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SRS Standard pair #487519353
details
property
value
status
complete
benchmark
multum2.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n177.star.cs.uiowa.edu
space
Secret_06_SRS
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
1.93398404121 seconds
cpu usage
6.399956956
max memory
9.7490944E8
stage attributes
key
value
output-size
1443
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: a(a(b(x1))) -> b(b(a(a(x1)))) b(a(b(a(x1)))) -> a(a(a(b(x1)))) Proof: Matrix Interpretation Processor: dim=4 interpretation: [1 0 0 0] [0] [0 0 0 0] [0] [a](x0) = [0 0 0 1]x0 + [1] [0 1 0 0] [0], [1 0 0 1] [0 0 1 0] [b](x0) = [0 0 0 1]x0 [0 0 0 0] orientation: [1 0 0 1] [0] [1 0 0 0] [0 0 0 0] [0] [0 0 0 0] a(a(b(x1))) = [0 0 1 0]x1 + [1] >= [0 0 0 0]x1 = b(b(a(a(x1)))) [0 0 0 0] [0] [0 0 0 0] [1 1 0 1] [1] [1 0 0 1] [0] [0 0 0 0] [1] [0 0 0 0] [0] b(a(b(a(x1)))) = [0 0 0 1]x1 + [1] >= [0 0 0 0]x1 + [1] = a(a(a(b(x1)))) [0 0 0 0] [0] [0 0 0 0] [0] problem: a(a(b(x1))) -> b(b(a(a(x1)))) String Reversal Processor: b(a(a(x1))) -> a(a(b(b(x1)))) KBO Processor: weight function: w0 = 1 w(a) = 1 w(b) = 0 precedence: b > a problem: Qed
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