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SRS Relative pair #487521204
details
property
value
status
complete
benchmark
random-120.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n140.star.cs.uiowa.edu
space
Waldmann_19
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
4.37783288956 seconds
cpu usage
16.225757815
max memory
1.936101376E9
stage attributes
key
value
output-size
2266
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: strict: c(c(a(x1))) -> c(c(b(x1))) b(b(c(x1))) -> a(a(b(x1))) weak: b(a(b(x1))) -> a(c(b(x1))) c(a(a(x1))) -> b(a(b(x1))) c(c(c(x1))) -> c(a(c(x1))) Proof: String Reversal Processor: strict: a(c(c(x1))) -> b(c(c(x1))) c(b(b(x1))) -> b(a(a(x1))) weak: b(a(b(x1))) -> b(c(a(x1))) a(a(c(x1))) -> b(a(b(x1))) c(c(c(x1))) -> c(a(c(x1))) Matrix Interpretation Processor: dim=2 interpretation: [1 1] [0] [c](x0) = [1 0]x0 + [1], [1 0] [a](x0) = [0 0]x0, [1 0] [b](x0) = [0 0]x0 orientation: [2 1] [1] [2 1] [1] a(c(c(x1))) = [0 0]x1 + [0] >= [0 0]x1 + [0] = b(c(c(x1))) [1 0] [0] [1 0] c(b(b(x1))) = [1 0]x1 + [1] >= [0 0]x1 = b(a(a(x1))) [1 0] [1 0] b(a(b(x1))) = [0 0]x1 >= [0 0]x1 = b(c(a(x1))) [1 1] [1 0] a(a(c(x1))) = [0 0]x1 >= [0 0]x1 = b(a(b(x1))) [3 2] [2] [1 1] [0] c(c(c(x1))) = [2 1]x1 + [2] >= [1 1]x1 + [1] = c(a(c(x1))) problem: strict: a(c(c(x1))) -> b(c(c(x1))) c(b(b(x1))) -> b(a(a(x1))) weak: b(a(b(x1))) -> b(c(a(x1))) a(a(c(x1))) -> b(a(b(x1))) String Reversal Processor: strict: c(c(a(x1))) -> c(c(b(x1))) b(b(c(x1))) -> a(a(b(x1))) weak: b(a(b(x1))) -> a(c(b(x1))) c(a(a(x1))) -> b(a(b(x1))) Matrix Interpretation Processor: dim=1 interpretation: [c](x0) = 3x0 + 1, [a](x0) = 3x0 + 2, [b](x0) = 3x0 orientation: c(c(a(x1))) = 27x1 + 22 >= 27x1 + 4 = c(c(b(x1))) b(b(c(x1))) = 27x1 + 9 >= 27x1 + 8 = a(a(b(x1))) b(a(b(x1))) = 27x1 + 6 >= 27x1 + 5 = a(c(b(x1))) c(a(a(x1))) = 27x1 + 25 >= 27x1 + 6 = b(a(b(x1))) problem: strict: weak: Qed
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