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SRS Relative pair #487521489
details
property
value
status
complete
benchmark
random-146.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n074.star.cs.uiowa.edu
space
Waldmann_19
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
2.17024993896 seconds
cpu usage
7.339658189
max memory
1.202642944E9
stage attributes
key
value
output-size
2367
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: strict: b(c(c(x1))) -> a(c(b(x1))) c(a(a(x1))) -> c(b(b(x1))) a(b(a(x1))) -> c(b(a(x1))) weak: a(b(c(x1))) -> a(a(c(x1))) c(a(a(x1))) -> c(a(b(x1))) a(b(c(x1))) -> c(c(c(x1))) Proof: String Reversal Processor: strict: c(c(b(x1))) -> b(c(a(x1))) a(a(c(x1))) -> b(b(c(x1))) a(b(a(x1))) -> a(b(c(x1))) weak: c(b(a(x1))) -> c(a(a(x1))) a(a(c(x1))) -> b(a(c(x1))) c(b(a(x1))) -> c(c(c(x1))) Matrix Interpretation Processor: dim=2 interpretation: [1 2] [b](x0) = [0 0]x0, [1 0] [c](x0) = [0 0]x0, [1 2] [0] [a](x0) = [0 0]x0 + [1] orientation: [1 2] [1 2] c(c(b(x1))) = [0 0]x1 >= [0 0]x1 = b(c(a(x1))) [1 0] [2] [1 0] a(a(c(x1))) = [0 0]x1 + [1] >= [0 0]x1 = b(b(c(x1))) [1 2] [2] [1 0] [0] a(b(a(x1))) = [0 0]x1 + [1] >= [0 0]x1 + [1] = a(b(c(x1))) [1 2] [2] [1 2] [2] c(b(a(x1))) = [0 0]x1 + [0] >= [0 0]x1 + [0] = c(a(a(x1))) [1 0] [2] [1 0] [2] a(a(c(x1))) = [0 0]x1 + [1] >= [0 0]x1 + [0] = b(a(c(x1))) [1 2] [2] [1 0] c(b(a(x1))) = [0 0]x1 + [0] >= [0 0]x1 = c(c(c(x1))) problem: strict: c(c(b(x1))) -> b(c(a(x1))) weak: c(b(a(x1))) -> c(a(a(x1))) a(a(c(x1))) -> b(a(c(x1))) String Reversal Processor: strict: b(c(c(x1))) -> a(c(b(x1))) weak: a(b(c(x1))) -> a(a(c(x1))) c(a(a(x1))) -> c(a(b(x1))) Arctic Interpretation Processor: dimension: 1 interpretation: [b](x0) = x0, [c](x0) = 8x0, [a](x0) = x0 orientation: b(c(c(x1))) = 16x1 >= 8x1 = a(c(b(x1))) a(b(c(x1))) = 8x1 >= 8x1 = a(a(c(x1))) c(a(a(x1))) = 8x1 >= 8x1 = c(a(b(x1))) problem: strict: weak: a(b(c(x1))) -> a(a(c(x1))) c(a(a(x1))) -> c(a(b(x1))) Qed
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