details

property	value
status	complete
benchmark	231149.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n014.star.cs.uiowa.edu
space	ICFP_2010

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	2.81068706512 seconds
cpu usage	7.586026568
max memory	8.75122688E8

stage attributes

key	value
output-size	8258
starexec-result	YES

output

/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) QTRSRRRProof [EQUIVALENT, 75 ms] (4) QTRS (5) AAECC Innermost [EQUIVALENT, 4 ms] (6) QTRS (7) DependencyPairsProof [EQUIVALENT, 9 ms] (8) QDP (9) DependencyGraphProof [EQUIVALENT, 0 ms] (10) TRUE ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 0(x1) -> 1(x1) 0(0(x1)) -> 0(x1) 3(4(5(x1))) -> 4(3(5(x1))) 2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(x1))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) -> 1(0(0(0(1(1(0(0(0(0(1(0(0(0(1(1(0(0(0(1(1(0(0(1(1(1(1(0(0(1(1(1(1(1(1(0(1(1(1(1(0(0(1(1(0(0(0(0(1(1(1(1(0(0(0(1(1(1(0(1(1(0(1(1(0(0(1(0(1(1(1(1(1(0(1(1(1(0(0(0(1(0(0(0(1(1(0(1(1(1(0(0(1(0(0(0(0(0(0(0(1(0(1(0(0(1(0(1(0(0(1(0(1(1(1(1(0(0(0(0(0(1(0(1(0(0(1(0(1(1(0(1(0(0(1(0(1(0(1(0(1(1(0(1(x1)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) 1(0(1(1(1(0(0(1(0(0(0(1(0(1(1(0(1(1(1(0(1(0(0(0(0(1(1(1(0(0(1(0(0(1(1(0(1(0(0(1(1(1(1(0(1(1(0(1(1(0(1(1(0(1(0(1(1(0(1(0(1(1(0(0(1(1(1(0(0(0(1(0(1(1(1(0(0(0(1(0(1(0(1(0(0(0(1(0(1(0(1(0(1(0(1(1(0(0(1(1(1(1(1(1(0(0(0(0(0(0(0(1(0(0(0(0(1(1(0(1(0(0(1(0(0(1(0(0(1(1(0(0(1(1(1(0(1(0(1(1(1(1(0(1(0(0(0(0(x1)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) -> 2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(x1))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 0(x1) -> 1(x1) 0(0(x1)) -> 0(x1) 5(4(3(x1))) -> 5(3(4(x1))) 2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(x1))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) -> 1(0(1(1(0(1(0(1(0(1(0(0(1(0(1(1(0(1(0(0(1(0(1(0(0(0(0(0(1(1(1(1(0(1(0(0(1(0(1(0(0(1(0(1(0(0(0(0(0(0(0(1(0(0(1(1(1(0(1(1(0(0(0(1(0(0(0(1(1(1(0(1(1(1(1(1(0(1(0(0(1(1(0(1(1(0(1(1(1(0(0(0(1(1(1(1(0(0(0(0(1(1(0(0(1(1(1(1(0(1(1(1(1(1(1(0(0(1(1(1(1(0(0(1(1(0(0(0(1(1(0(0(0(1(0(0(0(0(1(1(0(0(0(1(x1)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) 0(0(0(0(1(0(1(1(1(1(0(1(0(1(1(1(0(0(1(1(0(0(1(0(0(1(0(0(1(0(1(1(0(0(0(0(1(0(0(0(0(0(0(0(1(1(1(1(1(1(0(0(1(1(0(1(0(1(0(1(0(1(0(0(0(1(0(1(0(1(0(0(0(1(1(1(0(1(0(0(0(1(1(1(0(0(1(1(0(1(0(1(1(0(1(0(1(1(0(1(1(0(1(1(0(1(1(1(1(0(0(1(0(1(1(0(0(1(0(0(1(1(1(0(0(0(0(1(0(1(1(1(0(1(1(0(1(0(0(0(1(0(0(1(1(1(0(1(x1)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) -> 2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(x1))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) Q is empty. ---------------------------------------- (3) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(0(x_1)) = 23 + x_1 POL(1(x_1)) = x_1 POL(2(x_1)) = 12 + x_1 POL(3(x_1)) = x_1 POL(4(x_1)) = x_1 POL(5(x_1)) = x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: 0(x1) -> 1(x1) 0(0(x1)) -> 0(x1) 2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(x1))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) -> 1(0(1(1(0(1(0(1(0(1(0(0(1(0(1(1(0(1(0(0(1(0(1(0(0(0(0(0(1(1(1(1(0(1(0(0(1(0(1(0(0(1(0(1(0(0(0(0(0(0(0(1(0(0(1(1(1(0(1(1(0(0(0(1(0(0(0(1(1(1(0(1(1(1(1(1(0(1(0(0(1(1(0(1(1(0(1(1(1(0(0(0(1(1(1(1(0(0(0(0(1(1(0(0(1(1(1(1(0(1(1(1(1(1(1(0(0(1(1(1(1(0(0(1(1(0(0(0(1(1(0(0(0(1(0(0(0(0(1(1(0(0(0(1(x1)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) 0(0(0(0(1(0(1(1(1(1(0(1(0(1(1(1(0(0(1(1(0(0(1(0(0(1(0(0(1(0(1(1(0(0(0(0(1(0(0(0(0(0(0(0(1(1(1(1(1(1(0(0(1(1(0(1(0(1(0(1(0(1(0(0(0(1(0(1(0(1(0(0(0(1(1(1(0(1(0(0(0(1(1(1(0(0(1(1(0(1(0(1(1(0(1(0(1(1(0(1(1(0(1(1(0(1(1(1(1(0(0(1(0(1(1(0(0(1(0(0(1(1(1(0(0(0(0(1(0(1(1(1(0(1(1(0(1(0(0(0(1(0(0(1(1(1(0(1(x1)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) -> 2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(x1))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 5(4(3(x1))) -> 5(3(4(x1))) Q is empty. ---------------------------------------- (5) AAECC Innermost (EQUIVALENT) We have applied [NOC,AAECCNOC] to switch to innermost. The TRS R 1 is none The TRS R 2 is 5(4(3(x1))) -> 5(3(4(x1))) popout

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