details

property	value
status	complete
benchmark	neg-e-acqrel-fail.t2.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n143.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	5.60143899918 seconds
cpu usage	5.946695264
max memory	2.0451328E7

stage attributes

key	value
output-size	4253
starexec-result	MAYBE

output

/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f10#(x1, x2, x3, x4, x5, x6) -> f9#(x1, x2, x3, x4, x5, x6) f9#(I0, I1, I2, I3, I4, I5) -> f1#(0, 0, rnd3, I3, rnd5, I5) [rnd5 = rnd3 /\ rnd3 = rnd3] f2#(I6, I7, I8, I9, I10, I11) -> f7#(I6, I7, I8, I9, I10, I11) [1 <= I10] f2#(I12, I13, I14, I15, I16, I17) -> f3#(0, I13, I14, rnd4, I16, rnd6) [I16 <= 0 /\ y1 = 1 /\ rnd4 = rnd4 /\ rnd6 = rnd4] f4#(I18, I19, I20, I21, I22, I23) -> f1#(I18, 0, I24, I21, I25, I23) [I23 <= 0 /\ I26 = 1 /\ I24 = I24 /\ I25 = I24] f4#(I27, I28, I29, I30, I31, I32) -> f3#(I27, I28, I29, I30, I31, I32) [1 <= I32] f8#(I33, I34, I35, I36, I37, I38) -> f7#(I33, I34, I35, I36, I37, I38) f7#(I39, I40, I41, I42, I43, I44) -> f8#(I39, I40, I41, I42, I43, I44) f3#(I51, I52, I53, I54, I55, I56) -> f4#(I51, I52, I53, I54, I55, I56) f1#(I57, I58, I59, I60, I61, I62) -> f2#(I57, I58, I59, I60, I61, I62) R = f10(x1, x2, x3, x4, x5, x6) -> f9(x1, x2, x3, x4, x5, x6) f9(I0, I1, I2, I3, I4, I5) -> f1(0, 0, rnd3, I3, rnd5, I5) [rnd5 = rnd3 /\ rnd3 = rnd3] f2(I6, I7, I8, I9, I10, I11) -> f7(I6, I7, I8, I9, I10, I11) [1 <= I10] f2(I12, I13, I14, I15, I16, I17) -> f3(0, I13, I14, rnd4, I16, rnd6) [I16 <= 0 /\ y1 = 1 /\ rnd4 = rnd4 /\ rnd6 = rnd4] f4(I18, I19, I20, I21, I22, I23) -> f1(I18, 0, I24, I21, I25, I23) [I23 <= 0 /\ I26 = 1 /\ I24 = I24 /\ I25 = I24] f4(I27, I28, I29, I30, I31, I32) -> f3(I27, I28, I29, I30, I31, I32) [1 <= I32] f8(I33, I34, I35, I36, I37, I38) -> f7(I33, I34, I35, I36, I37, I38) f7(I39, I40, I41, I42, I43, I44) -> f8(I39, I40, I41, I42, I43, I44) f5(I45, I46, I47, I48, I49, I50) -> f6(I45, I46, I47, I48, I49, I50) f3(I51, I52, I53, I54, I55, I56) -> f4(I51, I52, I53, I54, I55, I56) f1(I57, I58, I59, I60, I61, I62) -> f2(I57, I58, I59, I60, I61, I62) The dependency graph for this problem is: 0 -> 1 1 -> 9 2 -> 7 3 -> 8 4 -> 9 5 -> 8 6 -> 7 7 -> 6 8 -> 4, 5 9 -> 2, 3 Where: 0) f10#(x1, x2, x3, x4, x5, x6) -> f9#(x1, x2, x3, x4, x5, x6) 1) f9#(I0, I1, I2, I3, I4, I5) -> f1#(0, 0, rnd3, I3, rnd5, I5) [rnd5 = rnd3 /\ rnd3 = rnd3] 2) f2#(I6, I7, I8, I9, I10, I11) -> f7#(I6, I7, I8, I9, I10, I11) [1 <= I10] 3) f2#(I12, I13, I14, I15, I16, I17) -> f3#(0, I13, I14, rnd4, I16, rnd6) [I16 <= 0 /\ y1 = 1 /\ rnd4 = rnd4 /\ rnd6 = rnd4] 4) f4#(I18, I19, I20, I21, I22, I23) -> f1#(I18, 0, I24, I21, I25, I23) [I23 <= 0 /\ I26 = 1 /\ I24 = I24 /\ I25 = I24] 5) f4#(I27, I28, I29, I30, I31, I32) -> f3#(I27, I28, I29, I30, I31, I32) [1 <= I32] 6) f8#(I33, I34, I35, I36, I37, I38) -> f7#(I33, I34, I35, I36, I37, I38) 7) f7#(I39, I40, I41, I42, I43, I44) -> f8#(I39, I40, I41, I42, I43, I44) 8) f3#(I51, I52, I53, I54, I55, I56) -> f4#(I51, I52, I53, I54, I55, I56) 9) f1#(I57, I58, I59, I60, I61, I62) -> f2#(I57, I58, I59, I60, I61, I62) We have the following SCCs. { 3, 4, 5, 8, 9 } { 6, 7 } DP problem for innermost termination. P = f8#(I33, I34, I35, I36, I37, I38) -> f7#(I33, I34, I35, I36, I37, I38) f7#(I39, I40, I41, I42, I43, I44) -> f8#(I39, I40, I41, I42, I43, I44) R = f10(x1, x2, x3, x4, x5, x6) -> f9(x1, x2, x3, x4, x5, x6) f9(I0, I1, I2, I3, I4, I5) -> f1(0, 0, rnd3, I3, rnd5, I5) [rnd5 = rnd3 /\ rnd3 = rnd3] f2(I6, I7, I8, I9, I10, I11) -> f7(I6, I7, I8, I9, I10, I11) [1 <= I10] f2(I12, I13, I14, I15, I16, I17) -> f3(0, I13, I14, rnd4, I16, rnd6) [I16 <= 0 /\ y1 = 1 /\ rnd4 = rnd4 /\ rnd6 = rnd4] f4(I18, I19, I20, I21, I22, I23) -> f1(I18, 0, I24, I21, I25, I23) [I23 <= 0 /\ I26 = 1 /\ I24 = I24 /\ I25 = I24] f4(I27, I28, I29, I30, I31, I32) -> f3(I27, I28, I29, I30, I31, I32) [1 <= I32] f8(I33, I34, I35, I36, I37, I38) -> f7(I33, I34, I35, I36, I37, I38) f7(I39, I40, I41, I42, I43, I44) -> f8(I39, I40, I41, I42, I43, I44) f5(I45, I46, I47, I48, I49, I50) -> f6(I45, I46, I47, I48, I49, I50) f3(I51, I52, I53, I54, I55, I56) -> f4(I51, I52, I53, I54, I55, I56) f1(I57, I58, I59, I60, I61, I62) -> f2(I57, I58, I59, I60, I61, I62) popout

output may be truncated. 'popout' for the full output.

job log

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actions

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