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SRS Standard pair #487520061
details
property
value
status
complete
benchmark
z100.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n005.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
2.11508584023 seconds
cpu usage
7.333440873
max memory
1.0645504E9
stage attributes
key
value
output-size
3720
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: r1(a(x1)) -> a(a(a(r1(x1)))) r2(a(x1)) -> a(a(a(r2(x1)))) a(l1(x1)) -> l1(a(a(a(x1)))) a(a(l2(x1))) -> l2(a(a(x1))) r1(b(x1)) -> l1(b(x1)) r2(b(x1)) -> l2(a(b(x1))) b(l1(x1)) -> b(r2(x1)) b(l2(x1)) -> b(r1(x1)) a(a(x1)) -> x1 Proof: String Reversal Processor: a(r1(x1)) -> r1(a(a(a(x1)))) a(r2(x1)) -> r2(a(a(a(x1)))) l1(a(x1)) -> a(a(a(l1(x1)))) l2(a(a(x1))) -> a(a(l2(x1))) b(r1(x1)) -> b(l1(x1)) b(r2(x1)) -> b(a(l2(x1))) l1(b(x1)) -> r2(b(x1)) l2(b(x1)) -> r1(b(x1)) a(a(x1)) -> x1 Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [0] [l2](x0) = [0 1 0]x0 + [0] [0 1 0] [1], [1 0 0] [0] [r1](x0) = [0 0 1]x0 + [1] [0 1 0] [1], [1 0 0] [l1](x0) = [0 0 1]x0 [0 1 0] , [1 0 1] [0] [b](x0) = [0 0 0]x0 + [1] [0 0 0] [0], [1 0 0] [a](x0) = [0 0 1]x0 [0 1 0] , [1 0 0] [r2](x0) = [0 0 1]x0 [0 1 0] orientation: [0] [0] a(r1(x1)) = x1 + [1] >= x1 + [1] = r1(a(a(a(x1)))) [1] [1] a(r2(x1)) = x1 >= x1 = r2(a(a(a(x1)))) l1(a(x1)) = x1 >= x1 = a(a(a(l1(x1)))) [1 0 0] [0] [1 0 0] [0] l2(a(a(x1))) = [0 1 0]x1 + [0] >= [0 1 0]x1 + [0] = a(a(l2(x1))) [0 1 0] [1] [0 1 0] [1] [1 1 0] [1] [1 1 0] [0] b(r1(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = b(l1(x1)) [0 0 0] [0] [0 0 0] [0] [1 1 0] [0] [1 1 0] [0] b(r2(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = b(a(l2(x1))) [0 0 0] [0] [0 0 0] [0] [1 0 1] [0] [1 0 1] [0] l1(b(x1)) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = r2(b(x1)) [0 0 0] [1] [0 0 0] [1] [1 0 1] [0] [1 0 1] [0] l2(b(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = r1(b(x1)) [0 0 0] [2] [0 0 0] [2] a(a(x1)) = x1 >= x1 = x1 problem: a(r1(x1)) -> r1(a(a(a(x1)))) a(r2(x1)) -> r2(a(a(a(x1)))) l1(a(x1)) -> a(a(a(l1(x1)))) l2(a(a(x1))) -> a(a(l2(x1))) b(r2(x1)) -> b(a(l2(x1))) l1(b(x1)) -> r2(b(x1)) l2(b(x1)) -> r1(b(x1))
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