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SRS Relative pair #487521004
details
property
value
status
complete
benchmark
zr08.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n139.star.cs.uiowa.edu
space
Mixed_relative_SRS
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
1.37411189079 seconds
cpu usage
4.357012517
max memory
6.11930112E8
stage attributes
key
value
output-size
2140
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: strict: b(b(x1)) -> c(d(x1)) c(c(x1)) -> d(d(d(x1))) d(d(d(x1))) -> a(c(x1)) weak: a(a(x1)) -> b(c(x1)) b(c(x1)) -> a(a(x1)) Proof: Arctic Interpretation Processor: dimension: 1 interpretation: [d](x0) = 2x0, [a](x0) = 3x0, [b](x0) = 3x0, [c](x0) = 3x0 orientation: b(b(x1)) = 6x1 >= 5x1 = c(d(x1)) c(c(x1)) = 6x1 >= 6x1 = d(d(d(x1))) d(d(d(x1))) = 6x1 >= 6x1 = a(c(x1)) a(a(x1)) = 6x1 >= 6x1 = b(c(x1)) b(c(x1)) = 6x1 >= 6x1 = a(a(x1)) problem: strict: c(c(x1)) -> d(d(d(x1))) d(d(d(x1))) -> a(c(x1)) weak: a(a(x1)) -> b(c(x1)) b(c(x1)) -> a(a(x1)) String Reversal Processor: strict: c(c(x1)) -> d(d(d(x1))) d(d(d(x1))) -> c(a(x1)) weak: a(a(x1)) -> c(b(x1)) c(b(x1)) -> a(a(x1)) Arctic Interpretation Processor: dimension: 1 interpretation: [d](x0) = 4x0, [a](x0) = 4x0, [b](x0) = x0, [c](x0) = 8x0 orientation: c(c(x1)) = 16x1 >= 12x1 = d(d(d(x1))) d(d(d(x1))) = 12x1 >= 12x1 = c(a(x1)) a(a(x1)) = 8x1 >= 8x1 = c(b(x1)) c(b(x1)) = 8x1 >= 8x1 = a(a(x1)) problem: strict: d(d(d(x1))) -> c(a(x1)) weak: a(a(x1)) -> c(b(x1)) c(b(x1)) -> a(a(x1)) String Reversal Processor: strict: d(d(d(x1))) -> a(c(x1)) weak: a(a(x1)) -> b(c(x1)) b(c(x1)) -> a(a(x1)) Arctic Interpretation Processor: dimension: 1 interpretation: [d](x0) = 3x0, [a](x0) = x0, [b](x0) = x0, [c](x0) = x0 orientation: d(d(d(x1))) = 9x1 >= x1 = a(c(x1)) a(a(x1)) = x1 >= x1 = b(c(x1)) b(c(x1)) = x1 >= x1 = a(a(x1)) problem: strict:
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