details

property	value
status	complete
benchmark	test75.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n154.star.cs.uiowa.edu
space	Mixed_innermost

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	2.10814595222 seconds
cpu usage	4.553851137
max memory	3.17218816E8

stage attributes

key	value
output-size	9637
starexec-result	YES

output

/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 0 ms] (2) QDP (3) DependencyGraphProof [EQUIVALENT, 0 ms] (4) QDP (5) UsableRulesProof [EQUIVALENT, 0 ms] (6) QDP (7) QReductionProof [EQUIVALENT, 0 ms] (8) QDP (9) TransformationProof [EQUIVALENT, 0 ms] (10) QDP (11) Induction-Processor [SOUND, 6 ms] (12) AND (13) QDP (14) PisEmptyProof [EQUIVALENT, 0 ms] (15) YES (16) QTRS (17) QTRSRRRProof [EQUIVALENT, 5 ms] (18) QTRS (19) RisEmptyProof [EQUIVALENT, 0 ms] (20) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(0, 1, X) -> f(g(X, X), X, X) g(X, Y) -> X g(X, Y) -> Y The set Q consists of the following terms: f(0, 1, x0) g(x0, x1) ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: F(0, 1, X) -> F(g(X, X), X, X) F(0, 1, X) -> G(X, X) The TRS R consists of the following rules: f(0, 1, X) -> f(g(X, X), X, X) g(X, Y) -> X g(X, Y) -> Y The set Q consists of the following terms: f(0, 1, x0) g(x0, x1) We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (3) DependencyGraphProof (EQUIVALENT) The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 1 less node. ---------------------------------------- (4) Obligation: Q DP problem: The TRS P consists of the following rules: F(0, 1, X) -> F(g(X, X), X, X) The TRS R consists of the following rules: f(0, 1, X) -> f(g(X, X), X, X) g(X, Y) -> X g(X, Y) -> Y The set Q consists of the following terms: popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to TRS Innermost