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SRS Standard pair #487518443
details
property
value
status
complete
benchmark
abaaaaa-aaaaaababaaab.srs.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n048.star.cs.uiowa.edu
space
Wenzel_16
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.66593003273 seconds
cpu usage
3.857584694
max memory
3.04381952E8
stage attributes
key
value
output-size
3418
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(a(a(a(x1))))))) -> a(a(a(a(a(a(b(a(b(a(a(a(b(x1))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(b(a(x1))))))) -> b(a(a(a(b(a(b(a(a(a(a(a(a(x1))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(a(b(a(x1))))))) -> b(a(a(a(b(a(b(a(a(a(a(a(a(x1))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(a(b(x)))))) -> b(a(a(a(b(a(b(a(a(a(a(a(x)))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(b(x)))))) -> b(a(a(a(b(a(b(a(a(a(a(a(x)))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(a(b(x)))))) -> b(a(a(a(b(a(b(a(a(a(a(a(x)))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 388, 389, 390, 391, 392, 393, 394, 395, 396, 397, 398, 399, 400, 401, 402, 403, 404, 405, 406, 407, 408, 409, 410, 411 Node 388 is start node and node 389 is final node. Those nodes are connected through the following edges: * 388 to 390 labelled b_1(0)* 389 to 389 labelled #_1(0)* 390 to 391 labelled a_1(0)* 391 to 392 labelled a_1(0)* 392 to 393 labelled a_1(0)* 393 to 394 labelled b_1(0)* 394 to 395 labelled a_1(0)* 395 to 396 labelled b_1(0)* 396 to 397 labelled a_1(0)* 396 to 401 labelled b_1(1)* 397 to 398 labelled a_1(0)* 397 to 401 labelled b_1(1)* 398 to 399 labelled a_1(0)* 398 to 401 labelled b_1(1)* 399 to 400 labelled a_1(0)* 399 to 401 labelled b_1(1)* 400 to 389 labelled a_1(0)* 400 to 401 labelled b_1(1)* 401 to 402 labelled a_1(1)* 402 to 403 labelled a_1(1)* 403 to 404 labelled a_1(1)* 404 to 405 labelled b_1(1)* 405 to 406 labelled a_1(1)* 406 to 407 labelled b_1(1)* 407 to 408 labelled a_1(1)* 407 to 401 labelled b_1(1)* 408 to 409 labelled a_1(1)* 408 to 401 labelled b_1(1)* 409 to 410 labelled a_1(1)* 409 to 401 labelled b_1(1)* 410 to 411 labelled a_1(1)* 410 to 401 labelled b_1(1)* 411 to 389 labelled a_1(1)* 411 to 401 labelled b_1(1) ---------------------------------------- (6) YES
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