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SRS Standard pair #487520451
details
property
value
status
complete
benchmark
size-11-alpha-3-num-12.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n133.star.cs.uiowa.edu
space
Waldmann_07_size11
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
44.7321560383 seconds
cpu usage
177.46591604
max memory
1.396547584E9
stage attributes
key
value
output-size
2612
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: a(x1) -> x1 a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) Proof: DP Processor: DPs: a#(b(b(x1))) -> a#(x1) a#(b(b(x1))) -> a#(a(x1)) TRS: a(x1) -> x1 a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) Arctic Interpretation Processor: dimension: 2 usable rules: a(x1) -> x1 a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) interpretation: [-& 0 ] [0 ] [c](x0) = [-& -&]x0 + [-&], [a#](x0) = [-& 2 ]x0 + [0], [0 0] [0] [a](x0) = [0 0]x0 + [0], [0 2] [0] [b](x0) = [0 0]x0 + [0] orientation: a#(b(b(x1))) = [2 4]x1 + [2] >= [-& 2 ]x1 + [0] = a#(x1) a#(b(b(x1))) = [2 4]x1 + [2] >= [2 2]x1 + [2] = a#(a(x1)) [0 0] [0] a(x1) = [0 0]x1 + [0] >= x1 = x1 [0 0] [0] [-& 0 ] [0] a(x1) = [0 0]x1 + [0] >= [-& 0 ]x1 + [0] = b(c(x1)) [2 2] [2] [2 2] [2] a(b(b(x1))) = [2 2]x1 + [2] >= [2 2]x1 + [2] = b(b(a(a(x1)))) problem: DPs: a#(b(b(x1))) -> a#(a(x1)) TRS: a(x1) -> x1 a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) Restore Modifier: DPs: a#(b(b(x1))) -> a#(a(x1)) TRS: a(x1) -> x1 a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) Arctic Interpretation Processor: dimension: 2 usable rules: a(x1) -> x1 a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) interpretation: [-& -&] [1] [c](x0) = [0 -&]x0 + [0], [a#](x0) = [2 1]x0 + [0], [0 -&] [0] [a](x0) = [1 0 ]x0 + [2], [-& 0 ] [0] [b](x0) = [1 0 ]x0 + [2] orientation: a#(b(b(x1))) = [3 2]x1 + [4] >= [2 1]x1 + [3] = a#(a(x1)) [0 -&] [0] a(x1) = [1 0 ]x1 + [2] >= x1 = x1 [0 -&] [0] [0 -&] [0] a(x1) = [1 0 ]x1 + [2] >= [0 -&]x1 + [2] = b(c(x1)) [1 0] [2] [1 0] [2] a(b(b(x1))) = [2 1]x1 + [3] >= [2 1]x1 + [3] = b(b(a(a(x1)))) problem: DPs: TRS: a(x1) -> x1 a(x1) -> b(c(x1))
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