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TRS Equational pair #487523140
details
property
value
status
complete
benchmark
AC16.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n184.star.cs.uiowa.edu
space
AProVE_AC_04
run statistics
property
value
solver
muterm 5.18
configuration
default
runtime (wallclock)
0.272294998169 seconds
cpu usage
0.27790341
max memory
3821568.0
stage attributes
key
value
output-size
3958
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x y) (THEORY (AC plus)) (RULES L(T(x)) -> L(x) L(plus(T(y),x)) -> plus(L(plus(x,y)),L(y)) T(T(x)) -> T(x) T(plus(T(y),x)) -> plus(T(plus(x,y)),T(y)) plus(T(plus(x,y)),x) -> T(plus(x,y)) plus(T(x),x) -> T(x) plus(x,0) -> x plus(x,x) -> x ) Problem 1: Reduction Order Processor: -> Rules: L(T(x)) -> L(x) L(plus(T(y),x)) -> plus(L(plus(x,y)),L(y)) T(T(x)) -> T(x) T(plus(T(y),x)) -> plus(T(plus(x,y)),T(y)) plus(T(plus(x,y)),x) -> T(plus(x,y)) plus(T(x),x) -> T(x) plus(x,0) -> x plus(x,x) -> x ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [L](X) = X + 1 [T](X) = 2.X + 2 [plus](X1,X2) = X1 + X2 + 1 [0] = 0 Problem 1: Reduction Order Processor: -> Rules: L(plus(T(y),x)) -> plus(L(plus(x,y)),L(y)) T(T(x)) -> T(x) T(plus(T(y),x)) -> plus(T(plus(x,y)),T(y)) plus(T(plus(x,y)),x) -> T(plus(x,y)) plus(T(x),x) -> T(x) plus(x,0) -> x plus(x,x) -> x ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [L](X) = 2.X + 2 [T](X) = 2.X + 2 [plus](X1,X2) = X1 + X2 [0] = 0 Problem 1: Reduction Order Processor: -> Rules: T(T(x)) -> T(x) T(plus(T(y),x)) -> plus(T(plus(x,y)),T(y)) plus(T(plus(x,y)),x) -> T(plus(x,y)) plus(T(x),x) -> T(x) plus(x,0) -> x plus(x,x) -> x ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [L](X) = 2.X [T](X) = 2.X + 2 [plus](X1,X2) = X1 + X2
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