 1(4(5(0(x1:S)))) -> 4(0(2(1(2(5(x1:S)))))) 1(4(5(2(0(x1:S))))) -> 0(3(1(2(5(4(x1:S)))))) 1(5(0(1(x1:S)))) -> 0(1(3(1(3(5(x1:S)))))) 1(5(0(1(x1:S)))) -> 1(5(0(3(1(3(x1:S)))))) 1(5(0(4(5(x1:S))))) -> 3(4(0(5(1(5(x1:S)))))) 1(2(0(4(x1:S)))) -> 1(3(4(2(0(x1:S))))) 1(2(0(5(0(x1:S))))) -> 5(2(1(0(2(0(x1:S)))))) 1(3(0(4(x1:S)))) -> 1(3(4(2(0(x1:S))))) 4(1(0(0(1(x1:S))))) -> 1(0(4(0(3(1(x1:S)))))) 4(1(0(0(x1:S)))) -> 0(2(4(2(0(1(x1:S)))))) 4(1(0(0(x1:S)))) -> 0(3(4(3(0(1(x1:S)))))) 4(1(0(5(x1:S)))) -> 4(0(2(1(5(x1:S))))) 4(1(5(3(1(x1:S))))) -> 2(1(5(4(3(1(x1:S)))))) 4(1(2(0(0(x1:S))))) -> 4(2(0(0(2(1(x1:S)))))) 4(1(2(0(x1:S)))) -> 3(0(2(1(3(4(x1:S)))))) 4(1(3(0(5(x1:S))))) -> 3(2(4(0(1(5(x1:S)))))) 4(4(1(0(1(x1:S))))) -> 1(3(4(4(0(1(x1:S)))))) 4(5(0(0(x1:S)))) -> 3(0(4(0(5(x1:S))))) 4(5(0(1(0(x1:S))))) -> 4(0(0(5(3(1(x1:S)))))) 4(5(1(1(0(x1:S))))) -> 1(1(3(4(0(5(x1:S)))))) 4(5(1(1(0(x1:S))))) -> 4(0(2(1(5(1(x1:S)))))) 4(5(1(5(1(x1:S))))) -> 4(1(5(5(3(1(x1:S)))))) 4(5(5(0(4(x1:S))))) -> 5(4(0(5(4(2(x1:S)))))) 5(0(0(4(1(x1:S))))) -> 5(4(0(3(0(1(x1:S)))))) 5(0(0(4(5(x1:S))))) -> 0(3(4(0(5(5(x1:S)))))) 5(0(0(4(5(x1:S))))) -> 4(0(0(3(5(5(x1:S)))))) 5(0(0(4(x1:S)))) -> 5(4(0(2(0(x1:S))))) 5(0(1(4(x1:S)))) -> 1(5(4(3(0(x1:S))))) 5(0(4(1(0(x1:S))))) -> 5(0(4(0(3(1(x1:S)))))) 5(1(5(0(1(x1:S))))) -> 5(0(3(5(1(1(x1:S)))))) 5(4(1(1(0(x1:S))))) -> 1(2(4(0(1(5(x1:S)))))) 5(4(1(5(x1:S)))) -> 4(3(1(5(5(x1:S))))) 5(4(5(1(0(x1:S))))) -> 5(5(1(3(4(0(x1:S)))))) 5(5(2(0(4(x1:S))))) -> 5(5(3(4(2(0(x1:S)))))) ) Problem 1: Dependency Pairs Processor: -> Pairs: 0#(1(0(0(x1:S)))) -> 0#(0(1(x1:S))) 0#(1(0(0(x1:S)))) -> 0#(1(x1:S)) 0#(1(0(0(x1:S)))) -> 0#(2(0(0(1(x1:S))))) 0#(1(0(0(x1:S)))) -> 1#(x1:S) 1#(0(0(1(x1:S)))) -> 0#(3(0(1(x1:S)))) 1#(0(0(1(x1:S)))) -> 1#(0(3(0(1(x1:S))))) 1#(0(0(4(x1:S)))) -> 0#(2(0(x1:S))) 1#(0(0(4(x1:S)))) -> 0#(3(2(0(x1:S)))) 1#(0(0(4(x1:S)))) -> 0#(x1:S) 1#(0(0(4(x1:S)))) -> 1#(4(0(2(0(x1:S))))) 1#(0(0(4(x1:S)))) -> 1#(4(0(3(2(0(x1:S)))))) 1#(0(0(4(x1:S)))) -> 4#(0(2(0(x1:S)))) 1#(0(0(4(x1:S)))) -> 4#(0(3(2(0(x1:S))))) 1#(0(1(0(x1:S)))) -> 0#(0(3(1(x1:S)))) 1#(0(1(0(x1:S)))) -> 0#(3(1(x1:S))) 1#(0(1(0(x1:S)))) -> 1#(3(0(0(3(1(x1:S)))))) 1#(0(1(0(x1:S)))) -> 1#(x1:S) 1#(0(1(4(5(x1:S))))) -> 0#(x1:S) 1#(0(1(4(5(x1:S))))) -> 1#(5(4(0(x1:S)))) 1#(0(1(4(5(x1:S))))) -> 1#(3(1(5(4(0(x1:S)))))) 1#(0(1(4(5(x1:S))))) -> 4#(0(x1:S)) 1#(0(1(4(5(x1:S))))) -> 5#(4(0(x1:S))) 1#(0(1(4(x1:S)))) -> 0#(3(1(2(4(x1:S))))) 1#(0(1(4(x1:S)))) -> 1#(0(3(1(2(4(x1:S)))))) 1#(0(1(4(x1:S)))) -> 1#(2(4(x1:S))) 1#(0(1(5(x1:S)))) -> 0#(2(1(5(x1:S)))) 1#(0(1(5(x1:S)))) -> 1#(0(2(1(5(x1:S))))) 1#(0(4(0(4(x1:S))))) -> 0#(4(3(4(0(x1:S))))) 1#(0(4(0(4(x1:S))))) -> 0#(x1:S) 1#(0(4(0(4(x1:S))))) -> 1#(0(4(3(4(0(x1:S)))))) 1#(0(4(0(4(x1:S))))) -> 4#(0(x1:S)) 1#(0(4(0(4(x1:S))))) -> 4#(3(4(0(x1:S))))
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