SRS Standard pair #487519629

details

property	value
status	complete
benchmark	z066.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n134.star.cs.uiowa.edu
space	Zantema_04

run statistics

property	value
solver	ttt2-1.20
configuration	ttt2
runtime (wallclock)	2.21327280998 seconds
cpu usage	7.373590888
max memory	1.116647424E9

stage attributes

key	value
output-size	2050
starexec-result	YES

output

/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


--------------------------------------------------------------------------------


YES

Problem:
 a(b(c(x1))) -> c(b(a(x1)))
 C(B(A(x1))) -> A(B(C(x1)))
 b(a(C(x1))) -> C(a(b(x1)))
 c(A(B(x1))) -> B(A(c(x1)))
 A(c(b(x1))) -> b(c(A(x1)))
 B(C(a(x1))) -> a(C(B(x1)))
 a(A(x1)) -> x1
 A(a(x1)) -> x1
 b(B(x1)) -> x1
 B(b(x1)) -> x1
 c(C(x1)) -> x1
 C(c(x1)) -> x1

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [B](x0) = x0 + 14,
   
   [b](x0) = x0 + 3,
   
   [A](x0) = x0 + 3,
   
   [C](x0) = x0 + 5,
   
   [c](x0) = x0 + 12,
   
   [a](x0) = x0
  orientation:
   a(b(c(x1))) = x1 + 15 >= x1 + 15 = c(b(a(x1)))
   
   C(B(A(x1))) = x1 + 22 >= x1 + 22 = A(B(C(x1)))
   
   b(a(C(x1))) = x1 + 8 >= x1 + 8 = C(a(b(x1)))
   
   c(A(B(x1))) = x1 + 29 >= x1 + 29 = B(A(c(x1)))
   
   A(c(b(x1))) = x1 + 18 >= x1 + 18 = b(c(A(x1)))
   
   B(C(a(x1))) = x1 + 19 >= x1 + 19 = a(C(B(x1)))
   
   a(A(x1)) = x1 + 3 >= x1 = x1
   
   A(a(x1)) = x1 + 3 >= x1 = x1
   
   b(B(x1)) = x1 + 17 >= x1 = x1
   
   B(b(x1)) = x1 + 17 >= x1 = x1
   
   c(C(x1)) = x1 + 17 >= x1 = x1
   
   C(c(x1)) = x1 + 17 >= x1 = x1
  problem:
   a(b(c(x1))) -> c(b(a(x1)))
   C(B(A(x1))) -> A(B(C(x1)))
   b(a(C(x1))) -> C(a(b(x1)))
   c(A(B(x1))) -> B(A(c(x1)))
   A(c(b(x1))) -> b(c(A(x1)))
   B(C(a(x1))) -> a(C(B(x1)))
  Bounds Processor:
   bound: 0
   enrichment: match
   automaton:
    final states: {17,14,11,8,5,1}
    transitions:
     B0(2) -> 18*
     B0(13) -> 11*
     B0(6) -> 7*
     c0(15) -> 16*
     c0(4) -> 1*
     c0(2) -> 12*
     A0(7) -> 5*
     A0(12) -> 13*
     A0(2) -> 15*
     a0(2) -> 3*
     a0(9) -> 10*
     a0(19) -> 17*
     b0(16) -> 14*
     b0(2) -> 9*
     b0(3) -> 4*
     C0(10) -> 8*
     C0(2) -> 6*
     C0(18) -> 19*
     f60() -> 2*
     17 -> 18,7
     14 -> 15,13
     11 -> 12,16
     8 -> 9,4
     1 -> 3,10
     5 -> 6,19
   problem:

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