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SRS Standard pair #487517643
details
property
value
status
complete
benchmark
aprove2.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n177.star.cs.uiowa.edu
space
Secret_05_SRS
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
3.77512907982 seconds
cpu usage
13.58745957
max memory
1.100128256E9
stage attributes
key
value
output-size
3538
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: g(h(x1)) -> g(f(s(x1))) f(s(s(s(x1)))) -> h(f(s(h(x1)))) f(h(x1)) -> h(f(s(h(x1)))) h(x1) -> x1 f(f(s(s(x1)))) -> s(s(s(f(f(x1))))) b(a(x1)) -> a(b(x1)) a(a(a(x1))) -> b(a(a(b(x1)))) b(b(b(b(x1)))) -> a(x1) Proof: Matrix Interpretation Processor: dim=1 interpretation: [a](x0) = x0 + 6, [g](x0) = x0 + 2, [f](x0) = x0, [b](x0) = x0 + 3, [h](x0) = x0, [s](x0) = x0 orientation: g(h(x1)) = x1 + 2 >= x1 + 2 = g(f(s(x1))) f(s(s(s(x1)))) = x1 >= x1 = h(f(s(h(x1)))) f(h(x1)) = x1 >= x1 = h(f(s(h(x1)))) h(x1) = x1 >= x1 = x1 f(f(s(s(x1)))) = x1 >= x1 = s(s(s(f(f(x1))))) b(a(x1)) = x1 + 9 >= x1 + 9 = a(b(x1)) a(a(a(x1))) = x1 + 18 >= x1 + 18 = b(a(a(b(x1)))) b(b(b(b(x1)))) = x1 + 12 >= x1 + 6 = a(x1) problem: g(h(x1)) -> g(f(s(x1))) f(s(s(s(x1)))) -> h(f(s(h(x1)))) f(h(x1)) -> h(f(s(h(x1)))) h(x1) -> x1 f(f(s(s(x1)))) -> s(s(s(f(f(x1))))) b(a(x1)) -> a(b(x1)) a(a(a(x1))) -> b(a(a(b(x1)))) String Reversal Processor: h(g(x1)) -> s(f(g(x1))) s(s(s(f(x1)))) -> h(s(f(h(x1)))) h(f(x1)) -> h(s(f(h(x1)))) h(x1) -> x1 s(s(f(f(x1)))) -> f(f(s(s(s(x1))))) a(b(x1)) -> b(a(x1)) a(a(a(x1))) -> b(a(a(b(x1)))) Matrix Interpretation Processor: dim=1 interpretation: [a](x0) = x0 + 4, [g](x0) = 2x0 + 8, [f](x0) = x0, [b](x0) = x0, [h](x0) = x0, [s](x0) = x0 orientation: h(g(x1)) = 2x1 + 8 >= 2x1 + 8 = s(f(g(x1))) s(s(s(f(x1)))) = x1 >= x1 = h(s(f(h(x1)))) h(f(x1)) = x1 >= x1 = h(s(f(h(x1)))) h(x1) = x1 >= x1 = x1 s(s(f(f(x1)))) = x1 >= x1 = f(f(s(s(s(x1))))) a(b(x1)) = x1 + 4 >= x1 + 4 = b(a(x1)) a(a(a(x1))) = x1 + 12 >= x1 + 8 = b(a(a(b(x1)))) problem: h(g(x1)) -> s(f(g(x1))) s(s(s(f(x1)))) -> h(s(f(h(x1)))) h(f(x1)) -> h(s(f(h(x1)))) h(x1) -> x1 s(s(f(f(x1)))) -> f(f(s(s(s(x1))))) a(b(x1)) -> b(a(x1))
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