details

property	value
status	complete
benchmark	ppblocktermbug.t2.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n139.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	64.8296821117 seconds
cpu usage	69.302268044
max memory	3.975168E7

stage attributes

key	value
output-size	12934
starexec-result	MAYBE

output

/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f9#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) -> f8#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) f8#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9, I10) -> f3#(I0, 0, 1, 0, I4, rnd6, I6, rnd8, I8, I9, 0) [rnd6 = rnd6 /\ rnd8 = rnd8] f3#(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) -> f7#(rnd1, I12, 1, I14, I15, I16, I17, I18, I19, I20, 0) [rnd1 = rnd1 /\ 1 + I18 <= I16] f3#(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) -> f2#(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, 0) [I27 <= I29] f7#(I33, I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f4#(I33, 1, I35, I36, I37, I38, rnd7, I40, I41, I42, I43) [rnd7 = rnd7 /\ 1 <= I33] f7#(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) -> f2#(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) [I44 <= 0] f5#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) f2#(I77, I78, I79, I80, I81, I82, I83, I84, I85, I86, I87) -> f5#(I77, I78, I79, I80, I81, I82, I83, I84, I85, -1 + I86, I87) [1 <= I86] f4#(I88, I89, I90, I91, I92, I93, I94, I95, I96, I97, I98) -> f1#(I88, 0, I90, I91, 0, I93, I99, I95, I96, I97, I98) [I99 = I99 /\ 2 <= I94] f4#(I100, I101, I102, I103, I104, I105, I106, I107, I108, I109, I110) -> f3#(I100, 0, I102, I103, I104, I105, I106, 1 + I107, I108, I109, 1) [I106 <= 1] f1#(I111, I112, I113, I114, I115, I116, I117, I118, I119, I120, I121) -> f3#(I111, I112, I113, I114, I115, I116, I117, I118, 1 + I119, I120, I121) [2 <= I117] f1#(I122, I123, I124, I125, I126, I127, I128, I129, I130, I131, I132) -> f2#(I122, I123, I124, I125, I126, I127, I128, I129, I130, I131, I132) [I128 <= 1] R = f9(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) -> f8(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) f8(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9, I10) -> f3(I0, 0, 1, 0, I4, rnd6, I6, rnd8, I8, I9, 0) [rnd6 = rnd6 /\ rnd8 = rnd8] f3(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) -> f7(rnd1, I12, 1, I14, I15, I16, I17, I18, I19, I20, 0) [rnd1 = rnd1 /\ 1 + I18 <= I16] f3(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) -> f2(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, 0) [I27 <= I29] f7(I33, I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f4(I33, 1, I35, I36, I37, I38, rnd7, I40, I41, I42, I43) [rnd7 = rnd7 /\ 1 <= I33] f7(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) -> f2(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) [I44 <= 0] f2(I55, I56, I57, I58, I59, I60, I61, I62, I63, I64, I65) -> f6(I55, I56, I57, 1, I59, I60, I61, I62, 0, I64, I65) [I64 <= 0] f5(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) f2(I77, I78, I79, I80, I81, I82, I83, I84, I85, I86, I87) -> f5(I77, I78, I79, I80, I81, I82, I83, I84, I85, -1 + I86, I87) [1 <= I86] f4(I88, I89, I90, I91, I92, I93, I94, I95, I96, I97, I98) -> f1(I88, 0, I90, I91, 0, I93, I99, I95, I96, I97, I98) [I99 = I99 /\ 2 <= I94] f4(I100, I101, I102, I103, I104, I105, I106, I107, I108, I109, I110) -> f3(I100, 0, I102, I103, I104, I105, I106, 1 + I107, I108, I109, 1) [I106 <= 1] f1(I111, I112, I113, I114, I115, I116, I117, I118, I119, I120, I121) -> f3(I111, I112, I113, I114, I115, I116, I117, I118, 1 + I119, I120, I121) [2 <= I117] f1(I122, I123, I124, I125, I126, I127, I128, I129, I130, I131, I132) -> f2(I122, I123, I124, I125, I126, I127, I128, I129, I130, I131, I132) [I128 <= 1] The dependency graph for this problem is: 0 -> 1 1 -> 2, 3 2 -> 4, 5 3 -> 7 4 -> 8, 9 5 -> 7 6 -> 7 7 -> 6 8 -> 10, 11 9 -> 2, 3 10 -> 2, 3 11 -> 7 Where: 0) f9#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) -> f8#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) 1) f8#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9, I10) -> f3#(I0, 0, 1, 0, I4, rnd6, I6, rnd8, I8, I9, 0) [rnd6 = rnd6 /\ rnd8 = rnd8] 2) f3#(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) -> f7#(rnd1, I12, 1, I14, I15, I16, I17, I18, I19, I20, 0) [rnd1 = rnd1 /\ 1 + I18 <= I16] 3) f3#(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) -> f2#(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, 0) [I27 <= I29] 4) f7#(I33, I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f4#(I33, 1, I35, I36, I37, I38, rnd7, I40, I41, I42, I43) [rnd7 = rnd7 /\ 1 <= I33] 5) f7#(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) -> f2#(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) [I44 <= 0] 6) f5#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) 7) f2#(I77, I78, I79, I80, I81, I82, I83, I84, I85, I86, I87) -> f5#(I77, I78, I79, I80, I81, I82, I83, I84, I85, -1 + I86, I87) [1 <= I86] 8) f4#(I88, I89, I90, I91, I92, I93, I94, I95, I96, I97, I98) -> f1#(I88, 0, I90, I91, 0, I93, I99, I95, I96, I97, I98) [I99 = I99 /\ 2 <= I94] 9) f4#(I100, I101, I102, I103, I104, I105, I106, I107, I108, I109, I110) -> f3#(I100, 0, I102, I103, I104, I105, I106, 1 + I107, I108, I109, 1) [I106 <= 1] 10) f1#(I111, I112, I113, I114, I115, I116, I117, I118, I119, I120, I121) -> f3#(I111, I112, I113, I114, I115, I116, I117, I118, 1 + I119, I120, I121) [2 <= I117] 11) f1#(I122, I123, I124, I125, I126, I127, I128, I129, I130, I131, I132) -> f2#(I122, I123, I124, I125, I126, I127, I128, I129, I130, I131, I132) [I128 <= 1] We have the following SCCs. { 2, 4, 8, 9, 10 } { 6, 7 } DP problem for innermost termination. P = f5#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) f2#(I77, I78, I79, I80, I81, I82, I83, I84, I85, I86, I87) -> f5#(I77, I78, I79, I80, I81, I82, I83, I84, I85, -1 + I86, I87) [1 <= I86] R = f9(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) -> f8(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11) f8(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9, I10) -> f3(I0, 0, 1, 0, I4, rnd6, I6, rnd8, I8, I9, 0) [rnd6 = rnd6 /\ rnd8 = rnd8] f3(I11, I12, I13, I14, I15, I16, I17, I18, I19, I20, I21) -> f7(rnd1, I12, 1, I14, I15, I16, I17, I18, I19, I20, 0) [rnd1 = rnd1 /\ 1 + I18 <= I16] f3(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, I32) -> f2(I22, I23, I24, I25, I26, I27, I28, I29, I30, I31, 0) [I27 <= I29] f7(I33, I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f4(I33, 1, I35, I36, I37, I38, rnd7, I40, I41, I42, I43) [rnd7 = rnd7 /\ 1 <= I33] f7(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) -> f2(I44, I45, I46, I47, I48, I49, I50, I51, I52, I53, I54) [I44 <= 0] f2(I55, I56, I57, I58, I59, I60, I61, I62, I63, I64, I65) -> f6(I55, I56, I57, 1, I59, I60, I61, I62, 0, I64, I65) [I64 <= 0] f5(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) f2(I77, I78, I79, I80, I81, I82, I83, I84, I85, I86, I87) -> f5(I77, I78, I79, I80, I81, I82, I83, I84, I85, -1 + I86, I87) [1 <= I86] f4(I88, I89, I90, I91, I92, I93, I94, I95, I96, I97, I98) -> f1(I88, 0, I90, I91, 0, I93, I99, I95, I96, I97, I98) [I99 = I99 /\ 2 <= I94] f4(I100, I101, I102, I103, I104, I105, I106, I107, I108, I109, I110) -> f3(I100, 0, I102, I103, I104, I105, I106, 1 + I107, I108, I109, 1) [I106 <= 1] f1(I111, I112, I113, I114, I115, I116, I117, I118, I119, I120, I121) -> f3(I111, I112, I113, I114, I115, I116, I117, I118, 1 + I119, I120, I121) [2 <= I117] f1(I122, I123, I124, I125, I126, I127, I128, I129, I130, I131, I132) -> f2(I122, I123, I124, I125, I126, I127, I128, I129, I130, I131, I132) [I128 <= 1] We use the basic value criterion with the projection function NU: NU[f2#(z1,z2,z3,z4,z5,z6,z7,z8,z9,z10,z11)] = z10 NU[f5#(z1,z2,z3,z4,z5,z6,z7,z8,z9,z10,z11)] = z10 This gives the following inequalities: ==> I75 (>! \union =) I75 1 <= I86 ==> I86 >! -1 + I86 We remove all the strictly oriented dependency pairs. DP problem for innermost termination. P = f5#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2#(I66, I67, I68, I69, I70, I71, I72, I73, I74, I75, I76) popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to Integer Transition Systems