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SRS Relative pair #487521209
details
property
value
status
complete
benchmark
random-152.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n146.star.cs.uiowa.edu
space
Waldmann_19
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
8.48352003098 seconds
cpu usage
32.448155967
max memory
2.113015808E9
stage attributes
key
value
output-size
7798
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: strict: a(a(c(x1))) -> a(a(a(x1))) c(a(c(x1))) -> a(a(a(x1))) weak: b(b(a(x1))) -> c(c(c(x1))) c(b(a(x1))) -> a(c(b(x1))) b(b(b(x1))) -> b(c(b(x1))) c(a(a(x1))) -> c(c(a(x1))) Proof: String Reversal Processor: strict: c(a(a(x1))) -> a(a(a(x1))) c(a(c(x1))) -> a(a(a(x1))) weak: a(b(b(x1))) -> c(c(c(x1))) a(b(c(x1))) -> b(c(a(x1))) b(b(b(x1))) -> b(c(b(x1))) a(a(c(x1))) -> a(c(c(x1))) Arctic Interpretation Processor: dimension: 1 interpretation: [a](x0) = 4x0, [c](x0) = 4x0, [b](x0) = 9x0 orientation: c(a(a(x1))) = 12x1 >= 12x1 = a(a(a(x1))) c(a(c(x1))) = 12x1 >= 12x1 = a(a(a(x1))) a(b(b(x1))) = 22x1 >= 12x1 = c(c(c(x1))) a(b(c(x1))) = 17x1 >= 17x1 = b(c(a(x1))) b(b(b(x1))) = 27x1 >= 22x1 = b(c(b(x1))) a(a(c(x1))) = 12x1 >= 12x1 = a(c(c(x1))) problem: strict: c(a(a(x1))) -> a(a(a(x1))) c(a(c(x1))) -> a(a(a(x1))) weak: a(b(c(x1))) -> b(c(a(x1))) a(a(c(x1))) -> a(c(c(x1))) String Reversal Processor: strict: a(a(c(x1))) -> a(a(a(x1))) c(a(c(x1))) -> a(a(a(x1))) weak: c(b(a(x1))) -> a(c(b(x1))) c(a(a(x1))) -> c(c(a(x1))) Matrix Interpretation Processor: dim=2 interpretation: [0] [a](x0) = x0 + [1], [0] [c](x0) = x0 + [1], [1 2] [b](x0) = [0 1]x0 orientation: [0] [0] a(a(c(x1))) = x1 + [3] >= x1 + [3] = a(a(a(x1))) [0] [0] c(a(c(x1))) = x1 + [3] >= x1 + [3] = a(a(a(x1))) [1 2] [2] [1 2] [0] c(b(a(x1))) = [0 1]x1 + [2] >= [0 1]x1 + [2] = a(c(b(x1))) [0] [0] c(a(a(x1))) = x1 + [3] >= x1 + [3] = c(c(a(x1))) problem: strict: a(a(c(x1))) -> a(a(a(x1))) c(a(c(x1))) -> a(a(a(x1))) weak: c(a(a(x1))) -> c(c(a(x1))) RT Transformation Processor: a(a(c(x1))) -> a(a(a(x1))) c(a(c(x1))) -> a(a(a(x1))) c(a(a(x1))) -> c(c(a(x1))) DP Processor: DPs: a#(a(c(x1))) -> a#(x1) a#(a(c(x1))) -> a#(a(x1)) a#(a(c(x1))) -> a#(a(a(x1)))
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