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SRS Relative pair #487521614
details
property
value
status
complete
benchmark
random-109.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n073.star.cs.uiowa.edu
space
Waldmann_19
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
5.64325904846 seconds
cpu usage
21.229912227
max memory
2.003595264E9
stage attributes
key
value
output-size
2348
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: strict: b(b(b(x1))) -> c(a(c(x1))) a(a(c(x1))) -> a(b(a(x1))) a(a(c(x1))) -> c(b(c(x1))) weak: c(b(b(x1))) -> b(b(c(x1))) c(c(c(x1))) -> b(b(c(x1))) a(a(a(x1))) -> a(b(c(x1))) Proof: Arctic Interpretation Processor: dimension: 2 interpretation: [0 0 ] [c](x0) = [-& -&]x0, [0 0 ] [b](x0) = [-& -&]x0, [0 4] [a](x0) = [0 4]x0 orientation: [0 0 ] [0 0 ] b(b(b(x1))) = [-& -&]x1 >= [-& -&]x1 = c(a(c(x1))) [4 4] [0 4] a(a(c(x1))) = [4 4]x1 >= [0 4]x1 = a(b(a(x1))) [4 4] [0 0 ] a(a(c(x1))) = [4 4]x1 >= [-& -&]x1 = c(b(c(x1))) [0 0 ] [0 0 ] c(b(b(x1))) = [-& -&]x1 >= [-& -&]x1 = b(b(c(x1))) [0 0 ] [0 0 ] c(c(c(x1))) = [-& -&]x1 >= [-& -&]x1 = b(b(c(x1))) [8 12] [0 0] a(a(a(x1))) = [8 12]x1 >= [0 0]x1 = a(b(c(x1))) problem: strict: b(b(b(x1))) -> c(a(c(x1))) a(a(c(x1))) -> a(b(a(x1))) weak: c(b(b(x1))) -> b(b(c(x1))) c(c(c(x1))) -> b(b(c(x1))) Arctic Interpretation Processor: dimension: 1 interpretation: [c](x0) = 8x0, [b](x0) = 8x0, [a](x0) = 4x0 orientation: b(b(b(x1))) = 24x1 >= 20x1 = c(a(c(x1))) a(a(c(x1))) = 16x1 >= 16x1 = a(b(a(x1))) c(b(b(x1))) = 24x1 >= 24x1 = b(b(c(x1))) c(c(c(x1))) = 24x1 >= 24x1 = b(b(c(x1))) problem: strict: a(a(c(x1))) -> a(b(a(x1))) weak: c(b(b(x1))) -> b(b(c(x1))) c(c(c(x1))) -> b(b(c(x1))) Arctic Interpretation Processor: dimension: 1 interpretation: [c](x0) = 2x0, [b](x0) = x0, [a](x0) = x0 orientation: a(a(c(x1))) = 2x1 >= x1 = a(b(a(x1))) c(b(b(x1))) = 2x1 >= 2x1 = b(b(c(x1))) c(c(c(x1))) = 6x1 >= 2x1 = b(b(c(x1))) problem: strict: weak: c(b(b(x1))) -> b(b(c(x1))) Qed
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