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SRS Standard pair #487518168
details
property
value
status
complete
benchmark
abaaaaa-aaaaaababab.srs.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n005.star.cs.uiowa.edu
space
Wenzel_16
run statistics
property
value
solver
MultumNonMulta 3.16 29 June 2020 60G
configuration
default
runtime (wallclock)
1.6653649807 seconds
cpu usage
5.201830107
max memory
1.652289536E9
stage attributes
key
value
output-size
8526
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES After renaming modulo { a->0, b->1 }, it remains to prove termination of the 1-rule system { 0 1 0 0 0 0 0 -> 0 0 0 0 0 0 1 0 1 0 1 } The system was reversed. After renaming modulo { 0->0, 1->1 }, it remains to prove termination of the 1-rule system { 0 0 0 0 0 1 0 -> 1 0 1 0 1 0 0 0 0 0 0 } Applying sparse tiling TRFC(2) [Geser/Hofbauer/Waldmann, FSCD 2019]. After renaming modulo { (0,0)->0, (0,1)->1, (1,0)->2, (0,3)->3, (1,1)->4 }, it remains to prove termination of the 6-rule system { 0 0 0 0 0 1 2 0 -> 1 2 1 2 1 2 0 0 0 0 0 0 , 0 0 0 0 0 1 2 1 -> 1 2 1 2 1 2 0 0 0 0 0 1 , 0 0 0 0 0 1 2 3 -> 1 2 1 2 1 2 0 0 0 0 0 3 , 2 0 0 0 0 1 2 0 -> 4 2 1 2 1 2 0 0 0 0 0 0 , 2 0 0 0 0 1 2 1 -> 4 2 1 2 1 2 0 0 0 0 0 1 , 2 0 0 0 0 1 2 3 -> 4 2 1 2 1 2 0 0 0 0 0 3 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 9: 0 is interpreted by / \ | 1 0 0 0 0 0 0 0 0 | | 0 1 0 0 0 0 0 0 0 | | 0 0 0 1 0 0 0 0 0 | | 0 0 0 0 1 0 0 0 0 | | 0 0 0 0 0 1 0 0 0 | | 0 0 0 0 0 0 1 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 1 0 0 0 0 0 0 0 | \ / 1 is interpreted by / \ | 1 0 0 0 0 0 0 0 0 | | 0 1 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 1 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | \ / 2 is interpreted by / \ | 1 0 1 0 0 0 0 0 0 | | 0 1 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 1 | | 0 0 0 0 0 0 0 0 0 | \ / 3 is interpreted by / \ | 1 0 0 0 0 0 0 0 0 | | 0 1 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | \ / 4 is interpreted by / \ | 1 0 0 0 0 0 0 0 0 | | 0 1 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 | \ / After renaming modulo { 0->0, 1->1, 2->2, 3->3, 4->4 }, it remains to prove termination of the 5-rule system { 0 0 0 0 0 1 2 0 -> 1 2 1 2 1 2 0 0 0 0 0 0 , 0 0 0 0 0 1 2 1 -> 1 2 1 2 1 2 0 0 0 0 0 1 ,
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