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SRS Standard pair #487520429
details
property
value
status
complete
benchmark
size-11-alpha-3-num-21.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n009.star.cs.uiowa.edu
space
Waldmann_07_size11
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
2.98117399216 seconds
cpu usage
8.060974441
max memory
1.052233728E9
stage attributes
key
value
output-size
2047
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 389 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(x1) -> x1 a(b(x1)) -> b(c(b(a(x1)))) b(x1) -> a(x1) c(c(x1)) -> x1 Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "a b b c b -> a b b c b" a b b c b -> a b b c b by OverlapClosure OC 3"a b b c b -> b b b c b by OverlapClosure OC 2"a b b c -> b b a by OverlapClosure OC 3"a b b c -> b c c b a by OverlapClosure OC 2"a b b -> b c c b a c by OverlapClosure OC 3"a b b -> b c b c b a c by OverlapClosure OC 3"a b b -> b c a b c by OverlapClosure OC 3"a b b -> b c b b c by OverlapClosure OC 2"a b -> b c b a by original rule (OC 1)""a b -> b c by OverlapClosure OC 2"a b -> b c b by OverlapClosure OC 2"a b -> b c b a by original rule (OC 1)""a -> by original rule (OC 1)"""b -> by OverlapClosure OC 2"b -> a by original rule (OC 1)""a -> by original rule (OC 1)"""""b -> a by original rule (OC 1)"""a b -> b c b a by original rule (OC 1)"""b -> by OverlapClosure OC 2"b -> a by original rule (OC 1)""a -> by original rule (OC 1)""""c c -> by original rule (OC 1)"""c c -> by original rule (OC 1)"""a b -> b c b by OverlapClosure OC 2"a b -> b c b a by original rule (OC 1)""a -> by original rule (OC 1)""""b -> a by original rule (OC 1)" ---------------------------------------- (2) NO
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