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SRS Standard pair #487519401
details
property
value
status
complete
benchmark
z104.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n123.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
1.38916897774 seconds
cpu usage
4.220074106
max memory
8.36374528E8
stage attributes
key
value
output-size
1244
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: c(c(c(a(x1)))) -> d(d(x1)) d(b(x1)) -> c(c(x1)) c(x1) -> a(a(a(a(x1)))) d(x1) -> b(b(b(b(x1)))) b(d(x1)) -> c(c(x1)) a(c(c(c(x1)))) -> d(d(x1)) Proof: Matrix Interpretation Processor: dim=1 interpretation: [c](x0) = x0 + 5, [b](x0) = x0 + 2, [a](x0) = x0 + 1, [d](x0) = x0 + 8 orientation: c(c(c(a(x1)))) = x1 + 16 >= x1 + 16 = d(d(x1)) d(b(x1)) = x1 + 10 >= x1 + 10 = c(c(x1)) c(x1) = x1 + 5 >= x1 + 4 = a(a(a(a(x1)))) d(x1) = x1 + 8 >= x1 + 8 = b(b(b(b(x1)))) b(d(x1)) = x1 + 10 >= x1 + 10 = c(c(x1)) a(c(c(c(x1)))) = x1 + 16 >= x1 + 16 = d(d(x1)) problem: c(c(c(a(x1)))) -> d(d(x1)) d(b(x1)) -> c(c(x1)) d(x1) -> b(b(b(b(x1)))) b(d(x1)) -> c(c(x1)) a(c(c(c(x1)))) -> d(d(x1)) WPO Processor: algebra: Sum weight function: w0 = 0 w(a) = 6 w(b) = w(d) = w(c) = 0 status function: st(b) = st(d) = st(c) = st(a) = [0] precedence: d > b ~ c ~ a problem: Qed
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