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Logic Programming pair #487529121
details
property
value
status
complete
benchmark
overlap.pl
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n137.star.cs.uiowa.edu
space
talp_apt
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.95829200745 seconds
cpu usage
4.441765525
max memory
3.58141952E8
stage attributes
key
value
output-size
14450
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.pl /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.pl # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Left Termination of the query pattern overlap(g,g) w.r.t. the given Prolog program could successfully be proven: (0) Prolog (1) PrologToPiTRSProof [SOUND, 0 ms] (2) PiTRS (3) DependencyPairsProof [EQUIVALENT, 6 ms] (4) PiDP (5) DependencyGraphProof [EQUIVALENT, 0 ms] (6) AND (7) PiDP (8) UsableRulesProof [EQUIVALENT, 0 ms] (9) PiDP (10) PiDPToQDPProof [EQUIVALENT, 0 ms] (11) QDP (12) QDPSizeChangeProof [EQUIVALENT, 0 ms] (13) YES (14) PiDP (15) UsableRulesProof [EQUIVALENT, 0 ms] (16) PiDP (17) PiDPToQDPProof [SOUND, 0 ms] (18) QDP (19) QDPSizeChangeProof [EQUIVALENT, 0 ms] (20) YES ---------------------------------------- (0) Obligation: Clauses: overlap(Xs, Ys) :- ','(member2(X, Xs), member1(X, Ys)). has_a_or_b(Xs) :- overlap(Xs, .(a, .(b, []))). member1(X, .(Y, Xs)) :- member1(X, Xs). member1(X, .(X, Xs)). member2(X, .(Y, Xs)) :- member2(X, Xs). member2(X, .(X, Xs)). Query: overlap(g,g) ---------------------------------------- (1) PrologToPiTRSProof (SOUND) We use the technique of [TOCL09]. With regard to the inferred argument filtering the predicates were used in the following modes: overlap_in_2: (b,b) member2_in_2: (f,b) member1_in_2: (b,b) Transforming Prolog into the following Term Rewriting System: Pi-finite rewrite system: The TRS R consists of the following rules: overlap_in_gg(Xs, Ys) -> U1_gg(Xs, Ys, member2_in_ag(X, Xs)) member2_in_ag(X, .(Y, Xs)) -> U5_ag(X, Y, Xs, member2_in_ag(X, Xs)) member2_in_ag(X, .(X, Xs)) -> member2_out_ag(X, .(X, Xs)) U5_ag(X, Y, Xs, member2_out_ag(X, Xs)) -> member2_out_ag(X, .(Y, Xs)) U1_gg(Xs, Ys, member2_out_ag(X, Xs)) -> U2_gg(Xs, Ys, member1_in_gg(X, Ys)) member1_in_gg(X, .(Y, Xs)) -> U4_gg(X, Y, Xs, member1_in_gg(X, Xs)) member1_in_gg(X, .(X, Xs)) -> member1_out_gg(X, .(X, Xs)) U4_gg(X, Y, Xs, member1_out_gg(X, Xs)) -> member1_out_gg(X, .(Y, Xs)) U2_gg(Xs, Ys, member1_out_gg(X, Ys)) -> overlap_out_gg(Xs, Ys) The argument filtering Pi contains the following mapping: overlap_in_gg(x1, x2) = overlap_in_gg(x1, x2) U1_gg(x1, x2, x3) = U1_gg(x2, x3) member2_in_ag(x1, x2) = member2_in_ag(x2) .(x1, x2) = .(x1, x2) U5_ag(x1, x2, x3, x4) = U5_ag(x4) member2_out_ag(x1, x2) = member2_out_ag(x1) U2_gg(x1, x2, x3) = U2_gg(x3) member1_in_gg(x1, x2) = member1_in_gg(x1, x2) U4_gg(x1, x2, x3, x4) = U4_gg(x4)
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