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SRS Relative pair #487521301
details
property
value
status
complete
benchmark
random-70.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n054.star.cs.uiowa.edu
space
Waldmann_19
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
2.00789403915 seconds
cpu usage
5.099440469
max memory
4.616192E8
stage attributes
key
value
output-size
10446
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination of the given RelTRS could be proven: (0) RelTRS (1) RelTRS S Cleaner [EQUIVALENT, 0 ms] (2) RelTRS (3) RelTRS Reverse [EQUIVALENT, 0 ms] (4) RelTRS (5) FlatCCProof [EQUIVALENT, 0 ms] (6) RelTRS (7) RootLabelingProof [EQUIVALENT, 16 ms] (8) RelTRS (9) RelTRSRRRProof [EQUIVALENT, 11 ms] (10) RelTRS (11) RIsEmptyProof [EQUIVALENT, 0 ms] (12) YES ---------------------------------------- (0) Obligation: Relative term rewrite system: The relative TRS consists of the following R rules: b(a(a(x1))) -> c(b(b(x1))) a(a(a(x1))) -> a(c(c(x1))) a(c(b(x1))) -> a(a(b(x1))) c(a(c(x1))) -> c(c(c(x1))) The relative TRS consists of the following S rules: c(a(a(x1))) -> c(a(a(x1))) c(c(a(x1))) -> c(b(b(x1))) a(a(b(x1))) -> b(a(b(x1))) ---------------------------------------- (1) RelTRS S Cleaner (EQUIVALENT) We have deleted all rules from S that have the shape t -> t: c(a(a(x1))) -> c(a(a(x1))) ---------------------------------------- (2) Obligation: Relative term rewrite system: The relative TRS consists of the following R rules: b(a(a(x1))) -> c(b(b(x1))) a(a(a(x1))) -> a(c(c(x1))) a(c(b(x1))) -> a(a(b(x1))) c(a(c(x1))) -> c(c(c(x1))) The relative TRS consists of the following S rules: c(c(a(x1))) -> c(b(b(x1))) a(a(b(x1))) -> b(a(b(x1))) ---------------------------------------- (3) RelTRS Reverse (EQUIVALENT) We have reversed the following relative TRS [REVERSE]: The set of rules R is b(a(a(x1))) -> c(b(b(x1))) a(a(a(x1))) -> a(c(c(x1))) a(c(b(x1))) -> a(a(b(x1))) c(a(c(x1))) -> c(c(c(x1))) The set of rules S is c(c(a(x1))) -> c(b(b(x1))) a(a(b(x1))) -> b(a(b(x1))) We have obtained the following relative TRS: The set of rules R is a(a(b(x1))) -> b(b(c(x1))) a(a(a(x1))) -> c(c(a(x1))) b(c(a(x1))) -> b(a(a(x1))) c(a(c(x1))) -> c(c(c(x1))) The set of rules S is a(c(c(x1))) -> b(b(c(x1))) b(a(a(x1))) -> b(a(b(x1))) ----------------------------------------
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