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TRS Relative pair #487520517
details
property
value
status
complete
benchmark
ex7.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n053.star.cs.uiowa.edu
space
INVY_15
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.78930401802 seconds
cpu usage
3.872706252
max memory
2.849792E8
stage attributes
key
value
output-size
1265
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination of the given RelTRS could be disproven: (0) RelTRS (1) RelTRSLoopFinderProof [COMPLETE, 16 ms] (2) NO ---------------------------------------- (0) Obligation: Relative term rewrite system: The relative TRS consists of the following R rules: f(s(x)) -> f(x) The relative TRS consists of the following S rules: inf -> s(inf) ---------------------------------------- (1) RelTRSLoopFinderProof (COMPLETE) The following loop was found: ---------- Loop: ---------- f(inf) -> f(s(inf)) with rule inf -> s(inf) at position [0] and matcher [ ] f(s(inf)) -> f(inf) with rule f(s(x)) -> f(x) at position [] and matcher [x / inf] Now an instance of the first term with Matcher [ ] occurs in the last term at position []. Context: [] Therefore, the relative TRS problem does not terminate. ---------------------------------------- (2) NO
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