details

property	value
status	complete
benchmark	janne_complex.t2_fixed.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n184.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	110.65171504 seconds
cpu usage	118.143896093
max memory	2.3474176E7

stage attributes

key	value
output-size	12212
starexec-result	MAYBE

output

/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f10#(x1, x2, x3, x4, x5, x6) -> f9#(x1, x2, x3, x4, x5, x6) f9#(I0, I1, I2, I3, I4, I5) -> f4#(rnd1, 1, 0, rnd4, 1, I5) [rnd4 = 1 /\ rnd1 = 1] f5#(I6, I7, I8, I9, I10, I11) -> f8#(I6, I7, I8, I9, I10, I11) [1 + I9 <= I6] f5#(I12, I13, I14, I15, I16, I17) -> f4#(2 + I12, I13, I14, -10 + I15, I16, I17) [I12 <= I15] f8#(I18, I19, I20, I21, I22, I23) -> f7#(I18, I19, I20, I24, I22, I23) [I24 = I24 /\ 6 <= I21] f8#(I25, I26, I27, I28, I29, I30) -> f7#(I25, I26, I27, 2 + I28, I29, I30) [I28 <= 5] f7#(I31, I32, I33, I34, I35, I36) -> f6#(I31, I32, I33, I34, I35, I36) [10 <= I34] f7#(I37, I38, I39, I40, I41, I42) -> f3#(1 + I37, I38, I39, I40, I41, I42) [1 + I40 <= 10] f6#(I43, I44, I45, I46, I47, I48) -> f3#(10 + I43, I44, I45, I46, I47, I48) [I46 <= 12] f6#(I49, I50, I51, I52, I53, I54) -> f3#(1 + I49, I50, I51, I52, I53, I54) [13 <= I52] f3#(I55, I56, I57, I58, I59, I60) -> f5#(I55, I56, I57, I58, I59, I60) f4#(I61, I62, I63, I64, I65, I66) -> f1#(I61, I62, I63, I64, I65, I66) f1#(I67, I68, I69, I70, I71, I72) -> f3#(I67, I68, I69, I70, I71, I72) [1 + I67 <= 30] R = f10(x1, x2, x3, x4, x5, x6) -> f9(x1, x2, x3, x4, x5, x6) f9(I0, I1, I2, I3, I4, I5) -> f4(rnd1, 1, 0, rnd4, 1, I5) [rnd4 = 1 /\ rnd1 = 1] f5(I6, I7, I8, I9, I10, I11) -> f8(I6, I7, I8, I9, I10, I11) [1 + I9 <= I6] f5(I12, I13, I14, I15, I16, I17) -> f4(2 + I12, I13, I14, -10 + I15, I16, I17) [I12 <= I15] f8(I18, I19, I20, I21, I22, I23) -> f7(I18, I19, I20, I24, I22, I23) [I24 = I24 /\ 6 <= I21] f8(I25, I26, I27, I28, I29, I30) -> f7(I25, I26, I27, 2 + I28, I29, I30) [I28 <= 5] f7(I31, I32, I33, I34, I35, I36) -> f6(I31, I32, I33, I34, I35, I36) [10 <= I34] f7(I37, I38, I39, I40, I41, I42) -> f3(1 + I37, I38, I39, I40, I41, I42) [1 + I40 <= 10] f6(I43, I44, I45, I46, I47, I48) -> f3(10 + I43, I44, I45, I46, I47, I48) [I46 <= 12] f6(I49, I50, I51, I52, I53, I54) -> f3(1 + I49, I50, I51, I52, I53, I54) [13 <= I52] f3(I55, I56, I57, I58, I59, I60) -> f5(I55, I56, I57, I58, I59, I60) f4(I61, I62, I63, I64, I65, I66) -> f1(I61, I62, I63, I64, I65, I66) f1(I67, I68, I69, I70, I71, I72) -> f3(I67, I68, I69, I70, I71, I72) [1 + I67 <= 30] f1(I73, I74, I75, I76, I77, I78) -> f2(I73, I74, rnd3, I76, I77, 1) [rnd3 = 1 /\ 30 <= I73] The dependency graph for this problem is: 0 -> 1 1 -> 11 2 -> 4, 5 3 -> 11 4 -> 6, 7 5 -> 7 6 -> 8, 9 7 -> 10 8 -> 10 9 -> 10 10 -> 2, 3 11 -> 12 12 -> 10 Where: 0) f10#(x1, x2, x3, x4, x5, x6) -> f9#(x1, x2, x3, x4, x5, x6) 1) f9#(I0, I1, I2, I3, I4, I5) -> f4#(rnd1, 1, 0, rnd4, 1, I5) [rnd4 = 1 /\ rnd1 = 1] 2) f5#(I6, I7, I8, I9, I10, I11) -> f8#(I6, I7, I8, I9, I10, I11) [1 + I9 <= I6] 3) f5#(I12, I13, I14, I15, I16, I17) -> f4#(2 + I12, I13, I14, -10 + I15, I16, I17) [I12 <= I15] 4) f8#(I18, I19, I20, I21, I22, I23) -> f7#(I18, I19, I20, I24, I22, I23) [I24 = I24 /\ 6 <= I21] 5) f8#(I25, I26, I27, I28, I29, I30) -> f7#(I25, I26, I27, 2 + I28, I29, I30) [I28 <= 5] 6) f7#(I31, I32, I33, I34, I35, I36) -> f6#(I31, I32, I33, I34, I35, I36) [10 <= I34] 7) f7#(I37, I38, I39, I40, I41, I42) -> f3#(1 + I37, I38, I39, I40, I41, I42) [1 + I40 <= 10] 8) f6#(I43, I44, I45, I46, I47, I48) -> f3#(10 + I43, I44, I45, I46, I47, I48) [I46 <= 12] 9) f6#(I49, I50, I51, I52, I53, I54) -> f3#(1 + I49, I50, I51, I52, I53, I54) [13 <= I52] 10) f3#(I55, I56, I57, I58, I59, I60) -> f5#(I55, I56, I57, I58, I59, I60) 11) f4#(I61, I62, I63, I64, I65, I66) -> f1#(I61, I62, I63, I64, I65, I66) 12) f1#(I67, I68, I69, I70, I71, I72) -> f3#(I67, I68, I69, I70, I71, I72) [1 + I67 <= 30] We have the following SCCs. { 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 } DP problem for innermost termination. P = f5#(I6, I7, I8, I9, I10, I11) -> f8#(I6, I7, I8, I9, I10, I11) [1 + I9 <= I6] f5#(I12, I13, I14, I15, I16, I17) -> f4#(2 + I12, I13, I14, -10 + I15, I16, I17) [I12 <= I15] f8#(I18, I19, I20, I21, I22, I23) -> f7#(I18, I19, I20, I24, I22, I23) [I24 = I24 /\ 6 <= I21] f8#(I25, I26, I27, I28, I29, I30) -> f7#(I25, I26, I27, 2 + I28, I29, I30) [I28 <= 5] f7#(I31, I32, I33, I34, I35, I36) -> f6#(I31, I32, I33, I34, I35, I36) [10 <= I34] f7#(I37, I38, I39, I40, I41, I42) -> f3#(1 + I37, I38, I39, I40, I41, I42) [1 + I40 <= 10] f6#(I43, I44, I45, I46, I47, I48) -> f3#(10 + I43, I44, I45, I46, I47, I48) [I46 <= 12] f6#(I49, I50, I51, I52, I53, I54) -> f3#(1 + I49, I50, I51, I52, I53, I54) [13 <= I52] f3#(I55, I56, I57, I58, I59, I60) -> f5#(I55, I56, I57, I58, I59, I60) f4#(I61, I62, I63, I64, I65, I66) -> f1#(I61, I62, I63, I64, I65, I66) f1#(I67, I68, I69, I70, I71, I72) -> f3#(I67, I68, I69, I70, I71, I72) [1 + I67 <= 30] R = f10(x1, x2, x3, x4, x5, x6) -> f9(x1, x2, x3, x4, x5, x6) f9(I0, I1, I2, I3, I4, I5) -> f4(rnd1, 1, 0, rnd4, 1, I5) [rnd4 = 1 /\ rnd1 = 1] f5(I6, I7, I8, I9, I10, I11) -> f8(I6, I7, I8, I9, I10, I11) [1 + I9 <= I6] f5(I12, I13, I14, I15, I16, I17) -> f4(2 + I12, I13, I14, -10 + I15, I16, I17) [I12 <= I15] f8(I18, I19, I20, I21, I22, I23) -> f7(I18, I19, I20, I24, I22, I23) [I24 = I24 /\ 6 <= I21] f8(I25, I26, I27, I28, I29, I30) -> f7(I25, I26, I27, 2 + I28, I29, I30) [I28 <= 5] f7(I31, I32, I33, I34, I35, I36) -> f6(I31, I32, I33, I34, I35, I36) [10 <= I34] f7(I37, I38, I39, I40, I41, I42) -> f3(1 + I37, I38, I39, I40, I41, I42) [1 + I40 <= 10] f6(I43, I44, I45, I46, I47, I48) -> f3(10 + I43, I44, I45, I46, I47, I48) [I46 <= 12] f6(I49, I50, I51, I52, I53, I54) -> f3(1 + I49, I50, I51, I52, I53, I54) [13 <= I52] f3(I55, I56, I57, I58, I59, I60) -> f5(I55, I56, I57, I58, I59, I60) f4(I61, I62, I63, I64, I65, I66) -> f1(I61, I62, I63, I64, I65, I66) f1(I67, I68, I69, I70, I71, I72) -> f3(I67, I68, I69, I70, I71, I72) [1 + I67 <= 30] f1(I73, I74, I75, I76, I77, I78) -> f2(I73, I74, rnd3, I76, I77, 1) [rnd3 = 1 /\ 30 <= I73] popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to Integer Transition Systems