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SRS Standard pair #487519427
details
property
value
status
complete
benchmark
z055.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n016.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.85565400124 seconds
cpu usage
3.784158837
max memory
2.70405632E8
stage attributes
key
value
output-size
1919
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) RFCMatchBoundsTRSProof [EQUIVALENT, 1 ms] (4) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: b(a(a(b(b(b(x1)))))) -> a(b(a(b(b(b(a(x1))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: b(b(b(a(a(b(x1)))))) -> a(b(b(b(a(b(a(x1))))))) Q is empty. ---------------------------------------- (3) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 0. This implies Q-termination of R. The following rules were used to construct the certificate: b(b(b(a(a(b(x1)))))) -> a(b(b(b(a(b(a(x1))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 2, 3, 11, 12, 13, 14, 15, 16 Node 2 is start node and node 3 is final node. Those nodes are connected through the following edges: * 2 to 11 labelled a_1(0)* 3 to 3 labelled #_1(0)* 11 to 12 labelled b_1(0)* 12 to 13 labelled b_1(0)* 13 to 14 labelled b_1(0)* 14 to 15 labelled a_1(0)* 15 to 16 labelled b_1(0)* 16 to 3 labelled a_1(0) ---------------------------------------- (4) YES
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