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SRS Standard pair #487518618
details
property
value
status
complete
benchmark
baabababba-abababbaababab.srs.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n115.star.cs.uiowa.edu
space
Wenzel_16
run statistics
property
value
solver
MultumNonMulta 3.16 29 June 2020 60G
configuration
default
runtime (wallclock)
1.10794901848 seconds
cpu usage
2.910696253
max memory
7.73730304E8
stage attributes
key
value
output-size
2452
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES After renaming modulo { b->0, a->1 }, it remains to prove termination of the 1-rule system { 0 1 1 0 1 0 1 0 0 1 -> 1 0 1 0 1 0 0 1 1 0 1 0 1 0 } The system was reversed. After renaming modulo { 1->0, 0->1 }, it remains to prove termination of the 1-rule system { 0 1 1 0 1 0 1 0 0 1 -> 1 0 1 0 1 0 0 1 1 0 1 0 1 0 } Applying the dependency pairs transformation. After renaming modulo { (0,true)->0, (1,false)->1, (0,false)->2 }, it remains to prove termination of the 8-rule system { 0 1 1 2 1 2 1 2 2 1 -> 0 1 2 1 2 2 1 1 2 1 2 1 2 , 0 1 1 2 1 2 1 2 2 1 -> 0 1 2 2 1 1 2 1 2 1 2 , 0 1 1 2 1 2 1 2 2 1 -> 0 2 1 1 2 1 2 1 2 , 0 1 1 2 1 2 1 2 2 1 -> 0 1 1 2 1 2 1 2 , 0 1 1 2 1 2 1 2 2 1 -> 0 1 2 1 2 , 0 1 1 2 1 2 1 2 2 1 -> 0 1 2 , 0 1 1 2 1 2 1 2 2 1 -> 0 , 2 1 1 2 1 2 1 2 2 1 ->= 1 2 1 2 1 2 2 1 1 2 1 2 1 2 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 11: 0 is interpreted by / \ | 1 0 1 0 0 0 0 0 0 0 0 | | 0 1 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 0 | \ / 1 is interpreted by / \ | 1 0 1 0 0 0 0 0 0 0 0 | | 0 1 0 0 0 0 0 0 0 0 0 | | 0 0 0 1 0 0 0 0 0 0 0 | | 0 0 0 0 1 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 1 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 1 0 0 | | 0 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 0 | | 0 1 0 0 0 0 0 0 0 1 0 | \ / 2 is interpreted by / \ | 1 0 0 0 0 0 0 0 0 0 0 | | 0 1 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 0 | | 0 0 1 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 1 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 1 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 1 0 | | 0 0 0 0 0 0 0 0 0 0 1 | | 0 0 3 0 0 0 0 0 0 0 0 | \ / After renaming modulo { 2->0, 1->1 }, it remains to prove termination of the 1-rule system { 0 1 1 0 1 0 1 0 0 1 ->= 1 0 1 0 1 0 0 1 1 0 1 0 1 0 } The system is trivially terminating.
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