details

property	value
status	complete
benchmark	7.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n037.star.cs.uiowa.edu
space	Secret_06_SRS

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	3.9731669426 seconds
cpu usage	12.769805778
max memory	1.639612416E9

stage attributes

key	value
output-size	3529
starexec-result	YES

output

/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 0 ms] (2) QDP (3) QDPOrderProof [EQUIVALENT, 150 ms] (4) QDP (5) UsableRulesProof [EQUIVALENT, 0 ms] (6) QDP (7) QDPSizeChangeProof [EQUIVALENT, 0 ms] (8) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(b(x1))) -> b(a(a(a(x1)))) a(a(b(x1))) -> b(a(b(x1))) Q is empty. ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: A(b(b(x1))) -> A(a(a(x1))) A(b(b(x1))) -> A(a(x1)) A(b(b(x1))) -> A(x1) The TRS R consists of the following rules: a(b(b(x1))) -> b(a(a(a(x1)))) a(a(b(x1))) -> b(a(b(x1))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (3) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. A(b(b(x1))) -> A(a(a(x1))) A(b(b(x1))) -> A(a(x1)) The remaining pairs can at least be oriented weakly. Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: <<< POL(A(x_1)) = [[0A]] + [[0A, 0A, -I]] * x_1 >>> <<< POL(b(x_1)) = [[0A], [1A], [-I]] + [[-I, -I, -I], [-I, -I, 0A], [0A, 1A, -I]] * x_1 >>> <<< POL(a(x_1)) = [[0A], [-I], [0A]] + [[-I, 0A, -I], [-I, 0A, -I], [1A, 0A, -I]] * x_1 >>> The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: a(b(b(x1))) -> b(a(a(a(x1)))) a(a(b(x1))) -> b(a(b(x1))) ---------------------------------------- (4) Obligation: Q DP problem: The TRS P consists of the following rules: A(b(b(x1))) -> A(x1) The TRS R consists of the following rules: popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to SRS Standard