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SRS Relative pair #487521529
details
property
value
status
complete
benchmark
random-58.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n076.star.cs.uiowa.edu
space
Waldmann_19
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
4.8348801136 seconds
cpu usage
17.212806183
max memory
1.672687616E9
stage attributes
key
value
output-size
2530
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: strict: a(c(c(x1))) -> b(a(a(x1))) b(a(b(x1))) -> b(c(a(x1))) weak: a(a(c(x1))) -> c(a(b(x1))) c(c(b(x1))) -> a(b(a(x1))) b(c(b(x1))) -> b(a(c(x1))) b(c(c(x1))) -> c(b(b(x1))) a(a(b(x1))) -> a(c(a(x1))) Proof: Matrix Interpretation Processor: dim=2 interpretation: [1 1] [a](x0) = [1 0]x0, [1 1] [1] [c](x0) = [1 0]x0 + [0], [1 1] [0] [b](x0) = [1 0]x0 + [1] orientation: [3 2] [3] [3 2] [0] a(c(c(x1))) = [2 1]x1 + [2] >= [2 1]x1 + [1] = b(a(a(x1))) [3 2] [1] [3 2] [1] b(a(b(x1))) = [2 1]x1 + [2] >= [2 1]x1 + [2] = b(c(a(x1))) [3 2] [2] [3 2] [2] a(a(c(x1))) = [2 1]x1 + [1] >= [2 1]x1 + [1] = c(a(b(x1))) [3 2] [3] [3 2] [1] c(c(b(x1))) = [2 1]x1 + [2] >= [2 1]x1 + [0] = a(b(a(x1))) [3 2] [2] [3 2] [2] b(c(b(x1))) = [2 1]x1 + [3] >= [2 1]x1 + [2] = b(a(c(x1))) [3 2] [3] [3 2] [3] b(c(c(x1))) = [2 1]x1 + [3] >= [2 1]x1 + [1] = c(b(b(x1))) [3 2] [1] [3 2] [1] a(a(b(x1))) = [2 1]x1 + [1] >= [2 1]x1 + [1] = a(c(a(x1))) problem: strict: b(a(b(x1))) -> b(c(a(x1))) weak: a(a(c(x1))) -> c(a(b(x1))) b(c(b(x1))) -> b(a(c(x1))) b(c(c(x1))) -> c(b(b(x1))) a(a(b(x1))) -> a(c(a(x1))) String Reversal Processor: strict: b(a(b(x1))) -> a(c(b(x1))) weak: c(a(a(x1))) -> b(a(c(x1))) b(c(b(x1))) -> c(a(b(x1))) c(c(b(x1))) -> b(b(c(x1))) b(a(a(x1))) -> a(c(a(x1))) Matrix Interpretation Processor: dim=1 interpretation: [a](x0) = 2x0 + 1, [c](x0) = 2x0, [b](x0) = 2x0 + 2 orientation: b(a(b(x1))) = 8x1 + 12 >= 8x1 + 9 = a(c(b(x1))) c(a(a(x1))) = 8x1 + 6 >= 8x1 + 4 = b(a(c(x1))) b(c(b(x1))) = 8x1 + 10 >= 8x1 + 10 = c(a(b(x1))) c(c(b(x1))) = 8x1 + 8 >= 8x1 + 6 = b(b(c(x1))) b(a(a(x1))) = 8x1 + 8 >= 8x1 + 5 = a(c(a(x1))) problem: strict: weak: b(c(b(x1))) -> c(a(b(x1))) Qed
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