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TRS Relative pair #487520747
details
property
value
status
complete
benchmark
rtL-me2.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n054.star.cs.uiowa.edu
space
Relative_05
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
2.17900013924 seconds
cpu usage
7.397334772
max memory
6.52566528E8
stage attributes
key
value
output-size
9456
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: strict: topB(i,N1(),y) -> topA(1(),T1(),y) topA(i,x,N2()) -> topB(0(),x,T2()) topB(i,S1(),y) -> topA(i,N1(),y) topA(i,x,S2()) -> topB(i,x,N2()) topA(i,N1(),T2()) -> topB(i,N1(),S2()) topA(1(),T1(),T2()) -> topB(1(),T1(),S2()) weak: topA(i,N1(),y) -> topA(1(),T1(),y) topB(i,x,N2()) -> topB(0(),x,T2()) topA(i,S1(),y) -> topA(i,N1(),y) topB(i,x,S2()) -> topB(i,x,N2()) topB(i,N1(),T2()) -> topB(i,N1(),S2()) topB(1(),T1(),T2()) -> topB(1(),T1(),S2()) Proof: Matrix Interpretation Processor: dim=2 interpretation: [1 0] [2 2] [1 0] [topA](x0, x1, x2) = [0 0]x0 + [1 2]x1 + [0 0]x2, [0] [S1] = [1], [1 0] [1 2] [2 0] [topB](x0, x1, x2) = [0 0]x0 + [0 2]x1 + [1 0]x2, [0] [T1] = [0], [0] [N2] = [0], [1] [N1] = [0], [0] [T2] = [0], [0] [S2] = [0], [0] [0] = [0], [0] [1] = [0] orientation: [1 0] [2 0] [1] [1 0] topB(i,N1(),y) = [0 0]i + [1 0]y + [0] >= [0 0]y = topA(1(),T1(),y) [1 0] [2 2] [1 2] topA(i,x,N2()) = [0 0]i + [1 2]x >= [0 2]x = topB(0(),x,T2()) [1 0] [2 0] [2] [1 0] [1 0] [2] topB(i,S1(),y) = [0 0]i + [1 0]y + [2] >= [0 0]i + [0 0]y + [1] = topA(i,N1(),y) [1 0] [2 2] [1 0] [1 2] topA(i,x,S2()) = [0 0]i + [1 2]x >= [0 0]i + [0 2]x = topB(i,x,N2()) [1 0] [2] [1 0] [1] topA(i,N1(),T2()) = [0 0]i + [1] >= [0 0]i + [0] = topB(i,N1(),S2()) [0] [0] topA(1(),T1(),T2()) = [0] >= [0] = topB(1(),T1(),S2()) [1 0] [1 0] [2] [1 0] topA(i,N1(),y) = [0 0]i + [0 0]y + [1] >= [0 0]y = topA(1(),T1(),y) [1 0] [1 2] [1 2] topB(i,x,N2()) = [0 0]i + [0 2]x >= [0 2]x = topB(0(),x,T2()) [1 0] [1 0] [2] [1 0] [1 0] [2] topA(i,S1(),y) = [0 0]i + [0 0]y + [2] >= [0 0]i + [0 0]y + [1] = topA(i,N1(),y) [1 0] [1 2] [1 0] [1 2] topB(i,x,S2()) = [0 0]i + [0 2]x >= [0 0]i + [0 2]x = topB(i,x,N2()) [1 0] [1] [1 0] [1] topB(i,N1(),T2()) = [0 0]i + [0] >= [0 0]i + [0] = topB(i,N1(),S2()) [0] [0] topB(1(),T1(),T2()) = [0] >= [0] = topB(1(),T1(),S2()) problem: strict: topA(i,x,N2()) -> topB(0(),x,T2()) topB(i,S1(),y) -> topA(i,N1(),y) topA(i,x,S2()) -> topB(i,x,N2()) topA(1(),T1(),T2()) -> topB(1(),T1(),S2()) weak:
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